A Simple Problem on the Hardest Physics Olympiad (IPhO)

[@gnnvoauekes6320]

I am just shocked how less of physics and chemistry channels are on KZbin as compared to maths keep going!!! Uniqueness is the key to success

[@particleonazock2246]

Math is the universal language, and pursued by a lot of Asians in higher education. Well, that is to say a far higher proportion of Asians will go on to a mathematics-related career than physics or even chemistry.

[@slickvishesh9993]

fi you havent seen a platypus doesnt mean it doesnt exists, there are more no of physics than math

[@imsengky]

I think maybe because of the problems of those are long and the solution as well.

[@harshitagarwal11oct]

Search insp on KZbin its a brilliant channel and u will learn a plenty of new concepts

[@datG0OSE]

physics videos are easy to find, chemistry is basically impossible, sadly

[@thakyou5005]

The best or worst fact you'll learn today is that no matter how good you are at an olympiad, remember someone had to design those problems first.

[@tinafeyalien]

I coulda designed that problem, but solving it not so much

[@thakyou5005]

@@tinafeyalien 🤣👍

[@user-nb6zu3rk4f]

@@tinafeyalienpfp checks out

[@DhairyaKuchhal-ps2xb]

well, people like Jaan kalda get paid for this stuff only

[@AalapShah12297]

​@@tinafeyalienActually the real olympiad question is not shown in this video but if you go look at it, the question is 2 pages long with 5 sub-questions that slowly lead you to the final solution. As a person smart enough to solve that question, I can confirm that I am not smart enough to design that question the way it is presented in the original paper. It's really a great way to design the question so that students can solve it without being confused as to what to assume and what not to assume.

[@akshitkumar9402]

The quality is amazing for such a small creator, love it

[@overthinkingdude3462]

Thank you. It did really take quite some effort. Cheers!

[@esgosar]

What do you think about my content?🤔

[@zz4165]

Yeah such a small creator innit mate

[@ongopom]

@@overthinkingdude3462please come back mate :(

[@yaminocrow168]

For the ones who are curious about the loss of kinetic energy: it happens when the axis of rotation (the edge in contact with the ground) changes. Basically at the instant the axis change there is conservation of angular moment (i.e. the force from the ground plane has no torque about the axis) . So, you can calculate angular moment right before impact with the equation that relates the angular moment of the axis about the center of mass with an arbitrary one and the angular moment right after impact simply by angular moment about the new axis of rotation. Due to the conservation of angular moment you know both of those must have the same result, but the first one is a function of angular velocity before impact and the second one a function of angular velocity after impact. Those velocities are different and by equating the angular moments you can find a constant that relates them. Say we call that constant b. Now we see how this affect kinetic energy: at any given moment it is proportional to the square of the angular velocity of the moment. So from a moment right before impact to a moment right after it is multiplied by our constant b but squared. That b squared must be 0.42 and represents how much of the energy is conserved. 1 - 0.42 = 0.58, that is the 58% that is lost. To verify it all we would need is the moment of inertia of the pencil about its center of mass and about the edges Hope my explanation was understandable, I'm not very good at English :p

[@n.d10yearsago.68]

It’s already unbeatable, my brain couldn’t even comprehend it

[@markkennedy9767]

Couple of questions. Why wouldn't the normal force of the surface (ground) produce a torque around either axis point when the face hits the ground. And wouldn't the moment of inertia about both of these axes be the same by symmetry (they're the same distance from the centre of mass). So If the angular momentum was conserved as we go from one axis to the other, wouldn't angular velocity also be conserved.

[@pawntastic4995]

@@markkennedy9767 Maybe due to the normal force passing through the centre of mass ie axis of rotation so the torque is zero( as theta is 0)

[@ZeroPlayerGame]

​ @markkennedy9767 Hey, I've went and read the solution: ipho.olimpicos.net/pdf/IPhO_1998_S1.pdf so I may be able to help. The angular momentum is conserved *around the edge of an impact* specifically - the solution assumes that an impact force is applied only along the impact edge, which is a reasonable assumption (you can inset the faces of the pencil by a tiny amount, and you wouldn't expect the behaviour to change). Moreover we know the directions of the center of mass right before and right after the impact. We find that the direction before contributes an extra 1/2 M R^2 w_before angular momentum, but the direction after contributes M R^2 w_after, since the angle between velocity and direction to center changed from 30deg to 90deg. Knowing that moment of inertia of a hexagonal prism is 5/12 M R^2 (which you can calculate by integration), we then equate 11/12 M R^2 w_before with 17/12 M R^2 w_after, obtaining that angular velocity changes by a factor of 11/17. (Note that the first angular velocity is about the "old" edge and the new one is about the "new" edge!) Then, since the situation is symmetric, we find that kinetic energy can be expressed as rotational kinetic energy about the edge (1/2 17/12 M R^2 w^2, but that doesn't matter), therefore kinetic energy change is a square of angular velocity change.

