Coulomb's Law Problems

[@weapons_check]

This literally helped me more than my actual physics teacher Tysm!

[@vinay22]

tbh i agree wid u

[@taylormadechamp]

Watching you work these problems out and explaining them makes it seem fairly simple. My instructor and the text made it so confusing for me. Thanks!

[@steves1015]

Nice video and you explained well. Just a minor point, it is a bit confusing when you say that when calculating F1 or F2 you don't need to worry if it is positive or negative because that just tells you the direction. Then later you say that the positive or negative for Fnet tells you the direction. I think it would be clearer to say that the negative or positive for the F1 or F2 indicates an attraction or repulsion. The positive or negative when calculating Fnet would indicate direction, left or right.

[@amanuelendalkachew2499]

thank you for your clear explanation .from Ethiopia

[@zewditukergo7951]

Are you from ethiopia? Nice to meet you

[@zewditukergo7951]

Are you grade 11

[@zewditukergo7951]

fool

[@cara.bella15]

Literally godsent video, thank you!!

[@qudhachure9598]

by this video, you earned my subscription your awesome mate.

[@thameral7rbi]

thank you very much, I've watched several videos, yours was the best.

[@PhysicsNinja]

Wow, thanks!

[@marekamoorosi7565]

You the best sir💞💞 Was lost but now am focused 💪

[@ARTDEVGRU247]

are you found?haha

[@erikjusufm]

Absolutely beautiful explanation like everytime, thank you!

[@christopheravila7989]

How do you locate q3 given 3charges and d between q1/q2 So far no one in any video has answered this, tired of net forces or magnitude

[@carultch]

It would help to see a time link for what example in the video you are asking about. q3 could be anywhere relative to q1 and q2, depending on how we specify it. You might ask, where can we place q3, so that the net force on it due to q1 and q2 is zero? Given q1 on the left and q2 on the right. In which case, you'd set up a generalized equation for the force on q3, along the axis of q1 and q2. You'd then identify three regions (left of q1, between q1 and q2, and right of q2), and develop an equation for the force on q3 in each of these regions. By inspection, you can rule out regions where the force on q3 could not equal zero. For instance, if q1 and q2 are opposite signs, then we know the force on q3 can't be zero between them, so we can rule out that region. If q1 > q2, then we know the force on q3 can't be zero to the left of q1. This leaves only one region (right of q2), where there could be a zero force point, to place q3.

[@raniahabbas85]

How do you know whether to measure from the horizontal or vertical when we want to find the x and y component. Like how do we know where to put the theta? 😔😔😔 help!

[@redjinn999devil2]

thank you your 100th comment on this vid love from Pakistan 💓

[@PhysicsNinja]

You rock!

[@zewditukergo7951]

​@@PhysicsNinja How

[@johnkevindavereposposa4223]

question. the Fnet 1y,. why did you use the 0.2m (0.2m is the d)? i think it should be 1.35N - 0.44N. since we are looking for the net force..

[@quakinaspens]

in the second problem after finding the angle 71, do we have to find the reference angle since it is in the second quadrant ?

[@manraaj7409]

i think its better to give a reference, to confirm the direction

[@BeyeneTasew3111]

Yes, Excellent answer ! I appreciate you! Thanks!

[@splashmoney2337]

thank you, u saved my life for the diagnostic test tomorrow.

[@PhysicsNinja]

Glad I could help

[@zewditukergo7951]

bruh. Also for my **** exam it helps a lot❤❤

[@jaganmayeesahoo4210]

Thank you ADMIN.# love from India

[@punsarawithanage3840]

Superb one ❤️ from Sri Lanka 🇱🇰

[@ravenousstrike012]

Thank you and this will be very helpful for my future tests and topics in Physics 2: Electromagnetic Waves❤! But i have a question, what is the exact value of 1Coulomb? It is 6.241x10^18 or either +/- 1.6x10^-19? I'm really confused that i cannot make progress about this problem. And also, if for example there's 2C, should i also multiply it by 2 on either of those 2 on my first question? The answer i get if there's only number of charges instead the value of C is on scientific notation and higher numbers that isn't I expected. Anyway thanks again for these!

[@zewditukergo7951]

Bruh, colomb is scalar. so we never use negative sign for that.

[@jakeisrich]

Why is did you disregard the sign in 11:12? isn't q3 supposed to be -2x10^6

[@sama1494]

I think it's because the formula only needs the magnitude of the number not it's direction or something like that

[@rachelhiltystudenthbhs2575]

great explanation! thanks for saving my grade

[@iiStayFlyx5]

hello, im having trouble figuring out when to use sin and cos when solving for f1x in coulombs law, the trig is messing me up. why did you use cos

[@sameerasif5302]

Hi, I think cos is used on the line where theta is, and sin is used on the line perpendicular to that.

[@thefirsthandleonyoutube]

Basically (cos) is used when your closing the angle. Like if the angle is on the y-axis, then you use (cos) with respect to the y-axis and (sin) with respect to the x-axis. And vise versa. Hope you understand and it helps.

