Introduction to Coulomb's Law or the Electric Force

[@as2ria]

This is the most unique channel for learning physics. I always find those questions that roam in my head and i don't know how to even ask them, i find them answered here already. The amount of effort and the "classroom vibes" you put in these videos provide a perfect environment for learning. I remember in the first semester i literally watched every single video i found about acceleration and did not understand the topic fully until i came across the bicycle video on your channel and i was really impressed of your ability to convey information in this unique way. For this topic, Clearing misconceptions, having students with different personalities and point of views, simplifying the subjects yet still not oversimplifying them that they don't lose their purpose, the amazing notes that you put while explaining are the most helpful thing that when i look back at my grade 11 textbook (holt physics if you care to know) i find these little notes summarizing the whole topic, i am really luck that i came across this channel, and grateful for the efforts you put in these videos!😊

[@FlippingPhysics]

What a wonderful comment. Thank you so much for this!

[@KBAZ100]

Just in time! I begin my units on Electricity and Magnetism tomorrow. Excellent video as always. Thank you so much for all of your efforts!

[@FlippingPhysics]

You are very welcome. I hope your students enjoy E&M!

[@cloyo5535]

Been 4 yrs bro , did you pass your course? Or almost

[@lgmarquez5469]

Omg! I got PTSD just watching this video 😖. I’m now a freshman in college and I remember watching your videos religiously junior year when I was taking AP Physics 1. You helped me pass the AP test with a 4. Because of that 4 I don’t have to take any science classes in college 😭. Thank you so much! I recommended your videos to my friends and my cousins who are currently taking physics. Hope the best for your channel man and will keep recommending your channel to all the crazy people I know who decide to enroll in a physics class😂🙏🏽.

[@FlippingPhysics]

Thank you for recommending my videos to my friends, however, it does make me a little sad that you no longer take any science classes. ☹️

[@DN-ps4bn]

WTF this man is literally the best teacher ive ever met in any subject on anywhere. I actually understood it all without writing anything down!

[@FlippingPhysics]

Thanks, Bo.

[@patsuan356]

You made it so simple to understand that a middle schooler would understand it too, respect

[@estebandiaz8063]

Better than doing the full readings! Explains the confusion I had!

[@AlaizaF]

how I wish my professors would teach physics this way. My life wouldn't be miserable

[@yamalote]

Same, I don’t understand a thing of what my teacher says, I guess that’s why people don’t go to his classes anymore, they’re so unorganized and not understandable XD

[@iRekishi]

hey Mr. P, you are the first physics channel I have watched where I learned and was entertained at the same time. I cannto express how much I enjoy these videos and how valuable they are to my understanding. You not only teach but also understand the common questions that we as students may encounter when hearing this for the first time. Thank you so much man!

[@FlippingPhysics]

You are absolutely welcome my friend!

[@julesislesbjan]

My teacher doesn't teach us anything so i have to resort to KZbin lol. Thanks dude, youre doing wonders for my grades.

[@FlippingPhysics]

Sorry. Glad to help!

[@kunalkumar-bt2ts]

i am from india .your video made my concepts stronger

[@lermabaldago3138]

I wish you're my physics teacher for real! Thank you! New subscriber here~

[@niki-rr1bj]

This is my first time watching a video on your channel, sir, and I have to say, this is very commendable! You explain so well and I love the small skits. It makes it interactive, and your explanations are extremely detailed! Thank you sir!

[@FlippingPhysics]

Welcome aboard!

[@erratum5619]

Our professor links your videos to our classes all the time! Super thankful for your videos!!!

[@FlippingPhysics]

Great! I am glad to help you learn.

[@teja7986]

Helpful for JEE Aspirants, Thank you

[@FlippingPhysics]

Agreed. The physics is the same in The United States and India!

[@chandanpandya1642]

I haven't seen prof/ teachers being mindful of explaining why we use micro coulomb in numericals. And now I know why we do.

[@scienceidisolated6659]

THE WAY OF YOUR TEACHING IS INCRIDIBLY GOOD ! THANKS ALOT. SIR.