[@IntegralKing]

holy handwave, batman. that 58% is the most important part of this calculation but it's "left as an exercise to the reader" haha

[@AttilaAsztalos]

...also, that final equation is only simple to solve if one happens to still remember that cos (a - b) = cos a * cos b + sin a * sin b...

[@laeroengr1693]

This trig identity is considered common knowledge even for a lot of regular high school students in the USA, which doesn't have the hardest math education. It's hard for students representing their countries at the IPhO to not remember this.@@AttilaAsztalos

[@skimmelsvamp9531]

@@AttilaAsztalos That’s literally one of the most trivial trig identities…

[@AttilaAsztalos]

@@skimmelsvamp9531 sure is - for a physics olympiad contestant. Not so much for the average mathematically-inclined KZbin viewer who might reasonable be able to follow/tackle simple maths and reasoning but last saw "trivial trig identities" years and years ago.

[@HaidarHavana1998]

@@AttilaAsztalos bruh I am not physics olympiad contestant but learned it in high school

[@dontmesswiththeriddim2699]

Damn, KZbin JUST had it in mind to recommend this channel to me, and your animations and awesome explanations got me hooked. Sad there are only 5 videos, but I can tell it requires a lot of work, and you may not be getting the traction you need and deserve. Gonna do my part and spread these "limited-edition" videos to more of my nerdy friends for sure. These are seriously amazing!

[@matheuspauloferreira8751]

After looking at the vid and before looking at the comments, I thought that you had at least 100k subscribers. You will grow a lot in the future, your content is so good

[@overthinkingdude3462]

Wow, thank you! Maybe someday :)

[@creativecarveciteclimb5684]

Still 6.2k 😢

[@yatogami1783]

7.4k

[@josephbentley-ross4141]

Criminal how the algorithm works in highlighting crap content and not highlighting actual content like this to viewers.

[@redrob6026]

​@@yatogami1783 8.4k

[@petersmythe6462]

Note that there will usually be some sliding if coefficient of friction isn't literally infinite. Also it can spontaneously transition to a runaway-accelerating hopping gate above a 24-27 degree angle, and maintain such a gate down to 14 degrees.

[@petersmythe6462]

This means that the 14-27 degree region is bistable, or rather, has one stable state (rolling normally at a speed under 166 mm/s) and one unstable state (accelerating to an infinite speed).

[@INSP_NITIN]

Great video and explanation !!! Many more success to you .

[@overthinkingdude3462]

Thanks a lot!

[@masoomladka8017]

Guruji 🤩🥴

[@shashwatniranjan5263]

Sir aap yaha 🥳

[@sat20y]

Pranam Sir 🙏🙏

[@arijitghosh5711]

Are sor orz 🙏🙏

[@himeshviews7622]

Great animations. I believe it will help me a lot in learning physics for Olympiads.

[@overthinkingdude3462]

Glad to hear that!

[@florincoter1988]

Lagrange wrote the whole mechanics without a single image. Physics speaks math, not photos.

[@chonchjohnch]

@@florincoter1988shut up

[@PARADOX1001-k3h]

Proffesional video analysis!!! Its a wonder that you have not yet reached 100 k subs! You definetly deserve more

[@ModernWizardx1]

just watched it now pretty good tbh

[@NeatNit]

Thank you, good video! Did you ever make the video to explain how to get the 58% figure at 8:20?

[@bobogirraffe5223]

Didn’t find a single other video outside your channel solving an IPHO question. Thanks

[@DangDatsCrazy]

4:26 Due to conservation of energy, with perfectly elastic collisions, the pencil should never stop rolling down no matter the angle if the pushing force is enough to tip it over once.

