Conditional Operator in C

[@ProgrammingwithArijit]

Ans will be 65. Explanation: lets break the problem into part (1) At first the condition is sizeof(var) if this condition is evaluated to be true then (var2>23 ? ((var==75) ? 'A' : 0) : 0) will be returned if false then 0 will be returned As we know sizeof() is an unary operator which returns how many byte a datatype can hold as var is an variable of integer data type , sizeof(var) will either return 2 or 4 as machine to machine int vary . We know every number except 0 is evaluated to be true. So (var2>23 ? ((var==75) ? 'A' : 0) : 0) it will returned (2)next the condition is (var2>23) if this condition is evaluated to be true then ((var==75) ? 'A' : 0) will be returned if false then 0 will be returned as we know 56>23 is true then ((var==75) ? 'A' : 0) will be returned. (3)the condition is (var==75) if this condition is evaluated to be true then 'A' will be returned if false then 0 will be returned As 75==75 then 'A' will be returned and stored into num variable As c support auto type casting so int can store char. In the final printf function we use the placeholder %d and it print integer value . According to Ascii integer value of 'A' is 65 So the output will be 65.

[@daytrade1013]

Thank you

[@harshmk1052]

Thanks a lot :)

[@mehadihasansanto538]

Why don't you think that ((var==75)? 'A' : 0) will be evaluated first? [As we know that bracket has the highest precedence than any other operator in C.]

[@ayushvats1808]

@@mehadihasansanto538 xactly this is my doubt and i think bracket will only be evaluated first

[@mehadihasansanto538]

@@ayushvats1808 Yeah, Brother. I also think so. Moreover, the associativity of conditional operator(? :) works from right to left. That's why I think ((var == 75)? 'A' : 0) will be evaluated first.

[@102ayushkumar3]

Answer -> 65 Solution -> num = sizeof(var) ? (var2 > 23 ? ((var == 75) ? 'A' : 0) : 0) : 0; as we know, var==75 is True, therefore, (var == 75) ? 'A' : 0 will be equal to 'A'. Then we will replace the equation with 'A' in the main equation. num = sizeof(var) ? (var2 > 23 ? 'A' : 0) : 0; as we know, var2 == 56, hence greater than 23, therefore, var2 > 23 ? 'A' : 0 will be equal to 'A'. Then we will replace the equation with 'A' in the main equation. num = sizeof(var) ? 'A' : 0; as we know, as condition is True if the result of expression is any number except 0, sizeof(var) == 4, as its an integer data type. sizeof(var) is a True statement, therefore, sizeof(var) ? 'A' : 0 will be equal to 'A'. This implies num = 'A'; In the printf statement, the format specifier of num is %d, so the ASCII value of the character will be printed. ASCII value of 'A' = 65.

[@acoinhastwosides5239]

You make it understandable. You remove my confusion to explain it line by line. Thax

[@pranaylambat9743]

O/p is 65 ... because all three condition are true...sizeof(var) Shows the size of int (which is other than 0 ....and then after all condition are executed it will return A and the decimal of A is 65 .. according to ASCII TABLE

[@Gautamsingh-dy4cp]

But here parenthesis is given first evaluate parenthesis then applied conditional ..

[@saiyadav5014]

By evaluating with the parentheses the answer will be A. But in what manner computer will execute.?

[@kajolnimesh483]

@@saiyadav5014 Answer should A for sure as all the conditions are true, but compiler should execute A as a integer value as it is assigned to num variable that is integer variable.

[@sairakeshdurga600]

tq bro

[@udaykumar-es2el]

@@Gautamsingh-dy4cp but as for associvity rule it caan be done from left to right

[@randomthief7838]

Interesting lectures and also they are making to think for every homework questions.

[@millenmarbun24]

it will be wayyy better if you can explain the homework problems @nesoacademy sometimes I can't fully comprehend the answers

[@creative_editzs1862]

yes

[@sarthak_jain_51515]

Yes

[@brocklesnarufcchamp1]

Yeah, that would be really nice :(

[@AK--vc9wd]

65

[@kanthurijaswanthroyal5685]

@@AK--vc9wd I to get the same answer

[@wajahatriazmirza]

The answer is 65 First we will solve the inner brackets. According to that our condition is true so it will store the corresponding value of A according to ASCII i.e. 65 (because we are dealing with integer datatype). Then we will work our way out solving the outer brackets one by one. Hence the final answer is 65.

