Introduction to Coulomb's Law or the Electric Force

Coulomb’s Law is introduced and compared to Newton’s Universal Law of Gravitation. “Point Charge” is defined. Micro, Nano, and Pico prefixes are explained. Two basic example problems are solved. And a the fact that the electric force is typically much larger than the gravitational force is shown. Want Lecture Notes? www.flippingphysics.com/coulo... This is an AP Physics 1/JEE/NEET Topic.
0:00 Intro
0:13 The equation
1:27 Understanding “r”
2:10 Comparing magnitude of constants
3:29 Example Problem #1
4:38 Prefixes you need to be familiar with
5:29 Solving example problem #1
7:07 Understanding the negative
10:17 Example Problem #2
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#ElectricForce #CoulombsLaw

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[@FlippingPhysics]

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[@FlippingPhysics]

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[@FlippingPhysics]

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[@FlippingPhysics]

Thank you for recommending my videos to my friends, however, it does make me a little sad that you no longer take any science classes. ☹️

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Good luck on your test tomorrow!

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[@FlippingPhysics]

Welcome to my channel and best of luck with the studies!

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[@FlippingPhysics]

Sorry. Glad to help!

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[@FlippingPhysics]

Glad it was helpful!

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Glad to keep you awake!

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[@FlippingPhysics]

I am very glad to have helped you learn!

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[@FlippingPhysics]

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[@FlippingPhysics]

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[@FlippingPhysics]

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[@aedaldaniel]

The charge of 0.056N which from Q2 is acting on Q1, then how it's acting to the right? from Q1. Should you say acting from Q2 to Q1 since Q2 is the charge in questing that's attracting?

[@namanagrawal1347]

7:08 So mathematically if we want to observe a force at any point in a dipole due to both the charges .the negative sign of force (from -q(suppose)) will give us the direction of force (i.e. towards -q(attractive)) and while calculating the net force this sign wont have any meaning (like in algebra 2-6 = -4; here *minus sign* used for subtracting and we just have to add them vectorially?

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[@sidharths9351]

Sir.. if q3 was negative and q2 positive.. is net force -0.11N.. towards left

[@treemanfan7718]

How is there a right arrow from charge 3 onto 1. i thought the arrow will be pointing on left ? Why ? Cause from what I heard from charge 2 onto 1 it points to the right cause charge 1 onto 2 has equal and opposite. Thank you.

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[@FlippingPhysics]

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[@AdamWeber11]

E=MC2 energy equals mass times the speed of light squared. But light has a rate of induction, not a speed… it’s only referring to the distance between two points. Also, Static electricity and gravity are one in the same thing. So is Force and Energy, and they are always equal. F=E. Gravitational Electrical and Magnetic forces are all Energy-Mass Equivalences. There is only one force in nature, and that is pressure mediation. Call it whatever you will. It’s doesn’t change anything…

[@NeonArtzMotionDesigns]

Since F = kq(1)q(2)/r² And x² + y² = r² We can therefore conclude in the xy coordinate plane that F = kq(1)q(2)/x²+y² P.s. I know this is not true and that electric force probably has nothing to do with the polar coordinate concepts, but it's interesting how in math and physics, there are similar variables used which represents different things

[@FlippingPhysics]

And very frustrating at times.

[@NeonArtzMotionDesigns]

@@FlippingPhysics oh yeah definitely if ur dealing with them in the same field

[@stevenhamerlinck6832]

In the exercise of the 3 charges, what if the charges are Q1(+) ----- Q2(-) ----- Q3 (+). Would have 2 attractive forces on Q2 : 0,0056 from Q1 to the right and 0,0056 from Q3 to the left. Now since Q1 and Q3 and equally charged, adhering to the law, these would repel each other, thus weakening the attractive forces Q1Q2 and Q2Q3. I would then assume you would have to divide the repulsive force between Q1Q3 by 2 and subtract that Force-value from the attractive force-value Q1Q2 and Q2Q3 to obtain the final (and correct) value's for Fq1q2 and Fq2q3. Correct ?

[@carultch]

The fact that Q1 and Q3 both repel each other does not impact the force from Q1 on Q2, or the force from Q3 on Q2. At least, not at this snapshot in time. Given that Q1 and Q3 are identical and equidistant from Q2, the net electrical force on Q2 adds up to zero. Indeed, Q1 and Q3 do repel each other, and if free to move, would accelerate away from Q2 and the forces on Q2 would decrease in magnitude. Assuming they both accelerate away at the same rate (i.e. masses are identical as well as charges and no other forces are involved), they both will decrease in magnitude by the same amount after a given time. The force on Q2 would continue to add up to zero.

[@themlgvlogs6434]

micro means 10 raised to -6 so it must be +/-5 x 10^-6

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Electrifying!

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What do electrons say when they move?? Charge!!! :) btw the vid was awesome u were So Charged!!!!! ;)))

[@FlippingPhysics]

Ha Ha Ha.

