R-H Criteria (Solved Problem 3)

[@asparohan4473]

Little Doubt🤷🏻‍♂️- If P=2, Then Constant Term (or) Coefficient Of S^0 Of Char.eq i.e (P-2)=0 & That Violets The Necessary Condition(Hurwitz poly.)

[@xiaoyanwang4403]

Can’t wait to watch video regarding root locus!!! Really need them to pass my exams. Appreciate your work and effort sir.

[@PunmasterSTP]

How did your exams go?

[@mhz5749]

sadly, i think neso academy never make videos on root locus or even bode and nyquist diagrams

[@codetheandroid]

hello @nesoAcademy if you put p = 2 then coeff for const becomes 0 hence system will be unstable at 2

[@siddharthgautam7293]

H/w ans is option D

[@Jai_Jai_shri_Ram108]

Sir please complete the playlist of (****impDSA) AND C++

[@Jai_Jai_shri_Ram108]

It's heartily request to you

[@sazzal3016]

3rd Row (s^1): | (4k^2+6k-4)/(2k) | 0 4th Row (S^0): | 4 | --> so, 2k > 0 (2nd row) & (4k^2+6k-4)/(2k) > 0 (3rd row) these two criteria must be met to be Stable system -->from 2k>0, we can say k > 0 (must be met for the first element of row 3rd row to be positive) --> from (4k^2+6k-4)/(2k) > 0 , we get k < -2 and k > 0.5 (i.e. any one of these criteria will make the first element of 3rd row positive, which is necessary for the system to be stable. However, we also found out that k >0 for the 3rd row to comply with stable system criteria --> combining these k > 0 and k > 0.5, we can say 0.5

[@Kapoompahpeempahpoompah]

Thank you so much! Love it!

[@subodhsingh9287]

ans= D (verified by PYQs)

[@komalsah6010]

OPTION -D

[@morfisiuslizerro6400]

Option A is the answer- the value of k must be between the roots of the equation: 2k^2 + 3 k - 2 = 0

[@VikashKumar-oc9tz]

ans D

[@learningfoundation6601]

amazing content keep going

[@AmanKumar-sn7ej]

Option c (00.5 from 2k^2+3k-2 > 0

[@tarupratikshapandurang1536]

Ans is option "D"

[@ahsajibmatubber2179]

Option A : practically correct.

[@mdimran5071]

Uploaded more videos of control system

[@sanskarkumar6484]

thanks Sir🙏❤

[@utkarshtiwari1167]

HW problem answer: D

[@lucky-zt8nm]

HW problem: Ans 'D'

[@shanmugikilli5697]

How? Solution plz

[@ayushmishra3283]

@@shanmugikilli5697 S^1 row first element would be 4k^2+6k-4/2k and S^0 first elemet would be 4. so s^1 element wuold be positive hence 4k^2+6k-4>0 as k is always greater than 0 since s^2 element was 2k(quest) which is always pistive.Solve that equation you will get it (k-1/2)(k+2)=0

[@ee19gauravshrivas18]

D

[@adarshsoni8226]

HW problem ans : D

[@swantarya8433]

B

[@saivarun7786]

answer A?

[@miltonpassanha4504]

2K^2 + 3K - 2 = 0 will give K=1/2 or .5 and also K Must be greater than zero

[@pravingupta5940]

H/w = option (C)

[@kenamsahithi2453]

howw ???

[@UEISurajDebnath]

D

[@miltonpassanha4504]

B is the correct answer

[@chandansahu2941]

OPTION -D

[@imkushagra12]

D

[@sakshibharti3386]

How? ?

[@ahsajibmatubber2179]

please prove the math

[@arvindkumarsahani9968]

D

[@3bdoeid]

D

[@ritusinghal9792]

D

[@deelipmandal5322]

D

[@ece116pranaykumar4]

D