[@sergeantleaux2979]

Very helpful to solidify my understanding for my test tomorrow, thanks so much man!

[@FlippingPhysics]

Good luck on your test tomorrow!

[@FlusteredBushStudios]

Even though im in regular physics not AP is is very helpful! Thanks for saving my test grade lol

[@Myl0696]

Thank you so much! Super cool to see someone passionate about physics that also understands how to make an interesting video, Hopefully I graduate soon but ill never stop watching!

[@MargaretEkpo-vg2ey]

I wish I had a physics teacher like dis🥺🥺

[@rose-ef5sc]

wow. came across your channel today and you do such a great job at explaining the material. thank you so much

[@ahanalahiri381]

You are a great teacher!I always understand whatever u teach

[@FlippingPhysics]

That is wonderful!

[@syedhassan4349]

the best ever physics teacher i have ever seen hats off to you sir :)

[@FlippingPhysics]

Thanks!

[@debrahm9536]

Brilliant and entertaining. Thank you!!

[@gmargarita]

I begin Calc-based Physics 2 next week! Thank you for this!

[@FlippingPhysics]

You are welcome. Best of luck!

[@MdborhanUddin-ok8nl]

your teaching method is so unique and i loved every moment of the class.God bless you.

[@FlippingPhysics]

Thank you! 😃

[@jonaha.4885]

Thank you so much, you do an incredible job. Keep up the great work. By the way you helped me pass the AP 1 test last year!

[@FlippingPhysics]

Wonderful!

[@Jordan-ww5vz]

YOU JUST SAVED MY GRADE 🙏

[@thetheoryofella]

This is the second or third video of yours I've watched. They're always helpful and entertaining- I'm subscribed now! Thank you sir!

[@FlippingPhysics]

Welcome to my channel and best of luck with the studies!

[@IITfanaticsYT]

Exceptional,, I wonder I could also form three ,experts students for me during my exams 😄

[@biancan.1699]

Love love love!! Well thought out and helpful. Thanks for these videos!

[@FlippingPhysics]

Thanks for the love!

[@ultimatefishingchampionship]

I clicked on this video because of your awesome hair and I learned a lot too.

[@raiveikhosipri7953]

i like your teaching techniques its very interesting and i can easily understand

[@onew7638]

Sir your videos are really awesome and I am very blessed to learn from you. Sir a request from my side , sir can you please make videos on ray and wave optics. 🙂🙂

[@MARYAM-ed9si]

You made the concept so easy to grasp. Thankyou!

[@FlippingPhysics]

Glad it was helpful!

[@harshateluguinfo3687]

Great job.awesome teaching skills with entertaining. Useful for jee aspirants. Love from india🥰🥰

[@FlippingPhysics]

Thank you! 😃

[@ehoerdemann]

OMFG THEY LOOK JUST LIKE U!!! THATS CRAZZZZZZY!!!

[@Enz0Gtz]

Thanks for explaining I had a test on this. Life saver.

[@kabandajamilu9036]

So nice and educative sir

[@mpilenhlemkhize5007]

Thank you so much. And I'm enjoying the video so much, it's not making me sleepy at all. Instead it's so funny and fun to watch.

[@FlippingPhysics]

Glad to keep you awake!

[@prasantpanda5680]

Thanks, you never fail to not bore me even for a single second, with bob,billy and bow🌈🌈

[@FlippingPhysics]

Thanks!

[@grooveharsh]

REALLY ENJOYED YOUR VIDEO NEVER BEFORE WS PHYSICS THIS INTRIGUING

[@FlippingPhysics]

Glad you enjoyed it!

[@loriskyrud2003]

You guys are the best. Thank you so much. I have been trying and trying to figure out the situation with that d and r^2 trip in the equation.🤪 Thank you. Thank you so much for clarifying that. And also for brilliantly demonstrating why the electrostatic force is stronger than the gravitational force (even though that’s counter intuitive) You guys are so, so great . thank you 🙏

[@FlippingPhysics]

I am very glad to have helped you learn!