[@untruegamer8079]

not if there's friction, which is needed for it to roll in the first place.

[@DangDatsCrazy]

@@untruegamer8079 I do understand friction prevents sliding but in a ideal scenario it should not consume energy from a rolling non-sliding pen. Just like how ground to rubber friction helps the a wheel roll and does not slow it down (again, in an ideal scenario).

[@bscutajar]

@@untruegamer8079 Friction does not count as an energy loss unless the pencil is sliding. Which it isn't. Energy equals force times distance, without any distance moved you don't have energy loss.

[@bscutajar]

You are exactly right, but the guy doing the video just pulls 58% out of his ass with no justification. The pencil should theoretically keep rolling even on a flat surface.

[@ZeroPlayerGame]

Well, wood's not elastic.

[@soumakbhattacharjee3866]

how did we get the 58% energy loss estimate? wonderful video! Unfortunately, the link to question/solution is not working :(.

[@ahmedsaadsabit1749]

This is so cooool, I seriously encourage you to do more tough IPHO problems, you are really good at it, well encouraged!

[@overthinkingdude3462]

Thank you! To tell you a secret, I am a IPhO medalist XD

[@ahmedsaadsabit1749]

@@overthinkingdude3462that's more than fantastic! Felt so nice to hear that! Keep it up man, I love the IPHO animations.

[@himeshviews7622]

@@overthinkingdude3462 phenomenol, I would love to interact with the people who have reached the milestone which is my inspiration.

[@mannpatel3239]

@@overthinkingdude3462 Can you please tel how to prepae? My goal is not till IPHO but till INPHO(conducted in india for selection in camp from where team is decided). It is basically more maths than physics in it.

[@namangoyal1297]

I saw a similar question in SS Krotov, but in that question the wedge was at an inclination α with horizontal, and the hexagonal pencil made an angle φ from the plane of the incline. It asked the value of φ for which the pencil just stays in equilibrium. That question was interesting too

[@ninja-nd1wm]

Yesssss!!!!

[@PieVio]

That was the problem which brought me here!

[@Inndjkaawed2922]

Great video.. dude. You have no idea how awesome a job you have done. How does pencil lose 58% of KE... Can you explain that part?

[@AalapShah12297]

I didn't watch the full video but found the problem quite intriguing after the point where he says it's not 30°. So I searched for 1998 physics olympiad and found the question paper. And I must say it's designed so nicely that the 5 sub-questions subtly nudge you towards the final solution. I haven't solved many physics problems for 5-7 years now, but I could solve it in a couple of hours because of all the sub-questions guiding me in the right direction. It felt very satisfying to solve it myself and I must say I wouldn't have been able to do it if the questions weren't framed so beautifully.

[@visweshshukla]

Dude please continue these videos. These are sooo good

[@overthinkingdude3462]

That's the plan! Just had a pneumonia and my video production got delayed. The next video is almost complete.

[@godfxth4104]

The most underrated Physics Channel on KZbin. You deserve more brother. De

[@overthinkingdude3462]

Glad you think so! I only have 4 videos now so it makes sense. Each video takes a lot of effort :)

[@godfxth4104]

@@overthinkingdude3462 I'm personally gonna publicise it.

[@overthinkingdude3462]

@@godfxth4104 Thank you, I appreciate it!

[@southerncross4956]

I took the click bait designed to capture exceptional and brilliant mind’s attention. At the 9:23 mark of this fascinating video I awoke from a 90 second nap and thought. “This is rather interesting but I must have coffee to continue”. I have a rule (well one of very many) if I start watching a video and it has any merit at all I am obligated to hit the like button if by chance I die before coming back to it (I am a man who takes rules and duty very seriously and dying is on the table i’m 78). Just above the like button was the channel’s name “Overthinking Dude”. I laughed thinking well he does admit to this weakness as I admit to mine, For some very odd reason I believe what I think or write is worth the time to read (but most likely not) but you have gotten this far and I salute you. Your coffee is getting cold.

[@amrit5]

Overclarified by the overthinking dude. You re an amazing explainer

[@jonathandawson3091]

Wait... where did 58% come from?

[@aegiswings]

I had the same question. He hand waved over the most important part.

[@niveliss1215]

180/pi, probably

[@coshy2748]

I enjoyed the presentation. Good to hear the physics reasoning and see the mathematical analysis. Combined, they provide a reasonable explanation of what we experience. Unfortunately, the problem and solution links don't work for me.