[@raniahabbas85]

@@thefirsthandleonyoutubehi, I have problem with where to measure my theta. If the question didn’t tell me the angle is horizontal or vertical. How do I know where to measure the theta from?

[@Hecticweek]

Thank you so much sir 👍👍👍

[@jpmcfrosty]

Followed this ex down to a tee and its saying my Net Force value is wrong, not sure what else to do. Only difference in my problem is that my q2 is positive and my q3 is negative and it wants my answer in mN's not N. Have walked through 3 different tutors now and none of them we're able to come to the same conclusion. not sure what else to do...

[@rubyanneinto49]

On the first problem, was it supposed to be 0.135 instead of 1.35 N?

[@daryldadizon5485]

question why u write -0.2 in calculation of F1y but the given is 0.20?

[@PhysicsNinja]

Because that component of the force is pointing down and i've called that the negative direction.

[@laurentiuslancaster1657]

Is it explained why he uses Tan at 13:50 specifically?

[@sama1494]

Because when we have an angle Tan = opp/adj

[@davidg305]

No but u can u use any trig function and get the same theta

[@hawadrammeh8870]

Awesome video, thank you so much!

[@Sattamsager]

Thank you so much this helped me so much

[@anastasia2291]

Very good explanation, thank you, you make me understand

[@imsengky]

Thank you so much, sir.

[@Aboodinho.]

I am the one who should thank you actually ♥

[@Ishmamy]

Great vid. But why do you not convert the micro coulombs to coulombs, doesn't it affect the answer?

[@PhysicsNinja]

just a habit. i always convert to SI

[@Decoy22x]

i wish my hw this easy

[@mathias1116]

Me to😢

[@salynt1126]

me three😥

[@ShitThatsMyn]

It's like watchmaking. Cheap, mainstream ones are easy to replicate. While expensive ones require craftsmanship and many complications. By having many complications in your homework your professor is building an expensive, luxurious brains. XD

[@overl0ad816]

@@ShitThatsMyn in which 50% will forget in a year and 95% in 5😂

[@alieusenghore4758]

sameee

[@amarakhan2192]

Why the direction of F2 is towards positive charge? It should be outwards.

[@richardferre1253]

but why do we do the vector and angle thing

[@PhysicsNinja]

unfortunately you have no choice the forces are vectors which have a length and a direction and you might need to add several vectors together. This will require some vector algebra.

[@richardferre1253]

@@PhysicsNinja yep that hurts me Ahah but why do we do it in this case, like what is a vector and when do we use it

[@GidleyKome]

What if the net force is negative, are we going to write negative charge or not

[@GidleyKome]

Sorry not charge but the negative sign

[@GidleyKome]

Please I need immediate reply

[@syedhunainali7663]

why you take nagitive sign on net force of x component

[@sholaibukun1352]

Sir, From my calculation the force on q1q3 is0.66N pls do a check Thanks

[@marriamhaji7440]

Thank you so much ♥️

[@al-edrisy1129]

Sorry , can some one tell me in the first problem why F21 = 135N Because I fund it 0.135N

[@rubyanneinto49]

I knew it😅😅

[@rubyanneinto49]

I also got the same answer😅

[@louistaboada964]

pls help im stuck at the part where 0.2 over 0.4 is equal to 1/2, explaination?

[@daph_di.]

0.2 / 2 = 0.1 ; 0.4/2 = 0.2 so 0.1/0.2 is the same as 1/2 it’s the same ratio

[@CalvinEthan]

Thank you sir, but I’m confused from breaking down of F1 into two components till the end pls help😢🙏🏾

[@pitfall0121]

Thank you for this video!

[@szxnv]

he's the goat

[@SadiqYahaya-o7i]

Thank you sir

[@mahletmekuria144]

Awesome vido i really say thank u

[@allyssacorral846]

Why is it -6?

[@mrchocolatebean8878]

thanks a lot man

[@bohlalenchabeleng1370]

Thank you.

[@en.muhammad6882]

The last parts of the second problem weren't clear enough Why did break the force into components?

[@ahmedomar9804]

You need to break into components because it consists of horizontal rise and vertical as gradient I.e. it is not fully vertical or horizontal - it's between them. This shows you that, it consists of vertical and horizontal line which you will need to find each of them. Another thing that can show you it consists of two components, It's like hypotenuse which is found by using the horizontal and vertical lines. Hope you'll get it.

[@en.muhammad6882]

@@ahmedomar9804 Thank you alot Ahmed for the reply... even though I don't need physics anymore but it was helpful for a further knowledge thanks again.

[@ahmedomar9804]

@@en.muhammad6882 You are welcome. 🖐

[@Ghost-hv2bi]

Thanks u helped my a lot 😅

[@kamilamohamed284]

Can u do it again the second problem please

[@AmareGebeyaw-kp3ih]

Way q3 came to between q1 and q2 not understand you says please

[@galagarcrizelm.2226]

Thankyouuuuuuuuuuuu so muchhhh

[@keolebogileseepamooka0169]

I don't understand the part where you are explaining the constant (k)

[@carultch]

It's a universal constant that we experimentally determine. It has a value you can look up, which is about 9*10^9 Newton-meters^2/Coulomb^2. Coulomb experimentally determined this constant, in a similar manner as Cavendish determined the Big G of gravity, and hence became the namesake of this law and the unit of charge. You may see it written as 1/(4*pi*epsilon0), to relate it to Gauss's law, in which case epsilon0 is the experimentally measured constant that directly depends on the Coulomb constant K. This way, 4*pi*r^2, the surface area of the sphere of influence, appears in the denominator.