[@ayeshasalmansalmanurrehman5642]

i just learned so much more in this video Ahhhh thankssss!

[@FlippingPhysics]

You are welcome

[@gamingvlogs2930]

I cant believe. Explanation is awesome. But why there is less views? Great man . Pls dont stop making videos.

[@FlippingPhysics]

Hopefully I will never have to stop making videos. Oh, and I hope I'll get more views eventually. 😇

[@jannatividad4714]

@@FlippingPhysics pls continue doing video tutorials, it really especially this time of pandemic. Ty

[@physics2349]

Sir your method of teaching is very nice.

[@brigaebryan7961]

thank you so much i have a end of term in a few mins

[@AdamWeber11]

E=MC2 energy equals mass times the speed of light squared. But light has a rate of induction, not a speed… it’s only referring to the distance between two points. Also, Static electricity and gravity are one in the same thing. So is Force and Energy, and they are always equal. F=E. Gravitational Electrical and Magnetic forces are all Energy-Mass Equivalences. There is only one force in nature, and that is pressure mediation. Call it whatever you will. It’s doesn’t change anything…

[@JenniferPChung]

I love your videos! I hope you have more for when I get to uni for engineering lol

[@NeonArtzMotionDesigns]

Since F = kq(1)q(2)/r² And x² + y² = r² We can therefore conclude in the xy coordinate plane that F = kq(1)q(2)/x²+y² P.s. I know this is not true and that electric force probably has nothing to do with the polar coordinate concepts, but it's interesting how in math and physics, there are similar variables used which represents different things

[@FlippingPhysics]

And very frustrating at times.

[@NeonArtzMotionDesigns]

@@FlippingPhysics oh yeah definitely if ur dealing with them in the same field

[@sethsamson-wk3uo]

Wow 😲 I benefited from this video. This has helped me

[@adityasingha38]

Your videos are so interesting

[@sallaklamhayyen9876]

new subscriber brilliant explanation , congratulation great job continue

[@MathsAdviceOnYourDevice]

Your videos are so educative and entertaining! :)

[@FlippingPhysics]

I do my best!

[@stevenhamerlinck6832]

In the exercise of the 3 charges, what if the charges are Q1(+) ----- Q2(-) ----- Q3 (+). Would have 2 attractive forces on Q2 : 0,0056 from Q1 to the right and 0,0056 from Q3 to the left. Now since Q1 and Q3 and equally charged, adhering to the law, these would repel each other, thus weakening the attractive forces Q1Q2 and Q2Q3. I would then assume you would have to divide the repulsive force between Q1Q3 by 2 and subtract that Force-value from the attractive force-value Q1Q2 and Q2Q3 to obtain the final (and correct) value's for Fq1q2 and Fq2q3. Correct ?

[@carultch]

The fact that Q1 and Q3 both repel each other does not impact the force from Q1 on Q2, or the force from Q3 on Q2. At least, not at this snapshot in time. Given that Q1 and Q3 are identical and equidistant from Q2, the net electrical force on Q2 adds up to zero. Indeed, Q1 and Q3 do repel each other, and if free to move, would accelerate away from Q2 and the forces on Q2 would decrease in magnitude. Assuming they both accelerate away at the same rate (i.e. masses are identical as well as charges and no other forces are involved), they both will decrease in magnitude by the same amount after a given time. The force on Q2 would continue to add up to zero.

[@ellahu5477]

I love the way you teach!

[@growwithgaurav3225]

your teaching technique is best

[@FlippingPhysics]

Glad you think so!

[@LiaqatAli-n3t]

Today I first time your video wonderful video ❤❤

[@CalebMulugeta]

Amazing easily explained tnx 🎉🎉

[@offusyoufus4278]

extremely entertaining and educational, thanks

[@FlippingPhysics]

You are very welcome!

