Solubility Product Constant (Ksp)

We've learned that some ionic solids are totally water insoluble, but in fact this is a slight oversimplification. Even such solids will dissolve to some minuscule degree, and we can measure this, and do calculations with it. Let's learn about solubility product constants!
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[@NourAhmed-go5jo]

7:53 x = 1.3 * 10 ^-3 not -9 for anyone who found it confusing it's just a mistake in the video

[@ProfessorDaveExplains]

Ah shoot! What a dumb mistake, thanks for catching that.

[@mycrafts5701]

S there is mistake in powers

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[@FortressFour444]

I keep on getting that answer raised to 4 instead of 3. Don't know what I'm doing wrong though, I've punched it into my calculator in different ways.

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[@ProfessorDaveExplains]

there is a checking comprehension question at the end of the video

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[@michaelsanchez3680]

Hi, a question: When one of the ions in the equlibrium concentration is, for example, 2x, why should also be squared?

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[@natan-elmensahsowah4581]

Thank you !! However, I have a question. I understand that for (OH)2 in Ca(OH)2, 2 is the coefficient for OH and becomes its exponent when calculating Ksp. How do you decide to use the subscript as a coefficient. I was wondering why in the last question PbI2, 2 was used as the coefficient? The reason why I am confused was because in the CaCO3 example, 3 was not used as a coeeficient : just [Ca][CO]?

[@arduino_8829]

This may be a bit late but that's because carbonate is a polyatomic ion. CaCO3 is one calcium (Ca) and one carbonate (CO3). If it were Ca(CO3)3 then there would be three carbonate ions and the exponent would be 3, [Ca][CO3]^3. This means that the Ksp expression would be Ksp=(x)(3x)^3. Because the carbonate is not separating into individual molecules, it is functionally just another ion, similar to iodine.

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[@parasuramang1860]

I been regularly asking this doubt ..Please help me with it..... I need reference book details that you use for yourself. If you could tell please share them.. and Thanks for your videos....

[@sofia4933]

for 7:00 why is the Ksp 4x^3 and not 2x^3 ??

[@Finnnloafin]

(2x)^2 is the same as 2x times 2x, so you can solve that part by multiplying the 2's and the x's together, making 4x^2. Then you multiply that by the last x which makes 4x^3. Hope that helps!

[@adarshyadav2848]

I got a confusion but this video help me a lot . Thanks for this video .. yyehhhh

[@nakhorosualehe1543]

Thanks Professor Davis

[@Chebe2]

How did you get the 2.6 * 10 ^-3? I know what the single X comes from but not the concentration of Iodine.

[@marislox1844]

If he knew what he was talking about, he would have explained. I suggest not wasting your time with this person's videos.

[@Absalonian]

Basically, the subscript becomes the coefficient since the amount of iodine being dissolved is two per molecule. And then using what you learned about icebox earlier you just apply the same concepts. At least that’s what I got out of it.

[@Absalonian]

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Looking good prof

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Hey Proffesor ! It's nice to bump into you again..

[@mechanical_engineering_passion]

Why we raise the power of concentration by its stoichiometric coefficient? Please explain

[@FireSniperShot]

Why is the OH value doubled AND squared?

[@ezzeldin3714]

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[@ezzeldin3714]

I dont get it either

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I did not focus on this video, just his neck.

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[@x-tr-igor5961]

I have a question: Why did you use solid compound I thought you can't use it or how does it work?

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thanks bro it helped a lot.

[@gary9793]

Thanks Sir!

[@asmaaabdelghany4707]

Can you explain calcium phosphate kidney stones formation through solubility product? I am a pediatrician and find it a bit difficult Thanks in advance 🙏

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Thank you

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Fantastic! Thank you.

[@irrationalmostly]

wait what do you mean by ''unitless equilibrium constant''? equilirium constants may have units..

[@aht3261]

at 6:06 how didi you solve for the 7.9×10^-5?

[@jakepena5563]

Square root

[@raezeaneizhiguillermo4470]

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[@minjinseo3681]

Hello, sir. What will happen to the solubility of BaSO4 if NaCl is being added, and why? Thank you so much.

[@aldanadagimpaulos7511]

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[@arway4766]

why does adding a solid not affect the equilibrium constant ?

[@mauli5380]

Please make a video on quantum computer

[@theredmonkey236]

I have two questions: 1.For your first example problem (6:00) when you broke down CuBr into Cu and Br you didnt put a subscript of 2 on Br. isn't Br diatomic? 2.In the Ksp formula do subscripts count as coefficents and go above the element? Or in the ICE table do you count them as a coefficent?

[@ProfessorDaveExplains]

Molecular bromine is diatomic. CuBr is an ionic compound consisting of one ion of each element. Coefficients that apply to each ion become exponents in the formula.

[@theredmonkey236]

@@ProfessorDaveExplains So are diatomic rules ignored when you break down a ionic compound?

[@ProfessorDaveExplains]

It's just a totally different compound. It has nothing to do with this one.

[@theredmonkey236]

@@ProfessorDaveExplains Oh ok, thanks for your help!

[@FakharKhan-sj2tq]

@@ProfessorDaveExplains I have a question that why we take square on [I-]2

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Thank you for this information👍💗

[@user-fl3zk4fv8u]

Why dont we consider solid reagents?

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Could you please make a video on Organometallic Chemistry?

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[@faeidhussain2657]

why to raise the molarity to the power of stoichiometric component?

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Awesome video

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thanks mister

[@deossegirinya1817]

What about the solubility of iron(II) hydroxide in a. Solution of ammonia solution

[@sonali_2_]

Thank you sir

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Thank u sir so much now i know how to make ICE chart💖

[@lidamagnus6053]

I don't get it dave.... pls send help

[@aaronius4444]

so when you're given Ksp of the reactant and find the solubility of the other products, how do you take pOH from that?

[@TarekFansa]

thanks very much

[@negar1370]

thank you so much!

[@rassimsimou1594]

Good

[@hillan_4462]

Thanks alot

[@magnuswootton6181]

does this mean if the human body is in touch with distilled water u solute a tiny tiny amount into it?

[@colephillips8070]

Can anyone explain why the book Ksp values very between different resources (even for the same temperature)?

[@reemissam6399]

Am really confused how did u get the 1.3×10^-9 like i mean what do u write in the calculator to get that result?

[@fernandagonzalez116]

I cant seem to understand the last practice problem can anyone explain?

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[@omaremad4780]

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[@thirumavalavanvalavan5074]

Why some AgCl soluble

[@miniwidget6407]

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[@MPH044]

1.3^-3 not -9

[@rav2254]

How do you know how many ions it dissolves to?

[@ProfessorDaveExplains]

just split it up into individual ions