ON07 P4 Q1 Elastic String Rotation | A2 Circular Motion | CAIE A Level 9702 Physics

[@UzairKhanNS]

That was helpful and easy to follow . You went through it step by step , gave the formulas needed ( I had totally forgotten Hooke's Law ) and you're personality made it less boring. From a new A2 student: Thanks!

[@ETphysics]

Glad it was helpful!

[@ibrahimshakir9598]

you forgot to square the angular speed in the last

[@JudeWeraduwage]

Thank you for tension=0, very helpful!!!!

[@raaziaabdullah23]

Thanks for explaining !! You’re amazing 😭💪🏼✨

[@kabeerahmed4588]

Really helpful! ❤️❤️❤️

[@asifjahanshuvro3245]

Hey, you forgot to square the angular speed.

[@ETphysics]

Yepp that's a typo, but somehow the final answer is still correct lol Good catch tho!

[@imboredd123]

Hello miss, why doesnt the centripetal force remains at 5N according to when the mass is at the top? and so tension is 5+5= 10N when the mass is vertically below C?

[@studycrumbs]

I'm wondering the same :((

[@BOBO_4869]

Because this is not a uniform circular motion, radius changes at the bottom so centripetal force magnitude won't be constant

[@57c37]

Damnn brooooo

[@alkadas6281]

I didnt understand why t=0 can someone explain? lol nvm I understood :)

[@mansoorghauri8087]

if possible, can you tell me? or even you can ETphysics

[@fabihaareeba9657]

It was very helpful thank u! ❤️

[@rumaisasiddiqa9638]

how do u know tension is 0 at top position??????????????????

[@nabeeharehman1140]

I guess because the question says that at the top, the *unextended* length of the string is 13.0cm. Since there is no extension, the only force acting is the weight.

[@rumaisasiddiqa9638]

@@nabeeharehman1140 thanks I get it 🥰