[@blue.jersey2482]

This is so awesome, your explanation is truly easy to grasp. Would love to see how you found out how much energy was lost each time.

[@Jasmine12348]

dude don't Stop making videos about ipho question. You're amazing... I love your video thanks dude ❤!!!

[@5eurosenelsuelo]

10:30 I don't understand where the 58% comes from. Does anyone know? Still, nice video.

[@hiHi-ee6zh]

Man, the video is just MIND BLOWING. Every steps are so deeply explained.

[@bscutajar]

If it's so well explained please provide the timestamp for the explanation on the 58% mentioned at 10:06

[@OleksandraKhrul]

10:30 I don't quite understand why exactly 58% is lost

[@yashagrawal8592]

Great Quality :) May u reach to millions !!

[@overthinkingdude3462]

Thank you! I hope so

[@alexanderstohr4198]

More reasons for why this first level of consideration is incomplete: * the materials in the game are plastic and elastic, so a pencil tipping over might see a noticeable return of energy. * the pencil not only has forward driving momentum, but it also has a rotational momentum (and this can be very strong). so in effect it can be the case that it will only shortly tip with its edges to the surface until it "floats" in air for the next edged to find contact. in other words, it does not necessarily fall down fast enough to just have at all any sort of flat contact with the surface. also air trapped might help it to get lifted quickly to such a "hovered" position. and guess what? a hovered motion will not have any sort (or at least much) of lifting up energy included - that would be able to stop a pencil from rotation. so the overall run length might be much increased. rationale: there might be much more in play that impacts on a real world setup. dont trust things to behave in a way the still simple formula above would predict.

[@azuolassiuk4838]

This is amazing! Wish you would solve some more IPho or other difficult problems :)))

[@overthinkingdude3462]

Sure, for starters, I'm planning to work on one more IPhO problem (will take some time)!

[@notforall318]

@@overthinkingdude3462 What medal u won in IPho?

[@anshlohani]

I remember trying to solve this problem :) This brings back memories! Nice

[@blazingazong]

We did similar problems in my first year of engineering physics course. If it’s tilted where its center of mass is past any of its points of contact, then it tips- I think

[@namehidden7456]

Sir please make a video on the mathematical derivations concerned with the amount of energies lost. One of the best videos I've watched so far!

[@vishrutmittal257]

beauty of physics cannot be ignored

[@petersmythe6462]

There's a bit of an issue here. We are assuming that thehexagonal pencil is "walking" when rolling. That is, there is constant contact with the ground, and briefly there are two separate points of contact once every circumradius of the pencil. However, this will only be the case for a pencil that can make that sharp of an arc. That is, one where the vertical launch speed of the pencil can be cancelled within the time it takes to roll. Otherwise it will transition to either a very efficient running gate, or a less efficient bchaotic hopping/bouncing gate. The vertical launch speed of a pencil in a walking gate must be enough to reach 0 velocity at an apex of 0.134 circumradii under gravity within half a circumradius of horizontal travel. If we make the slightly wrong but helpful approximation that way the transition point the cycloidal arc is actually parabolic, for a 3.5mm radius, we get a time to apex of slightly under 9.8 milliseconds. This caps the step frequency of our walking gate at about 1 step per 19.6 ms, or a speed of 3.5 mm per 19.6 ms, or 178.9 mm/s. However, remembering that our steps are in fact cycloids and not parabolas, we end up with higher vertical velocity on every launch than necessary. This means that we will get too high an apex once our vertical speed ever exceeds approximately 96 mm/s. Which will actually happen at a speed of 166.3 mm/s. What we see is that we will transition to a running or hopping gate at somewhere around this speed. Basically once we reach about ~950 rpm it will either jump around like crazy or roll on the corners while being fully airborne at least some of the time. Which will actually occur is another question.

[@petersmythe6462]

It turns out that the efficient running gate is unstable and will always transition to the chaotic hopping gate. This will nonetheless lead to runaway acceleration above about a 14 degree angle.

[@iamnotcaptainyt4953]

Man everyone's getting recommended after he stopped uploading for 3 years.Its so random

[@doggyman4503]

well, i found 3b1b's brother

[@overthinkingdude3462]

Thank you! I use the animation engine that he has developed. It's true that I'm quite inspired by his work!

