Projectile Motion: Shooting a Basketball Problem

[@eugeneallevato5791]

I would explain that the equation for the height is a parabola. So there are two solutions: one for going up and going down for the 10 ft mark. However, the velocity has a negative sign once starts going down. Once you calculate the time for 15 ft, you define the location. I guess, at least for me if you see the description of the trajectory as a parabola, it is easier to understand.

[@koungmeng]

Glad you are back. Haven't seen you in 4 months xD

[@PhysicsNinja]

I took the summer off but am back now. Looking to make 1-2 videos/week. Thanks for following Physics Ninja.

[@FavourEzema-m8i]

How is a basketball carrying a projectile motion

[@SlionsDotNet]

Awesome video, helped me dust off my math. However, I seriously doubt you can score from 7 feet with 45° angle. Pretty sure it hits the frame of the hoop first. But it does make the equations look prettier after simplification because sin 45° equals cos 45°. As a basketball player you would have a lot more success shooting with 60° angle and above.

[@connormann9612]

is the velocity you found for the final question the same as the final velocity?

[@Animedeos]

Hello from 2024,thankyou so much it helps me a lot in my assignment, to all videos abt projectile motion, I think it's the easiest vid to understand NFL😂😂😂

[@user-sh7ov3df6p]

Yayyy tysm!! I really needed this!

[@ribandrey6430]

Oh wait I have another question sir. In 12:59 you showed how to solve the time it takes for the ball to reach the rim, and actually we are doing our research now and we know the t or the time it takes for the ball to pass through the rim. So, can we simply calculate the initial velocity from there like: Vo = L/((cos0)t) ?

[@PhysicsNinja]

Yes

[@abbyberkenyi8175]

how would i solve this problem if my problem did not give me and initial height of ball but i have the initial velocity?

[@jeromesmoral8636]

sir why did you used 9.81 m/s than 32.2 ft/s even though its feet?

[@pauloopena3652]

May I ask why the Vy= Voy-gt is not Vy=Voy-gt because the Vo of the Vy would be zero cuz it's from the max height?

[@danielshamlian2800]

You lost me at 15:40 I don't understand how all the v sin thetas (I count four of them), only turn into v^2sin theta^2 -- it looks like either half of the equation would be that, but one just disappears. I can't base my studying on terms seemingly disappearing, so I can't use this to study, even if the answers are right. Thanks for trying.

[@lancepaschal8486]

How could the height of 3 meters and the acceleration due to gravity both be positive

[@prathameshrumde3027]

hi sir can we cal calculate initial velocity v by using formula R = v2 sin(2theta)/ g R = 15 feet = 4.57 m theta = 45 degree if yes then im getting v as 6.69 m/s pls clearify

[@armelasopjio2986]

Hello excuse me, is the velocity considere as a force? Otherwise I want to know how the movement on the horizontal direction is made.

[@PhysicsNinja]

Velocity is not a force. This analysis starts from the instant that the ball leaves the hand. Once the ball doesn’t touch the hand the only force acting on the ball is gravity (ignoring air resistance). It will be the hand that produces the initial force on the ball to cause the movement.

[@sskprl]

Good content 🎉

[@nourmakhlouf2628]

in 10:56 you said the height was 3 ft... isnt it 7ft which is 2.13 m ?!

[@lourdessalgado9177]

you are doing great

[@themflad]

What Math is used in question 2?

[@guapdoctor4534]

Thank you!

[@mulatiedemis3501]

good work

[@ribandrey6430]

Hi Physics Ninja! It was a very informative video! However, I have a question. Is it possible to calculate the force exerted by the player (in your example) without the acceleration and final velocity of the ball given?

[@PhysicsNinja]

Not possible

[@ribandrey6430]

Ok thank you!

[@ribandrey6430]

Btw how do you calculate the release force when shooting the basketball? Like are there any formulas for it?

[@lawdcastentertainment7688]

@@ribandrey6430 I think for a basketball player, they could measure their max height, where Velocity Y =0 of their throw.

[@boscomerinoechevarria6844]

What if you don’t know the initial angle and what to find it

[@larsvanmoerkerk2953]

kzbin.info/www/bejne/apuxdmabibt4ndE

[@EyaelMekuanint]

Thank you

[@vikramnagarjuna3549]

Why did you take long gap bro...

[@greerangeminecraft6912]

ITS NOT STRAIT forward to the point but its fine i learn something from it

[@trhasamare8865]

wowowwww.but how can i get acc ?

[@lincolninniss5781]

Hi, I worked out 3.56 m for the maximum height.

[@russellcapilayan3763]

I agree. this should be the answer. you should add the height of the player when releasing the ball.

[@Vishnu_the_slayer]

❤

[@tatemccune5881]

I don't think the maximum height is correct. how would it be less than the height of the basketball rim? I got 3.56 m for ymax

[@PhysicsNinja]

10ft rim is 3.05m… all good

[@meshachjones6909]

God sent

[@fizixx]

😎

[@baconear7155]

You remind me of Ben Affleck lol

[@Thewerwolf]

Last velocity value -3.18 is actually your value in ft/sec not m/s. Your value in m/s should be −0.99584 m/s. If you us this the angle should be actually -10.5 degree thus 10.5 down from the horizontal. Cheers and thanks you have fun content...

[@russellcapilayan3763]

he converted all in ft to meters, before solving, what are you talking about?

[@matteveringham477]

what da fuck