[@ahmedsedeek2814]

okay guys , here is the point .. if we considered it as an if statement , it'll be as following ; ) int var = 75 , var2 = 65; int num ; if(sizeof(var)) { if(var2 > 23) { if(var == 75) { num = 'A'; } } printf("%d" , num); } else return 0; the output is gonna be 65 , and this is according to ASCII table , as 'A' is = 65 ..

[@khalilrin-ju3nm]

thank you very much for explanation Mr Sedeek. If you do not mind i will ask you questions in future too

[@nbk330]

by looking at this equation now i understood the last stage of the problem clearly

[@ekanshkhanulia4078]

Please make your own videos,no gyan choding here

[@Gaurav-zh4pm]

else statements biro ?

[@pavanroyal8183]

Var 2 is 56 .how u right 65?

[@justindenison7029]

Output will be the ASCI code of 'A' =65; Thank you for your efforts, I like your explanation so much ❤

[@sowmithb4673]

thanks bro

[@soumi6720]

hands down this is the best channel . pls continue blessing us with valuable information.

[@satishsgm0157]

First rule to be followed while solving these type of conditions is: First of all we need to divide given expression into three parts i.e L|M|R And then start evaluate each and expression. Al last num variable initialised by A which is equivalent of 65.

[@rsingh6216]

This question is like 10 questions in one question. Neso team is great.

[@gautam1801]

Thanks for teaching me something in 5 minutes that my teacher took two 50 minutes classes for! 😃😃

[@kunalkhallar9699]

I think that's the main reason, why does our education system lag behind.

[@sumit4789]

true uncle@@kunalkhallar9699

[@bengalisareeshubstore3633]

Result is 65, start to solve from the inner bracket to the outer bracket, fixed inputs and take care of format specifier used during output, it will convert the result A into ASCII decimal 65 (%d is used for output)

[@98_shubhamr.sharma78]

Sir please solve homework problems also so that we can give it a try and if we are not able to solve it then we can refer to your explanation that would really really be helpful for beginners like me and all would really appreciate that effort of yours!!!! 🙏🙏🙏🙏

[@jayap8355]

O/p - ASCII Value of A= 65 Explained it perfectly man!!!!

[@shashankpandey6428]

Thanks a lot for videos sir ❣️. It's really helpful.

[@APstudent-y6s]

5:22 o/p is 65 thanks a bunch to the tutor n nesoAcademy ❤🙏

[@AYUSHSINGH-pv3pl]

#solution #include int main() { int var=75,var2=56,num; num=sizeof(var)?(var>23? ((var==75)?'A':0):0):0; printf(" the num is :%d",num); return 0; } output=65

[@helloHima790]

65 since sizeof var is 4or 8 according to processor which is True in boolean form and ascii value of A is 65 as we need to print in integer the value.

[@aniketnandi7478]

*/Output will be*/ 65 as per the expression, the result will be 'A' and it will be stored in num. But, num is int type data So, 'A' will be converted to its corresponding ASCII value which is 65.

[@Tejaswini01212]

Ans of H.W:It will print 65 that means the o/p of code is 'A' 65 is a ASCII value of capital 'A'.

[@sumanroy4615]

Ans will be 65 because the return value of 'num' is equal to 'A' according to ASCII table the value of A is 65.

[@otetumooluwaseun3948]

All other inner conditional expressions will be treated first. They return true. Then, the main operand, sizeof, returns true which implies 'A' will be returned. Since %d specifier was used, the printf will print the decimal value of character A, which is 65.

[@pramodinireddy1553]

Your classes are amazing sir , the way you explain with examples makes us more easier to understand the topics .

[@davidebenedettivalentini1812]

Easy explanation of last exercise: Remember that Expression1 ? Expression 2 : Expression 3 means: if Expression1 is True return Expression 2, else return Expression 3 so rephrasing the exercise we get: if (sizeof(var) is True return (if (var2 > 23) is True return ( if var == 75 return 'A' else return 0) else return 0) else return 0. Now just remember var is int and sizeof(int) returns 4 (which C reads as True) and ascii code of 'A' is 65 (i read it from other answers)

