Nice Algebra Math Simplification | Algebra | Find the Value of X | Olympiad

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Elaa_Eduworks

Elaa_Eduworks

Күн бұрын

Пікірлер: 28
@brianday67
@brianday67 6 күн бұрын
3 just by looking at it.
@YashinArafatRafi
@YashinArafatRafi 9 күн бұрын
Thanks sir
@herbertklumpp2969
@herbertklumpp2969 3 күн бұрын
Easy x=3 conlude x^3+x - 30 = ( x-3)* ( x^2 -3x +10)=0 Solve the quadratic Equation complex solutions thats all
@tharanathakula3588
@tharanathakula3588 3 күн бұрын
X = 3 transpose X in the equation to other side to satisfy the equation
@VELenergo
@VELenergo 9 күн бұрын
х1=3 _________________ х2+3х+10=0 х2+3х+10-7,75=0-7,75 х2+3х+2,25=-7,75 (х+1,5)2=-7,75 х+1,5=+-sqrt(-7,75) х=+-j•sqrt(7,75)-1,5 х2=+jsqrt(7,75)-1,5 х3=-jsqrt(7,75)-1,5
@dr.m.k.hardaha4114
@dr.m.k.hardaha4114 22 сағат бұрын
The number has to be positive. X^3 + x = 30 X[X^2 +1] =30 Factors of 30 are 2, 3 and 5 X can't be 5 It has to be 3 X=2 does not fit
@stealthragnarr2644
@stealthragnarr2644 Күн бұрын
X = 3, that's it 😮😮😮
@madurappankalyanaraman8015
@madurappankalyanaraman8015 3 күн бұрын
X should be equal to 3 3³ +3= 27+3=30
@Christopher-e7o
@Christopher-e7o 2 күн бұрын
X,2x+5=8
@bayuafrianto276
@bayuafrianto276 23 сағат бұрын
Is 3 just to look by number and think hahaha
@hottuamanullang8046
@hottuamanullang8046 10 күн бұрын
3
@bradramsay8299
@bradramsay8299 6 күн бұрын
Ok, but let's assume it's not something as obvious as 3 in the first step. How would you approach this problem? What if it's x^3+x=40? Doing x^3-27+x-3 is no longer useful. You pretty much just skipped the most important step.
@theultimateidiot7943
@theultimateidiot7943 3 күн бұрын
And u pretty much just skipped the mean of the problem, solve it for me without calculator then please
@robertlunderwood
@robertlunderwood 3 күн бұрын
@@bradramsay8299 Rational root theorem. The worst case scenario would be the cubic formula.
@Shivsingh-e3z
@Shivsingh-e3z Күн бұрын
X is equal to 3
@morelibrahimtraore9389
@morelibrahimtraore9389 5 күн бұрын
3*3*3 + 3 = 30
@subratabiswas2502
@subratabiswas2502 6 күн бұрын
x^3+x-30=0 ; i,e x^3-27+x-3=0 ; i,e (x-3)(x^2+3x+9)+1(x-3)=0 ; i,e (x-3)(x^2+3x+9+1)=0 ; i,e (x-3)(x^2+3x+10)=0 ; i,e x=3 or x= (-3+√31i)/2 or (-3-√31i))2
@earlwoodland1873
@earlwoodland1873 3 күн бұрын
3 is only a partial answer. Since this is a cubic equation it ha 3 answers. One real and two imaginary.
@horuxs
@horuxs 6 күн бұрын
X is 3 . 1 sec for solution
@ChuckyTheHorrorSouthParkLover
@ChuckyTheHorrorSouthParkLover 6 күн бұрын
Yeah that was easy
@Halina-cg8zo
@Halina-cg8zo 10 күн бұрын
3
@ChuckyTheHorrorSouthParkLover
@ChuckyTheHorrorSouthParkLover 6 күн бұрын
3
@pas6295
@pas6295 5 күн бұрын
3
@gopalsinnarkar277
@gopalsinnarkar277 4 күн бұрын
3
@chinnu8038
@chinnu8038 3 күн бұрын
3
@rajendransubramanium5650
@rajendransubramanium5650 3 күн бұрын
3
@Stopthegyattbots
@Stopthegyattbots 2 күн бұрын
3
@LightningBFDI-e4r
@LightningBFDI-e4r 2 күн бұрын
3
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