Operator Overloading in C++ Example 2 | C++ Tutorial | Mr. Kishore

[@NareshIT]

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[@manalisamani6729]

Is this normal operator overloading is also called binary operator overloading, right? I just want to confirm🙂 plzz sir reply And thanks for this amazing explanation 🙂

[@queensheba693]

Best teacher of c++ I have ever seen. Thank you so much sir 🙏

[@ironsight6186]

Best explanation for + operator overloading on youtube. thank you so much.

[@thayalanthayalan5234]

Eventhough taking more time... repeating and enforceing every point again and again gets into our head open our mind... this is super sir and ur teaching is too good..God bless you... thank you

[@TheShowgun13]

Definitely one of the best teachers of c++ ,all while using a whiteboard!? Much respect to you sir!

[@speedyrax4506]

this lecture is the best because of the board...... everything shown in codeblocks goes over my head.... wish i had you as my teacher...

[@NithyaShree-lv3my]

the most underrated channel on youtube!!great lectures!!

[@kickflicks9683]

Best channel and best lecturer in the KZbin....thank you sir

[@priyasuresh7024]

Great explanation.. thanks a lot sir for free online classes... Even paying classes also not like these classes 🙏🙏🙏🙏🙏👍👍👍👍

[@aumkhant5215]

We can also add two strings using string data type directly. Eg. String s1,s2,s3; s3=s1+s2;

[@sunitakanharkar1542]

we know that operators works only with predefined data types. In C++ this operator overloading concept is defined to work with user-defined data type. Please note that string is predefined data type but objects are user defined and we are adding two objects. So we can't directly add them.

[@aumkhant5215]

@@sunitakanharkar1542 I am telling that we can use string instead of char array in this problem!!

[@fxexile]

@@aumkhant5215 The objective (focus) here is to see how operator overloading works. Most of the programmers already know we can do string addition directly.

[@aumkhant5215]

@@fxexile yes bro I agree with you

[@anjanarajam3459]

you are the only one in the entire youtube who has explained this concept well. Thank you

[@jockergaming6853]

i was struggling to under this concept but your two video made this cystle clear

[@premav4500]

In depth Explanation.....Nice teaching sir

[@dattakhandway7547]

1 number ...........sir........osm.........................

[@prost5514]

thanks a lot, you are perfect as usual, even without computered explanation

[@sathibabumedisetti8786]

Thank you sir. Your explanation is very clear

[@srijanmukherjee3648]

excellent explanation

[@techdyan8500]

you are a good teacher ..sir

[@revathi7623]

Thank u so much sir. Very clear explanation

[@udaykumargadikar7909]

Great explanation 👍👍..

[@kritikasharma3331]

excellent explanation sir!!😁

[@sanjaymahli7772]

Very nicely explained

[@anitajadhav3254]

Thanku sir you are simply great

[@ajaykharat8689]

#include #include #include using namespace std; //operator overloading is using existing operator on user defined datatype(Object,Structure) instead of function or similar to function //existing operator(+,/,*,) operates on pre-define datatype(int, float, char) now using operator overloading existing operator operates on user define datatype (Object, Structure) //Always L.H.S object must be implicit object of same class and R.H.S object must be explicit. This rule is true for both 1. using function 2. using operator overloading. class ajay { int a; public: void getdata() { couta; } void add(ajay a2) { cout

[@karthikeyan-lv6wu]

good but it is simple addition u made it more complicate. matrix addition is best one for + operaor M3 = M1 + M2; where M1, M2 are matrices.......................

[@madhukumars458]

I got the clear cut difference between implicit and explicit objects

[@happysai9119]

A builder started the construction of their two buildings on the same day and completed at different day. Develop an OOP to perform the comparison on their completion date and find the earlier completion date and later completion date by overloading the < and/or > operator. Assume the difference between the two completion dates may be more than a year. Need ans plsss

[@kvkmtech]

Thank you to kishore sir and naresh technologies

[@sahdevchandraswarnakar4549]

You are great,,, Sir

[@suryanshs3079]

Well explained!, Please keep uploading more vedios sir

[@ankushjain3683]

Its awesome...:) clearly understood.