[@harshantbaraiya4712]

int var = 75; declares and initializes an integer variable var with the value 75. int var2 = 56; declares and initializes another integer variable var2 with the value 56. int num; declares an integer variable num without initializing it. Now, let's analyze the following line: num = sizeof(var) ? (var2 > 23 ? ((var == 75) ? 'A' : 0) : 0) : 0; This line uses nested conditional operators to assign a value to num based on several conditions: sizeof(var) calculates the size of the var variable, which is 4 bytes (assuming a typical 32-bit system). var2 > 23 checks if var2 is greater than 23, which is true because var2 is 56. (var == 75) ? 'A' : 0 checks if var is equal to 75. If it is, it assigns the character 'A' to num; otherwise, it assigns 0. So, the value of num will be 'A' because both sizeof(var) and var2 > 23 are true, and var is indeed equal to 75. Finally, the code prints the value of num using printf, which will output 'A' as a character (ASCII value of 'A' is 65). Therefore, the output of this code will be: A

[@tufanchakraborty5925]

65 Tip: use different bracket such as {}()

[@cirobermudez]

The output of the programa is A, because as sizeof(var) is diferent to 0 it enters to the first true statement, then it checks if var2 > 23, that is true, so finally checks it var == 75, again this is true so num equal to A

[@cirobermudez]

Lakshman Patel, thanks

[@ankurdutta5641]

@@lakshmanpatelofficial but why is 65 ?

[@SerajAlhorany]

@@ankurdutta5641 A = 65 according to ASCll

[@HDP76]

Out put will be 65 Since program execution begins from main function Declared variable var and assigned 75 to it Declared another variable var2 and assigned 56 to it Declared num integer type And given condition sizeof is unary operator since given sizeof(int) it returns 2 or 4 bytes depends on the compiler machine.How many bytes int will occupy it returns We know that if the condition is false it returns 0 and other than 0 returns 1 so now our condition is true it checks other condition of that true it checks other condition finally it returns A and num is assigned with A and it will be printed since the value of A according to ASCII in c is 65

[@ashishtayade047]

Thank you sir very nice gide & very nice best information conditional operator teaching video.👍

[@abhijit2231]

Output will be ASCII value of 'A' ie. 65

[@reginahshikanda6478]

Answer is 65 , thank you so much for this lectures

[@mislead1070]

The ans is 65 i.e. Numerical equivalent of the letter A. Explaination: The first condition/expression will return the size of var which is ofcourse more than 0, and as we all know, any value other than 0 is said to be true, so hence, the next expression will get terminated, which is again true... Bec var2 i.e. 56 > 23, thus the next expression will get terminated which i again true as we can see the value of var is 75, So thus, being true it will again terminate the true statement, But this time, there is no condition and its just a letter 'A', So as it being the last one of the conditions, the 'A' will get stored in num And as we know, ("%d") prints numerical values, so even if we store alphabetical values, it will convert the alphabetical value to its Numerical equivalent according to the ASCII Table and thus we will be getting the output as 'A' i.e. 65.

[@fahimarian2264]

Output will be : 65

[@aldaiansaklain]

Really awesome classes.

[@sachinkumbar3789]

It will print output as a 65 which is ASCII equivalent of 'A'

[@deepeshsunuwar1086]

all the three boolean returns true value so the value of num is "A" then the ASCII value of A is printed. so the final answer will be 65...........

[@sdk28]

Steps occured: 1. num = sizeof(var) ? (var > 23 ? ((var == 75) ? 'A' : 0) : 0) : 0; 2. num = sizeof(var) ? (var > 23 ? ('A') : 0) : 0; 3. num = sizeof(var) ? (('A')) : 0; 4. num = (('A')); Thus, num = 65 (when expressed in integer format)

[@ssenapati3328]

Pls tell the ans with ur explain @neso academy.. All doute are clear

[@adityajayswal1303]

65 or wot blissed lectures.....

[@Kim_jong_un69]

Will print 65 because 65 is the ASCII value of A if you use print("%c", num); instead of %d you will get A.