[@aedaldaniel]

The charge of 0.056N which from Q2 is acting on Q1, then how it's acting to the right? from Q1. Should you say acting from Q2 to Q1 since Q2 is the charge in questing that's attracting?

[@broysthgaming3877]

I have a problem with some phrases, which is "I don't mind, go ahead".

[@shototodoroki1283]

I like the way you're teaching😂💙💙

[@loriskyrud2003]

Awesome video. Thanks

[@daiwikdhar6464]

What do electrons say when they move?? Charge!!! :) btw the vid was awesome u were So Charged!!!!! ;)))

[@FlippingPhysics]

Ha Ha Ha.

[@creativejay-db7261]

This is very well explained, I can't thank you enough but thank you

[@FlippingPhysics]

You're very welcome!

[@lumaineje]

Thank you!! Sending Love from the Philippines

[@glitchbanana]

Studying EE and I'm back to this video to refresh on Coulomb's Law for my electromagnetics class haha thank you so much!

[@FlippingPhysics]

Good to have you back!!

[@mang0.0]

Would you say these videos are sufficient enough to self-study the concepts for e&m? Im trying to possibly self-study this for fun lol

[@FlippingPhysics]

Absolutely. I would use this list of videos: www.flippingphysics.com/ap-physics-c-em.html

[@tiffyb.5630]

Hey how will I going to solve for electric force if the distance is in C and not a meter thank you!

[@themlgvlogs6434]

micro means 10 raised to -6 so it must be +/-5 x 10^-6

[@lsauce45]

Epic! At 1:31 .

[@nk_niels]

is this Leonard from big bang

[@FlippingPhysics]

yes

[@magranin7319]

Our textbook uses the unit vector form but with a negative sign making negative forces repulsive and attractive forces positive.

[@FlippingPhysics]

In my experience calculus-based physics uses that vector form of the equation, and algebra-based physics uses this scalar form.

[@magranin7319]

Flipping Physics I forgot to mention I was in AP Physics C : Electricity and magnetism (did AP Physics C Mechanics last year in junior year) :)

[@Omar-gs5jw]

Great video

[@namanagrawal1347]

7:08 So mathematically if we want to observe a force at any point in a dipole due to both the charges .the negative sign of force (from -q(suppose)) will give us the direction of force (i.e. towards -q(attractive)) and while calculating the net force this sign wont have any meaning (like in algebra 2-6 = -4; here *minus sign* used for subtracting and we just have to add them vectorially?

[@amirof2810]

Really good!

[@pigeonhuntron]

You're videos are the best!

[@FlippingPhysics]

Thanks!

[@victoriadeery2081]

IMMA NEED YOU TO DO A CALCPHYSICS 2 PLAYLIST PLEASE

[@sidharths9351]

Sir.. if q3 was negative and q2 positive.. is net force -0.11N.. towards left

[@joyceestefanyvejerano4976]

I hate physics but you kinda make me enjoy it

[@FlippingPhysics]

I consider that a win.

[@cassieknight6602]

If more students knew how thorough and clear you explained things you would have millions of subscribers. You need to find a way to get yourself known to all those students left to fend for themselves in mediocre public education systems.

[@FlippingPhysics]

I try. It's not an easy task.

[@treemanfan7718]

How is there a right arrow from charge 3 onto 1. i thought the arrow will be pointing on left ? Why ? Cause from what I heard from charge 2 onto 1 it points to the right cause charge 1 onto 2 has equal and opposite. Thank you.

[@duckymomo7935]

Is the subtle implication that large mssses can overcome electrical charge? Is it that suppose Earth and Mars are both partially positive, are they attractive because of gravity while electric charge isn’t strong enough to repel them?