[@letsileutlwang2456]

Thanks. But just to clarify, the alpha should be 71.3.

[@toitozky155]

don't approximate the number

[@arcadiana-jan-causin5421]

can anyone enlighten me why 1.35N when i got her 1,350?

[@joanad1246]

Earned a subscriber thx❤

[@PhysicsNinja]

Thanks for your support!

[@maxbingen8773]

THANK YOU

[@anwynanimations7207]

Amazing, thank you!

[@brandongarcia8244]

For the second question what happened to the 0.44N?

[@roeal-wazeer3135]

he used it to calculate the x and y components of that force, then used those calculated components to find the net force

[@cyrus2857]

fantastic

[@JamesPOATE]

Can you add a video on charges forming equilateral and how to find the magnitude and direction of the force of one of the vertex of the triangle.

[@ebukaugwu1684]

great work

[@wamakaghambi4477]

wow this is really a good work

[@Hanan-pe4hh]

Find the.distance between two spheres one -3.0x10 race to -5 and the other -2.5x10race to -4 ,if the electric force is 1.0N

[@Hanan-pe4hh]

What means electric force?

[@ahmedomar9804]

r=7.35m

[@ahmedomar9804]

@@Hanan-pe4hh Electric force is the force acted on a charge by another of like(same) or unlike ( different) charge(s).

[@EYEBALLKLOTT]

Thank you for telling

[@jbonceu2457]

Just wanna clarify, if it's a negative charge, do you require to put negative sign on the process or not?

[@ahmedomar9804]

No, you don't need. The negative sign just shows you that the charge you have is a negative charge. But if it is force, the negative sign shows you the direction of the force.

[@frazebean5117]

Don't put negative sign on the process as it just defines the direction.

[@ahmedomar9804]

Thank you, sir.

[@lekanfabiyi3363]

Merci

[@jeseniafilpo9938]

🥰🥰🥰

[@kowh262]

You did a good job cutie

[@EYEBALLKLOTT]

We're dealing with far more than microcool. He and we at this House are dealing with every fitted label and price setter. That's Android policy you're taking about. So I have shopped for this house and receipts were sent out I expect. It also has a limited right to ERR within it's space as the state lottery stays next door. Our house may clip some hedges and it's height is as high as federalist access goes. In our practical lives here, we don't all do this. I do. I'm the fence keeper here and it is a house Paul. So let's just say it has a soft underbelly as an opportunity to prove youre A: capable of outlining a property's edges. You know what that is and you can be found at the door. B: You're safe being trusted to stand in C: You're a stay put homebody D:You'd kick instead of shoot E: You'd Enterprises F: you'd find treasures in the dirt on ground G: has no right this high up.

[@Patrick-kickass]

Very good!

[@nononnomonohjghdgdshrsrhsjgd]

du vergisst Mobbing nie und kommst über die Errinnerung nicht, weil die Stiche zu viel gewesen sind.

[@xiaos3198]

wait. how did you know that there are 2 forces acting on y direction?

[@mrfn9529]

It's so easy guys.if u were in Iran's high school you would leave the school😂.

[@Nic-co6ot]

Good thing I don't.

[@nononnomonohjghdgdshrsrhsjgd]

das ergebnis ist massiver Vertrauensverlust und Erschöpfung.

[@bert4969]

This guy is a total geek. He should stick to chemistry. Sending hate from Delaware.

[@PhysicsNinja]

I’m a physicist pinhead

[@bert4969]

@@PhysicsNinja oh really? Sounds like something a wannabe physicist would say. Stick to chemistry bud…

[@zewditukergo7951]

​@@PhysicsNinja He is great. but no use to learn most physics justto pass the f*ucking exam

[@wistfulgraph]

@@zewditukergo7951then why click on this video?

[@marbenangelolause3186]

hello newton set b

[@nononnomonohjghdgdshrsrhsjgd]

ich wünsche allen, die mitgelacht und teilgenommen haben, es zu erleben. dann werden sie sich anders verhalten.

[@nononnomonohjghdgdshrsrhsjgd]

mobbing muss verboten werden.

[@OzoemenaZita]

You lost me when you brought in the components for F1. Why F1 and not F2. The whole thing is confusing and annoying 😭😭

[@devcl1ps]

you earned my dislike thanks so much for not helping

[@PhysicsNinja]

I still like you

[@devcl1ps]

@@PhysicsNinja mbmb i got really pissed bc i couldn't understand lol

[@SalisuMaryam-d1u]

You should start from the questions not just from diagrams please

[@zewditukergo7951]

There is enough given to solve the problem on the diagram.