[@riturajanand7133]

sir if I use 2 strcpy() and 1 strcat() then I don't get desired result i.e both string will not get copied

[@behindthescene4406]

How u are using copy fcn... n concatenation fcn

[@desihiphop4998]

exactly bro same problem have u resolved it ???

[@jayanthbharadwaj2041]

Excellent Sir

[@vishalbhardwaj8577]

jatt da ni muqabla sirra teacher

[@chahatvamdev4088]

Amazing Sir

[@manjubpillai447]

Good explanations sir.

[@senthilk8375]

Thank you sir 🙏

[@ГерриПитт]

Thanks for the videos!

[@rakshithasiddaramaiah2617]

Here in operator declaration we're using (Test T2) and while Calling the main fiction the object T1 is not assigned how will the compiler consider T1 as implicit value in operator definition?

[@vsarts1967]

This is a rule.always L.H.S object must be implicit object of same class and R.H.S object must be explicit.(valid for using function ,using operator overloading )

[@erankishashank2839]

Are you aware about "this" pointer?

[@erankishashank2839]

The compiler takes it this way : In add function argument Test add(test t2) : Test t3 = this->st + t2.st; Where "this" is the pointer to the calling object.

[@maheshshirsat9075]

what does implicit and explicit object means??

[@elijaheinstein160]

Great Explanation!

[@indiacomputers9885]

Very nice

[@kattakarthik306]

can we take object in number fucction because t3 is declared in function right

[@nidhirajput810]

Salute sir

[@sachin6873]

good explanation sir

[@shhhahil]

Outstanding

[@dipjoydebnath1963]

Sir can't we define a sum function and call it in main function by t3.sum()? please do reply

[@victorbeemer1873]

But what are you exactly adding in the sum function? Because you haven't passed any argument , you are just calling the function for the object t3. Could you be more specific?

[@rajaranganathan2467]

Super sir.

[@daviskollannoor1442]

numbering the lessons serially will help those wishing to learn systematically... can we look forward to numbered lessons

[@basudevnath7977]

Sir pls demonstrate how to overload new and delete operator

[@venkateshbavirisetty4239]

seriously ur super

[@JagguBhai9580]

why don't we need to overload "="operator in t3=t1+t2; statement

[@the_confusedguy]

assignment operator '=' works for objects.There is no need to to overload '=' operator for objects. It will copy the contents of t1+t2 to t3 data member by member

[@saivaraprasadpasupuletilvn4412]

Can anyone tell me why it is giving error at test t2

[@bhumitrakhadka6633]

Because u dont know to type

[@saivaraprasadpasupuletilvn4412]

@@bhumitrakhadka6633 OMG thankyou for the reply it's very quick and really helpful 😎

[@victorbeemer1873]

@@saivaraprasadpasupuletilvn4412 haha lol

[@programmingworld8946]

Sir i think you have experience of 20 to 25 year of teaching😇😇😇😇😇😇

[@rashidakhatun7437]

Thanks

[@7sinsganiftw877]

why dont he use string data type directly when we have string data type in c?

[@sonu-uq1um]

hello sir can you upload the videos of java

[@azharjamali7485]

give example of adding three or more objects

[@prasadsolleti3870]

when i tried to print the string it is printing only second sting but not first .can anyone please help me

[@techdyan8500]

if you follow his step ..it will definitely works ..please check the code once

[@suhailsama5195]

bro you are using strcpy function in strcat i am doing same

[@viswanathgupta7406]

add function overloading sessions sir

[@rahularora37]

fk maza agya

[@viththaldeshpande875]

Thank you very much sir for your nice explanation!

[@ajaykharat8689]

#include #include #include using namespace std; //operator overloading is using existing operator on user defined datatype(Object,Structure) instead of function. //existing operator(+,/,*,) operates on pre-define datatype(int, float, char) now using operator overloading existing operator operates on user define datatype (Object, Structure). //Always L.H.S object must be implicit object of same class and R.H.S object must be explicit. This rule is true for both 1. using function 2. using operator overloading. class ajay { int a; public: void getdata() { couta; } void operator +(ajay a2) { cout

[@chahatvamdev4088]

Amazing Sir

[@sushilgyawali7880]

Thank you 😊 .sir

[@sharifkhan9170]

you are great sir

[@iniyaviji2796]

Thank u sir

[@edsword9071]

Thanks