[@mang0.0]

Would you say these videos are sufficient enough to self-study the concepts for e&m? Im trying to possibly self-study this for fun lol

[@FlippingPhysics]

Absolutely. I would use this list of videos: www.flippingphysics.com/ap-physics-c-em.html

[@soumikchowdhury1707]

your teaching is awesome and innovative........ a single doubt stucks in my head that "why the denominator is r(square) rather than r " , (square) is a 2 dimensional and (distance and radius) is one dimensional . every book there is r(square) but how and why r(square) is not there . please reply :) :) :)

[@carultch]

Good question. It has to do with how the fields spread out in 3-dimensional space. Think of each charge as a source of electrical "spray paint", that it sprays in a spherically symmetric pattern. When second charge experiences this "spray paint", consider a spherical shell at the position of this second charge, where the "spray" stops. The force will be proportional to the density of this "spray paint" on the inner surface of this spherical shell. A spherical shell's area is proportional to the square of its radius. Hence, the density of the "spray paint" will be inversely proportional to the square of its radius, and so will the force it represents. In a more in-depth version of electrostatics, you learn about Gauss's law, and how Coulomb's law is a special case of it. There is a concept called electric flux, that is what that imagined "electrical spray paint" really is. Any closed surface has a total electric flux, that equals the net charge enclosed divided by the universal constant epsilon_0. This is the integral form of Gauss's law, which is related to the differential form, divergence of E = rho_e/epsilon_0. You see the k in Coulomb's law will get replaced with 1/(4*pi*epsilon_0), to show how it is a special case of Gauss's law, and you see that the 1/(4*pi) and 1/r^2, when put together, indicate that electrical force is inversely proportional

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[@magranin7319]

Our textbook uses the unit vector form but with a negative sign making negative forces repulsive and attractive forces positive.

[@FlippingPhysics]

In my experience calculus-based physics uses that vector form of the equation, and algebra-based physics uses this scalar form.

[@magranin7319]

Flipping Physics I forgot to mention I was in AP Physics C : Electricity and magnetism (did AP Physics C Mechanics last year in junior year) :)

[@anneshepard]

Bazinga

[@miniman251]

Dang, what a great video, I wish I could just watch these videos instead of attending my physics class. Thanks!

[@FlippingPhysics]

Glad to help you learn!

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I have a problem with some phrases, which is "I don't mind, go ahead".

[@user-fp1fu3hs7d]

Sir please give me the link of your video on " electric field due to ring of charge " . there are many videos of diff* prof. On youtube , but your videos are really benefitial for me , i understand the topics. So easily with your videos as compare to others . 😢 And now i am too confused i could not understand this topic 😢 .. Help me !

[@FlippingPhysics]

My assumption is that you are looking for my video "Thin Ring Electric Field". You can find it on this webpage, along with a bunch more useful videos for you. www.flippingphysics.com/ap-physics-c.html#em

[@user-fp1fu3hs7d]

@@FlippingPhysics thank you sooo much sir ☺️

[@duckymomo7935]

Is the subtle implication that large mssses can overcome electrical charge? Is it that suppose Earth and Mars are both partially positive, are they attractive because of gravity while electric charge isn’t strong enough to repel them?

[@carultch]

There is a charge/mass ratio where it is possible in theory for the gravitational force and the electrostatic force to both add up to zero on both objects, but it is rare you will ever encounter this. In fact, we can calculate just how many missing electrons the Earth and Mars would need for this to happen. Assuming the Earth and Mars had the same charge-to-mass ratio, and assuming both are positive, Earth would need a 3.22*10^33 missing electrons, and Mars would need 3.44*10^32 missing electrons, in order for the electric force to completely nullify the gravitational force between them. I don't know where you are getting your information that Earth or Mars is positively charged. The Earth excluding the atmosphere does have a net negative charge, but there is a positively charged atmosphere to accompany it. At the scale of astronomical bodies, electrostatic forces are close to negligible, and gravitational forces govern. At the scale of subatomic particles, the reverse is true.

[@duckymomo7935]

@@carultch it’s hypothetical I never intended to insinuate that the earth is positive

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[@FlippingPhysics]

شكر!

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I consider that a win.

[@gusmore26]

Why is there a 12 and a 21 as subcripts to F vectors in Newton's 3rd Law Force Pairs?

[@FlippingPhysics]

Please see: www.flippingphysics.com/third-law.html

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I didn't get the answer in second question after determining the electric force

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👍🏼

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If more students knew how thorough and clear you explained things you would have millions of subscribers. You need to find a way to get yourself known to all those students left to fend for themselves in mediocre public education systems.

[@FlippingPhysics]

I try. It's not an easy task.

[@donp3635]

I thought you get 1coulomb by 6 x 10 to the 18th power

[@PasajeroDelToro]

You should look into the Biot-Savart law also. It's really the Colomb force in disguise, but over both time and displacement, making it an angular impulse for an electric force. This lady's video on it is pretty good: kzbin.info/www/bejne/gXPLaaSVeaZjkLs

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is this Leonard from big bang

[@FlippingPhysics]

yes

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If I could just be as smart as these 3 guys in my class lol

[@FlippingPhysics]

I think we all feel that way.