[@AsteriskYoutube]

Sir I’m studying only 10th standard but learning c from u thanks a lot sir and I got the answer for ur homework problem as 0 if wrong plz explain by replying to me

[@ravindra_sings_]

ans is 65

[@ravindra_sings_]

Ans will be 65. Explanation: lets break the problem into part (1) At first the condition is sizeof(var) if this condition is evaluated to be true then (var2>23 ? ((var==75) ? 'A' : 0) : 0) will be returned if false then 0 will be returned As we know sizeof() is an unary operator which returns how many byte a datatype can hold as var is an variable of integer data type , sizeof(var) will either return 2 or 4 as machine to machine int vary . We know every number except 0 is evaluated to be true. So (var2>23 ? ((var==75) ? 'A' : 0) : 0) it will returned (2)next the condition is (var2>23) if this condition is evaluated to be true then ((var==75) ? 'A' : 0) will be returned if false then 0 will be returned as we know 56>23 is true then ((var==75) ? 'A' : 0) will be returned. (3)the condition is (var==75) if this condition is evaluated to be true then 'A' will be returned if false then 0 will be returned As 75==75 then 'A' will be returned and stored into num variable As c support auto type casting so int can store char. In the final printf function we use the placeholder %d and it print integer value . According to Ascii integer value of 'A' is 65 So the output will be 65.Ans will be 65.

[@Xero75]

Great job kn explaining this! Thank you 😊 soo much

[@vittorio9763]

Output is 65, the decimal value of A

[@NMAJJINEERAJA]

ASCII code of 'A' will be the answer and that is 65

[@AbhinavKumar-qv7to]

65 ans because 'A' will be stored in num and due to %d it will be printed in ascii encoding equivalent 65.

[@akritibhan5858]

questions are just amazing..

[@brotherinterest6912]

so as i think that we have break it inside the bracket (var==75)?'A':0 then the answer is A because 75 is equal to 75. then, (var2>23?'A':0) then the answer will be A because 56 is greater than 23. then, we have sizeof(var)?'A':0; then the ascii A will be implemented that is 65

[@Sekhar_Home]

Thnx . U have given me a best lecture

[@mechguy0404]

the answer will be 65, the ASCII value of 'A'. As each of the three statements is true so expression 2 of each statement will be the outcome.

[@andistheinforitbutso7513]

Good morning 🙏 🌄

[@venkatesh3439]

Var==75 true A Var2>23 true A Sizeof(var) 4 non zero true A A is character we are using %d A ASCII value 65

[@manalkhazraj]

But how could the size of var be A?

[@balaagisp8490]

Ans is A because all 3 statement is true and if true the ans is A. But in printf it's %d which is integer and value of A is 65 in decimal so Final ans = 65

[@raiderpsk9690]

'A' is implicitly convert to int to become 65

[@ahmedmomtaz8696]

The answer 65 From inside out ((Var==75)?’A’:0 True. ‘A’. Then Var2>23?’A’:0. True. ‘A’ then Sizeof(var) ?’A’:0. True. ‘A’ Nume=‘A’ Nume=65

[@Dwarika_Sahu]

Thank you so much for this information

[@Rest_leave]

Whole expression is true that's by it has to return 65(at the place of A because c supports auto casting).

[@unaib7676]

65 because all conditions are true hence variable contain A and in decimal it will be 65

[@md.hasanmahmud416]

//We can think just like that if (sizeof(var)) { // 4 = true so go inside if(var2>23) { // 56>23=true so go inside if (var==75) { //var=var= true so go inside num='A'; // Final 'A' will assign in num else num=0; } else num=0; } else num=0; }

[@VijayKumar-tp9ux]

Nice steps bro👏

[@waterford7736]

Excellent👍

[@nexrainlyrical7876]

answer --> 51 explanation a=7; a^=5--> a=a^5--> a=2 printf("%d",a+=3)--> a+=3-->a=a+3--->a=5; printf("%d",printf(printf("%d",a+=3));------->51 ans only one character is there so 1 will be printed after 5..

[@balaagisp8490]

Ans A ASCII value of A is 65

[@duconsao3768]

what is the definition of tenary operator 3:28

[@sajooj7948]

can you determine the size of on your own without using the sizeof() operator? is it like a rule where int is always 4? And do we start solving the expression from the parenthese on the inside or outside first?

[@randomthief7838]

65 stand for character A All the conditions are true.

[@goutamvohra3442]

Ans is A but the return value is in the form of int datatype then it will transform into ASCII format return the value of A is 65 So the output is 65

[@sanyagandhi6576]

size of var is something other than 0 therefore, the condition is going to be true and A will be printed.