[@carultch]

There is a charge/mass ratio where it is possible in theory for the gravitational force and the electrostatic force to both add up to zero on both objects, but it is rare you will ever encounter this. In fact, we can calculate just how many missing electrons the Earth and Mars would need for this to happen. Assuming the Earth and Mars had the same charge-to-mass ratio, and assuming both are positive, Earth would need a 3.22*10^33 missing electrons, and Mars would need 3.44*10^32 missing electrons, in order for the electric force to completely nullify the gravitational force between them. I don't know where you are getting your information that Earth or Mars is positively charged. The Earth excluding the atmosphere does have a net negative charge, but there is a positively charged atmosphere to accompany it. At the scale of astronomical bodies, electrostatic forces are close to negligible, and gravitational forces govern. At the scale of subatomic particles, the reverse is true.

[@duckymomo7935]

@@carultch it’s hypothetical I never intended to insinuate that the earth is positive

[@miniman251]

Dang, what a great video, I wish I could just watch these videos instead of attending my physics class. Thanks!

[@FlippingPhysics]

Glad to help you learn!

[@AlaizaF]

thank you so much, sir

[@Onlinebusiness-s3v]

Sir please give me the link of your video on " electric field due to ring of charge " . there are many videos of diff* prof. On youtube , but your videos are really benefitial for me , i understand the topics. So easily with your videos as compare to others . 😢 And now i am too confused i could not understand this topic 😢 .. Help me !

[@FlippingPhysics]

My assumption is that you are looking for my video "Thin Ring Electric Field". You can find it on this webpage, along with a bunch more useful videos for you. www.flippingphysics.com/ap-physics-c.html#em

[@Onlinebusiness-s3v]

@@FlippingPhysics thank you sooo much sir ☺️

[@soumikchowdhury1707]

your teaching is awesome and innovative........ a single doubt stucks in my head that "why the denominator is r(square) rather than r " , (square) is a 2 dimensional and (distance and radius) is one dimensional . every book there is r(square) but how and why r(square) is not there . please reply :) :) :)

[@carultch]

Good question. It has to do with how the fields spread out in 3-dimensional space. Think of each charge as a source of electrical "spray paint", that it sprays in a spherically symmetric pattern. When second charge experiences this "spray paint", consider a spherical shell at the position of this second charge, where the "spray" stops. The force will be proportional to the density of this "spray paint" on the inner surface of this spherical shell. A spherical shell's area is proportional to the square of its radius. Hence, the density of the "spray paint" will be inversely proportional to the square of its radius, and so will the force it represents. In a more in-depth version of electrostatics, you learn about Gauss's law, and how Coulomb's law is a special case of it. There is a concept called electric flux, that is what that imagined "electrical spray paint" really is. Any closed surface has a total electric flux, that equals the net charge enclosed divided by the universal constant epsilon_0. This is the integral form of Gauss's law, which is related to the differential form, divergence of E = rho_e/epsilon_0. You see the k in Coulomb's law will get replaced with 1/(4*pi*epsilon_0), to show how it is a special case of Gauss's law, and you see that the 1/(4*pi) and 1/r^2, when put together, indicate that electrical force is inversely proportional

[@velocityacademy1925]

Wowwwwww wht a way of teaching

[@FlippingPhysics]

Thanks!

[@kevink8748]

Yo bobby's my favorite he's a chad

[@luismerchan9140]

Electrifying!

[@FlippingPhysics]

nice

[@gusmore26]

Why is there a 12 and a 21 as subcripts to F vectors in Newton's 3rd Law Force Pairs?

[@FlippingPhysics]

Please see: www.flippingphysics.com/third-law.html

[@kleinyyt3034]

thanks

[@maguiruiz802]

Saving lives fr

[@ngsbsad5502]

I didn't get the answer in second question after determining the electric force

[@growwithgaurav3225]

awesome

[@donp3635]

I thought you get 1coulomb by 6 x 10 to the 18th power

[@PasajeroDelToro]

You should look into the Biot-Savart law also. It's really the Colomb force in disguise, but over both time and displacement, making it an angular impulse for an electric force. This lady's video on it is pretty good: kzbin.info/www/bejne/gXPLaaSVeaZjkLs

[@haze2049]

I love you brooo

[@arjaypena8810]

If I could just be as smart as these 3 guys in my class lol

[@FlippingPhysics]

I think we all feel that way.