Calculate Solubility from Ksp

[@alexiamcintyre]

This channel is so underrated! Thank u so much for these videos! I’m watching all the ones in the playlist , they are extremely helpful and very easy to understand

[@OldSchoolChemistry]

Hi Alexia, I am so glad! I hope they put you ahead! Thank you for your comment!😊

[@abigail3032]

I have a test tomorrow You totally saved me!

[@OldSchoolChemistry]

Hi Abigail, I hope your test went well. Great job doing extra work to figure out chemistry:)

[@amrithaketheeswaranathan7929]

Your videos help me so much!!

[@OldSchoolChemistry]

I am so glad! Thank you for letting me know, and God bless you in the rest of your class:)

[@OldSchoolChemistry]

I am so glad!! Thank you for letting me know and God bless you in your class:)

[@morvis422]

Thank you! This is exactly the help I was looking for for my homework!

[@OldSchoolChemistry]

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[@spaceshipastro]

thanks, really good explaintion and simple in the same time

[@OldSchoolChemistry]

Hi Spaceship Astro, I am so glad! I appreciate your comment - thank you!

[@spaceshipastro]

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[@azizalharbi7412]

you make everything easy! thanks

[@OldSchoolChemistry]

Hi Aziz, I am so glad. I hope your class goes well! :)

[@paolocamesasca4336]

Hi, I really liked this video, It is clear and very good, but I have a question: Why do you use Ksp = 5.5*10^(-5) while all the data about Calcium hydroxide say 5.something*10^(-6)? When I repeat the calculations with the available data from different institutes, the solubility I obtain is 0.79g/L, while the correct value is around 1.7g/L. Where did you get the Ksp data? And why the "correct" Ksp value does not give me the correct solubility? Thank you!

[@OldSchoolChemistry]

Hi Paolo, I am sure I just looked up the Ksp for Ca(OH)2 on a table. Maybe I misread it. You can Google or look in textbook tables for salt Ksp values. Ask your professor which table they prefer you use! Thanks!

[@hamzaal-f4x]

you helped me alot thx so much

[@OldSchoolChemistry]

Hi Hamza, You are welcome! I am so glad it was helpful:)

[@JUHAYRAAGAMA]

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[@OldSchoolChemistry]

Hi Juhayra, that makes me SO happy! Thank you for sharing with me, and well done working so hard!