IPv6 address prefix and subnetting explained | ccna 200-301 |

[@softwarephil1709]

Since the last 64 bits are the unit number, it seems like the maximum prefix length would be 64. Can the prefix extend into the unit field?

[@networkingwithh4716]

you mean for example /126?

[@AL-bf8ys]

In the last example, how do you know that the 53th bit is in the 4th block (blue one)?

[@somewhereovertherainbow9550]

Okay I will try to explain in this chat. we know till twelfth nibble but not 13.25 (which is 53/4=13.25). so first convert the thirteenth and fourteenth nibble to binary (since it lies somewhere this range). i.e. 01010110 (8 bits of 2 nibbles) that means each bit is 0.25. now when you multiply 0.25 X 5=1.25. (it is fifth-bit position) Since you already know 12th, now when we add12+1.25=13.25. which is why it lies there. But I think you don't have to worry about this. since you know it lies somewhere after the 13th so just put zeros after.

[@bilalwardak1999]

for the last question how why didnt you end on a double colon (::)???

[@networkingwithh4716]

double colon is only used if you have consecutive zeros like 0000:0000:0001 = ::1.. i hope i cleared your doubt. let me know

[@bilalwardak1999]

@@networkingwithh4716 you wrote the last prefix as 2001:1234:abcd:5000:0:0:0:0/53 Where do those zeros come from? Because every other time you changed the host portion to zeros you used ::

[@networkingwithh4716]

consecutive zeros can also be represented as :: once in the address

[@ahmed12358]

please what app you are using to edit the video (for writing ...) thanks

[@networkingwithh4716]

Doodly

[@Jonathan-jd7hd]

So once you find the 53rd bit in the block, since it is not hexadecimal and its already in decimal format, you just leave the 5 and turn the rest to 0?

[@andrewjcalhoun7865]

Im still on the hunt trying to make sense of this too, comrade lol.

[@sreesweraam]

First 3 octets make 48. So 5 more to come to 53. So go from left to right in Binary "0101 0110 0111 1000" for 5 places and you end up with "0101 0" which will be 5 in value I think. I could be wrong!

[@pedrohartman5973]

kzbin.info/www/bejne/kH_YiayFjcaYa7c

[@iss9958]

you took your time to edit that hand, probably took the longest time ever

[@sweetliliane]

Cnfusing