[@renuk8560]

​@@overthinkingdude3462will you return to making videos?

[@rishinaik4326]

I actually saw this question a week or two and now I have the solution . Thank You , please keep this coming

[@overthinkingdude3462]

That's quite a coincidence, where did you see it?

[@rishinaik4326]

@@overthinkingdude3462 In the 1998 Physics Olympiad paper . I was glancing through it and saw this question. Though it was out of my capacity to solve it.

[@overthinkingdude3462]

@@rishinaik4326 Don't be scared. Try to imagine the problem in every detail you can. Try applying some common sense. And after that apply some physics laws. That's generally how I solve all the problems. If you really think you are not at the level you can solve this problem, you can start with something easier such as Irodov.

[@rishinaik4326]

@@overthinkingdude3462 Thank You I do solve Irodov seldomly . Can you suggest a progression I can follow to be able to solve IPho level problems.

[@overthinkingdude3462]

@@rishinaik4326 Back in high school I solved all Irodov mechanics and thermodynamics problems and would have solved electromagnetism if I had the time. Some people suggest Krotov instead of Irodov, but personally, I didn't even know it existed. Basically, after solving Irodov you should be able to progress to past IPhO problems. Start with the older ones since they are easier. And you can probably pick up some theory along the way. :)

[@shaneahmad2598]

Why the energy lost in collision is 58%??

[@mitchellcouchman1444]

He says its somewhere else but I can't find it, its effectively the "bounce" as the pencil hits the table on the flat side which comes down to the materials of the pencil

[@cockroach7237]

I want to know how to find the exact amount of energy (In this case 58%) that is lost when the pencil collides with the surface while rolling down.

[@deinauge7894]

i tried to solve before watching, and ended up thinking only about how to get the answer to this energy loss without calculating the rotational inertia of the hexagonal shape around its center and its edge. To somehow get the energy loss on impact. I disn't get there in a few minutes and watched to find out. And then he just gives a number 😢

[@SalaheerNazaar]

Please upload more videos! Subscribed to your channel from 3 devices already,mate! Consistency is key!!!

[@IcecalGamer]

Home-boy here pulled a gangsta 58 out of the back pocket and managed to smuggle in a calculator at an Olympiad. 10:30 . 17:13 . Show your work or get out. Also, solution "assumes" stuff at the end like Friction, drag, density. Give solution considering those variables or can I just "easily use a calculator" / LLM and send it?

[@danielmontejo790]

Very good content for so a small channel !!! , keep going and eventualy wont be small

[@overthinkingdude3462]

Thanks, I hope so too!

[@tinafeyalien]

The most difficult and crucial part, the 58% KE loss, is not explained and the solution link is a 404. Fail.

[@chonchjohnch]

Oh wow I didn’t notice, thanks for pointing that out for us

[@KenesuEXE]

Love this video! Question though, where did you get that 58% loss?

[@anmolagrawal.9373]

how did u calculate the 58% thing???

[@bscutajar]

he pulled it out of his ass

[@hinth_the_blessings.]

Very good quality... InsAllah,You can go further more.Doing such a good job.Love from Bangladesh.

[@voyageintostars]

Amazing vid. I wonder tho... how the idea of rotational kinetic energy would affect this entire calculation. I reckon KE you give to the centre of mass is not just doing work to overcome the peak of potential energy and energy loss during a hit. But also to give the pencil it's rotational kinetic energy.!

[@amarsing982]

Brother love from India I am very amazed to see this that's the reason why I love physics ❤ Thanks for making such a video

[@abhiyanampally3764]

It's totally OK to include mathematical analysis in the videos too.

[@Khadijah-rp4os]

It's a really good question...me being in high school have learnt the concept of toppling in chapters like centre of mass and rotational dynamics..which were arguably helpful here

[@danianzaripov8822]

I want to see how you calculated that the pencil lost that procent of kinetic energy while he's falling down from his highest point, make the full-of-math video, please!!! I really like your video, thank you very much!

[@sorenchoi9511]

Roughly 58% is because the angular momentum is dependent on the pivot. The pivot changes when the next edge hits the table, so we "lose" a bunch of angular momentum. I think.

[@BotConnorrr]

Such a high-quality video and explanation!

