Block Diagram Reduction (Solved Example 1)

[@niibenedict7830]

Thanks for consistently imparting knowledge to us, I just have a little concern about the numerator of the transfer function, I think it should be G1G2G3 instead of G2G3H2

[@thevalkyriemen4442]

I think so too..

[@shiro5410]

yes I think so as well

[@deeptanuj6249]

yes @@shiro5410

[@joe_cheeramkuzhy]

yes g1g2g3 was correct, they went wrong there

[@mikeclaro3526]

Thank you for this lecture. I only have one question. Shouldn't it be G1G2G3 in the numerator of the final answer and not G2G3H2? Thank you sir!

[@yeruvasupradeepreddy9050]

Same doubt bro, thankyou for asking for me too

[@kalyanachakravarthi2736]

It is G1G2G3 because the element H2 has been cancelled out once we take the lcm, maybe it was a typing mistake.

[@Worldfamousvlog1996]

Same doubt. But may be typing mistake . I was solved this question by Masons gain formula

[@minalbasindha326]

Same question.. Also.

[@debdutmajumder9939]

Yes. It will be G1G2G3 in the numerator

[@dennismanarondong1058]

Thank you for the example problem sir. But I have concern about your final answer sir. That would be G1G2G3/1+G2G3H2+G1G2H1

[@Jabu_Mandlangisa]

thats true and that is what i got when i was doing it

[@damianyawuliga6968]

true

[@musharrafsaroof3036]

Yeah man

[@seifdahy1628]

this true of course

[@kartavyatripathi2720]

I think there is a mistake while calculating the transfer function in the last step. It should be G1G2G3/1+H2G2G3+H1G1G2..... Please look after my answer... If I am calculating wrong please respond🙏🏻

[@clementlg68]

Just done the calculus as well and ended up finding the same as yourself

[@mjollnirboy]

You are correct...G1G2G3 it is in the Numerator

[@aftab7814]

yes you are right, i got the same too and when I saw his answer I was confused lol

[@abhinabgogoi2000]

Yup...clearing the same doubt

[@piyushsoni4100]

Yes you are correct, I did a calculation mistake. It should be G1G2G3 in the numerator in the final answer.

[@prakashjaiswal6697]

It wasn't a mistake. It's just a way to see we all following his lessons properly! 😁😉 Surprisingly all most everyone noticed that mistake (it should be G1G2G3 in numerator)😅 Love your way of teaching sir❤😊

[@atharvashinde6398]

Thank you for this series

[@avigarg7859]

Sir at 6:32 the overall function should be (G1G2G3)/(1+G2G3H2+G1G2H1)

[@ibymamaril9645]

hi can I get a copy of your solution how did you get it?

[@ambadkarvinay7026]

you are right bro..........same here.

[@kevingozochaya9458]

G1 is missing right?

[@Wehn.]

How do you still have G2 and H2 in denominator when they got cancelled out?

[@dutdut11]

@@Wehn. same question

[@sahilumariya4873]

Thank you very much sir, I have an exam in 1 hour and this was a very good explanation.

[@cricketbestforme6168]

G1G2G3/(1+H2G2G3+H1G1G2 ) SAME HERE I THINK THIS IS THE RIGHT ANSWER, SIR

[@mayankupadhyay1206]

Same here

[@John-re3tr]

Same here

[@makinsights6818]

u r correct

[@tanayghodekar6454]

Same here

[@MrXyzElectronics]

**(G1 / (1 + G1 × H1))** Where: **G1 = (G1 × G2 × G3) / (1 + G2 × G3 × H2)** And **H1 = H1 / G3** ### Step 1: Substitute the value of G1 into the main expression. Substitute **G1 = (G1 × G2 × G3) / (1 + G2 × G3 × H2)** into the main expression: (G1 / (1 + G1 × H1)) = ((G1 × G2 × G3) / (1 + G2 × G3 × H2)) / (1 + ((G1 × G2 × G3) / (1 + G2 × G3 × H2)) × (H1 / G3)) ### Step 2: Simplify the second term in the denominator. Simplify **((G1 × G2 × G3) / (1 + G2 × G3 × H2)) × (H1 / G3)**. The **G3**'s cancel out: (G1 × G2 × H1) / (1 + G2 × G3 × H2) ### Step 3: Substitute this simplified term back into the main expression. Now the expression becomes: ((G1 × G2 × G3) / (1 + G2 × G3 × H2)) / (1 + (G1 × G2 × H1) / (1 + G2 × G3 × H2)) ### Step 4: Simplify the denominator. The denominator becomes: 1 + (G1 × G2 × H1) / (1 + G2 × G3 × H2) Write **1** as **(1 + G2 × G3 × H2) / (1 + G2 × G3 × H2)**: (1 + (G2 × G3 × H2) + (G1 × G2 × H1)) / (1 + G2 × G3 × H2) ### Step 5: Substitute this back into the main expression. The expression now becomes: ((G1 × G2 × G3) / (1 + G2 × G3 × H2)) / ((1 + (G2 × G3 × H2) + (G1 × G2 × H1)) / (1 + G2 × G3 × H2)) ### Step 6: Simplify the overall fraction. Since both the numerator and denominator have the common term **(1 + G2 × G3 × H2)**, they cancel out: (G1 × G2 × G3) / ((1 + G2 × G3 × H2) + (G1 × G2 × H1)) ### Final Answer: (G1 × G2 × G3) / ((1 + G2 × G3 × H2) + (G1 × G2 × H1))

[@swirlhydro]

thank you paul enriquez for the link! i hope you pass the pre-final exams!