[@gauravvaidya1868]

There is %d which is decimal placeholder therefore it's ASCII value will be printed which is 65

[@nagasubramanian875]

Let me make it easier Expression is: Sizeof(var)?(var2>23?((var==75)'A':0):0):0 Now let's separate into 3 segments 1st (var==75)?'A':0 2nd (var2>23)?'A':0 3rd sizeof(var)?'A':0 Ans for 1: 75==75 so A is returned Ans for 2:. 2>23 so A is returned Ans for 3: A A is output and the ASCII value of A is 65

[@happy_girls]

👍👍👍🥰

[@rsingh6216]

I solved in first attempt , before this playlist ,i used to write stdio.h to studio.h

[@agamgill9563]

Numeric value of a return 65

[@sirnoxy2534]

Hurray!! Got the answer in just one go! BTW ans is 65.

[@AbbaJi-gm4vc]

Sir please give the solution video also so that we can compare our result

[@gauravjoshi4865]

65 ASCII code of "A"

[@ritiksaxenaofficial]

Output is 65...ascii of A

[@anandkumar-bd2ru]

65. // Ascii value of 'A'

[@porankirajkumar4709]

As the variable num is of data type integer how can it take of char 'A' as its value and print 65 in integer

[@anjani_tiwari]

int var = 75; int var2 = 56; int num; num = sizeof(var) ? (var2 > 23 ? ((var == 75) ? 'A' : 0) : 0) : 0; num = sizeof(var) ? 'A' : 0; num = sizeof(var) ? 'A' : 0; num = 65

[@JackVaileon]

I wonder if we can solve not from inner bracket but from the outer bracket, in this HW, both conditions are the same.

[@chinua2518]

answer is A, since all conditions happen to be true in all tested case.

[@xiaoshan9722]

the num = A ，but the output should be decimal number, then it convert to its binary representation 65

[@Gautamsingh-dy4cp]

Sir firstly applied parenthesis operation after that apply ternary operator..first offl all remove parenthesis then evaluate ..it true or not

[@hikmathasanov]

65 will be printed, since it is the decimal value of character A.

[@saeedakther7023]

Please explain again condition operation

[@the_mitwa]

Which ternary operator gets evaluated first?

[@vishalyadav067]

Output is 'A', how A become 65 ,pls anyone explain me.....???ohhh i gotted because be are storing value of char data type in int data type as a answer.....if we are using char num .....than answer is A .....👍👍🙏 Char Value of A to Z in int value A=65 B=66 C=67 D=68 So on...

[@AbdElrahmanAmirMohamed]

answer = 65 .... this is the decimal number parallel to "A" in ascii table.

[@venkat230]

Single quotations are responsible for printing ASCII value of A

[@mobeenshaik4219]

O/p will be 2 bcz sizeof doesn't evaluate expression

[@karanneelkanth8318]

Output will be ASCII VALUE OF A

[@heyrishabh13]

ASCII value of 'A' may be the answer.

[@Rahulsingh-mq2ny]

65

[@rajdeepray4009]

1st: sizeof (var)? (var2>23 ? ((var==75)? 'A' : 0) : 0) : 0 ; is evaluated and here sizeof(var) is either 2 or 4 (depends on machine to machine), not zero. and go for next expression: (var2>23 ? ((var==75)? 'A' : 0) : 0) 2nd: (var2>23 ? ((var==75)? 'A' : 0) : 0) is evaluated and here var2>23 this also true and to for next expression: (var==75)? 'A' : 0) 3rd: (var==75) ? 'A' : 0 is evaluated and here var==75 is true, so 'A' go forward.Then 'A' is assigned with num and then print 'A' in integer form: 65 (ASCII)

[@neelabauri9503]

do we have to memorise the ascii table values?

[@selvalakshmis.v4232]

65. Thank you, Sir

[@DarkyS73]

thank you so much sir

[@jagath123-m2r]

Both conditions are satisfied and print A value or A

[@recursiveminds]

output is 65 because 65 is acii value of A

[@vinaykumarreddy9956]

using return in ternary operator is allowed?

[@deekshdeekshitha6744]

Output of assignment is 65

[@manuvenu28]

It's the ascii value of A

[@ritikshrivastava9442]

Sir, I am unable to understand that last problem but I know how to use if else or nested as well so I break down that problem into if else #include int main() { int a=75; int b=56; int num; if(sizeof(a)) { if(b>23) { if(a ==75) { num = 'A'; } } printf("%d",num); } return 0; } And I have questions as we need to learn the ASCI table ? For i.e if we go for an interview the question arrive in which ASCI table is used in output so in that situation what we do? So pls tell should we learn that or these type of questions is not being asked in interview

[@rishisingh7237]

I also have same doubt