Newton's Second Law

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The Physics Classroom

The Physics Classroom

Күн бұрын

Пікірлер: 12
@pickleshayley
@pickleshayley Жыл бұрын
The teaching is so good
@GuerrasLaws
@GuerrasLaws 4 жыл бұрын
Without applying Energy from within you, one couldn’t push or pull on an object(s) regardless of how much Force you apply. Note: Force does not physically exist like an object with mass. Force is just an expression like one would use the word, “Love” to express one’s feelings.
@PhysicsclassroomVideos
@PhysicsclassroomVideos 4 жыл бұрын
It is true that the exertion of a force upon another object is often accompanied by energy changes within us. But a force is a push or pull that is exerted upon another object as a result of interacting /touching it. If you've ever been shoved, hit, bumped into, pulled, collided with, you've experienced a force. And I'm sure that you would deny its existence. And if you are currently sitting upon another object, you're then you are exerting a force upon it and it upon you (with little to no energy exertion). You can learn about the Newtonian definition of force in our video What is a Force?
@ciennamonroll
@ciennamonroll 3 жыл бұрын
tbh tis the best website to learn physics
@PhysicsclassroomVideos
@PhysicsclassroomVideos 3 жыл бұрын
That's so good to hear. Thanks.
@mathapelomabunda5698
@mathapelomabunda5698 2 жыл бұрын
This helped so much thru my grade 10 and 11 year . Thank you
@stacy9841
@stacy9841 4 жыл бұрын
thank u!! so glad i found this account
@PhysicsclassroomVideos
@PhysicsclassroomVideos 4 жыл бұрын
I'm happy you're finding it helpful.
@saywhatki
@saywhatki 4 жыл бұрын
So helpful! Thank you!
@PhysicsclassroomVideos
@PhysicsclassroomVideos 4 жыл бұрын
Glad it helped. Come back again when you need more help.
@SerenaMy6555
@SerenaMy6555 4 ай бұрын
On 9:29 how did you determine the F net?
@NM-zb6pd
@NM-zb6pd 2 жыл бұрын
Acceleration is directly proportional to net Force - How can this result be achieved or established independently by measuring F & a before even F=ma & 1 Newton is defined? If we observe that X increases with increase of Y then they could also be in a relation Y = (K * X cube). It need not be Y = K * X. We have to measure Y & X independently to establish Y is directly proportional to X i.e Y = K * X.
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