[@learninginstudentscafe7284]

Very good style of explanation

[@farooq9861]

Final answer is G1G2G3/1+G2G3H2+G1G2H1✅✅

[@PunmasterSTP]

Block diagram reduction? More like "Astounding knowledge instruction!" Thanks again for making and sharing all of these wonderful videos.

[@karimma7moud-q6k]

same doubt

[@PunmasterSTP]

@@karimma7moud-q6k I’m just curious. What was your doubt specifically?

[@038_erasharma9]

Complete this playlist asap

[@atifsultan_mech]

An easier approach is to shift the last pick up point behind G3. And then first solve the negative feedback with H2 term and finally with H1 term. This way it is much easier to solve. Anyways the answer has G1G2G3 in numerator as everyone else pointed out.

[@lekanadenusi462]

That's Awesome!

[@JF59122]

Can I shift it to the left?

[@atifsultan_mech]

​@JF59122 yes you can! You'll then be multiplying the gain G3 with H2

[@abrokestudentsboringlife5806]

​@@atifsultan_mech Hi, will the final answer then be G1G2G3/1+G2H2+G1G2G3H1? Or did I mess up?

[@atifsultan_mech]

​@abrokestudentsboringlife5806 The numerator is correct. However, please double check the denominator

[@rk.engineering]

Thanks for this video

[@rasaqatandaalao1325]

Pls upload complete lecture. Thank and God bless u sir

[@learninginstudentscafe7284]

Thank you

[@vanessacatama711]

on point discussion. keep it up!

[@eggxecution]

Nice I finally get it

[@sanskarkumar8674]

thanks Sir❤

[@kenrampingplay]

Thank you so much!

[@miltonpassanha4504]

Correct answer is G1G2G3/ 1+ G2G3H2+G1G2H1

[@udoyshourov1880]

There is a problem in the last step answer should be (G1G2G33)/ (1+G2G3H2+G1G2H1)

[@peterwilliams8911]

Sir @2:28 why is it H1/G3 and not for a negative feedback system?

[@bsah82]

sir..pls post all video

[@sreerajguptays3531]

Sir, please update the playlist with further topics

[@EngrZakiVlogs]

Sir please upload electrical machine and electrical measurement and instrumentation

[@kumarharsh3685]

Sir please upload these videos quickly we desparately need this

[@PunmasterSTP]

I'm just curious; did he upload the videos quickly enough so that you and your classmates could use them before your exams?

[@savindahimesh4022]

Final Answer should be G1.G2.G3/ 1+G1.G2.H1

[@charleschristianbarnacha4571]

Finally.

[@felixleong61]

Same here.

[@uchiha_itachi_of_anime]

after calculating myself i come in the conclusion , on 6:16 you have little mistake you see the ans is G1G2G3/1+H2G2G3+H1G1G2 and your ans has h2 instead of g3 , and i am wrong pls replay me

[@bollamravinder4664]

Sir..pls complete the topics...

[@AniketAjagar]

I think it cannont be solved forever 😢

[@BGMI_003]

The final answer will be ( C/R = G1G2G3/1+G1G2H1)

[@AFRIN-ci8st]

Can u plzz.. Complete the full portion

[@rakshitakarnam4841]

Sir,please solve more and more examples on this topick🙏

[@madhavrathod1204]

Ya Its a typing mistake. Its = G1G2G3/1+G2G3H2+G1G2H1

[@markoriokot3425]

Yeah, Just like all the people have pointed it out, the final transfer function in this example is not correct. It should be G1G2G3/(1 + G2G3H2 + G1G2H1). The playlist is good but advanced topics are not included.

[@kollunageswarrao5179]

When u will be back🤧😭

[@Mystery-v5v]

There is an mistake in transfer function in this video,where in numerator in case of H2 there will be G1

[@rsingh6216]

When next video of data structures will come?

[@Sammy2000sv]

sir when will the further lecture come.........and is there any time period for further videos as your lecture make easy to understand control engg

[@chandupala7164]

Sir please check the answer

[@anuzravat]

*Last m it should be G1G2G3 instead of G2G3H2*

[@VibudaJayathilake]

Sir, how many videos are there for the full course?

[@ouukun]

Why don't you actually show the math in solving or combing the blocks. That would make this video much more helpful

[@unclejordi]

its not just him all the other channels on control system don't show the work its so annoying I had to waste so much time trying to understand how to do it dumb channels I swear

[@oreo3850]

@@unclejordi they do it on purpose to make you train on solving the right answer although here the professor made a small mistake in the final result .

[@vseelix957]

i can not figure out how to simplify that fraction it is way to complicated

[@ankit_yadav11]

numerator should be g1g2g3 not any h2 in nuemertor , its a simple mistake in ur solution .

[@sravankumarmarri4902]

Numerator value is wrong

[@allhindisongs9606]

last calculation is wrong please correct

[@mosesp7842]

🔥👍

[@5minupdates]

what happnend to your voice

[@DeepakKumar-lb5ku]

But I think Final ans is Wrong

[@mechanicalkiller1061]

31 December 2022 There is G1 missing in the final answer. Thank you

[@muhammadiqbalbinazizi2384]

ok

[@Lifelong1139]

In negetive feedback G/1-GH y G/1+GH???

[@PunmasterSTP]

I'm pretty sure the formula for the transfer function of a closed loop with unity negative feedback is G/(1+GH), and that for a closed loop with unity positive feedback is G/(1-GH). He discussed these formulas a fair amount in earlier videos.

[@dhruvgarg2003]

The numerator should be g1g2g3 , be careful while making video, as your single mistake wastes out lot of time

[@anujthakur614]

Answer is incorrect bruh "-"

[@ningdi_mac]

the answer is wrong

[@broma7298]

mali mani sir

[@sanskarkumar6484]

thanks Sir🙏❤

[@rajsekharreddy3142]

thank you sir