[@walterbrown8694]

Reminds me of one of my undergrad mechanical engineering courses about 60 years ago in kinetics and kinematics.

[@Firstname..Lastname]

Before continuing the video I wanna write my initial guess of “anything greater than 30 degrees”. A hexagonal pencil has interior angles of 60 degrees on each angle. The pencil would perfectly balance on an edge at the center point of the angle, which is 30 degrees. At greater than 30 degrees, the pencil will no longer be stable, and fall towards the steep side. This will result in the pencil being unstable balancing on the next edge, causing it to fall to the side again. This would make the pencil role.

[@Anupamchess]

I am a neet aspirant even tho I can understand by your simple explanation.... And I did completed the rotational motion chapter so I was connecting the chapter with the video.. Thank you❤

[@fatchulanjaza2433]

Overthinking dude? Perfect name for me. Subscribed.

[@TheAlison1456]

The first thing I thought when I saw this thumbnail is, the pencil is not perfectly hexagonal.

[@redpug5042]

where did the 58% loss calculation come from?

[@projekcja]

The calculation was not included in the video, but it is shown in the links. If you follow the link for "The solution" you will get a 404 error, but if you google the filename 1998_Iceland_p1Sol.pdf , you can see the full calculation. The video just skips it and pretends to have shown the full solution to the problem. Inattentive listeners believe it. 58% is just an approximation, the exact value is 168/289, which can give you a clue about to the complexity of the problem.

[@markkennedy9767]

Nice problem. Still trying to figure out where the 58% value comes from.

[@sergiojasierzurbanoperez4555]

We need more of this and less of the dumb stuff we get suggest from KZbin. Great analysis!

[@wmfwoodworking]

At the 3:00 when the center of gravity is directly above point O, depending on the static friction, wouldn't the pencil start to slide? I know this is not the question being asked or the point of the video, I just thought it was an interesting argument that could be made for having a lower desk angle to maintain rolling if the rolling was initiated by external force.

[@damirskrjanec]

The pencil colides with the pad in each step. If the colision is elastic, no energy is lost. That means, 58% is some serious guesswork. Also, the mass distribution doesn't matter, contrary to the claim at the end of the video, as long as mass is not movable and the center of gravity stays the same.

[@sphynx_owner8224]

in a perfectly rigid environment with 0 friction, to my undesrtanding, even on a 0 slope surface the hexagon will continue rolling, as its not losing any energy to heat, and just bounces back as high as was required to initialize the spin. i think delving into more detail as for the friction model would make sense. just saying theres 58% reduction on impacte assums the environment is not perfect, in which i would like to see where it is stated in the question you are answering.

[@-ZH]

17:36 Well it says there is static friction, so it’s not a 0 friction environment.

[@bscutajar]

Friction does not cause the pencil to lose energy unless it is sliding.

[@bscutajar]

Friction does not make the pencil lose energy unless it is sliding. Energy = Force * Distance. No distance sliding means no energy is lost due to friction.

[@sphynx_owner8224]

static friction still needs to be explicitly defined by the question, i am asking for the definition of friction conditions, where static friction would be one of those.@@-ZH

[@yashrajsingh8725]

Seriously your curiosity is just like anything

[@CalvinChristYOLO]

Amazing video! I'd love to understand how the recursion equation is solved by hand as I'm guessing graphing simulators wouldn't have been allowed at the Olympiad? Thanks!

[@bogdanbusui5249]

At 16:30, if Kmin is needed to keep on rolling, then how are the red values achieving that if the initial value is less than Kmin?

[@ashishawasthi4350]

Love it ❤thanx dear Do u use Manim for animation ?

[@Jasmine12348]

Please start posting again!!!

[@razvanirina5971]

Can you update the link in the description, it seems to be broken

[@SAURYASHRESTHA-eg5ze]

Great Video! Does someone know what tool os being used for Animation?

[@Kapomafioso]

Except the most handwavy assumption - the 58% lost in each bump - was totally glossed over. I don't even know how I'd approach figuring that out, I would probably give the answer in terms of some constants like the coefficient of restitution kind of analolgue and maybe make an estimate based on a few "what if" values.

[@sincity147]

Off course make the math for that, that’s why we’re here, also to be indulged by Mathematics equations, please 🙏

[@sudarshan1793]

i done it by concept of toppling and angle of repose

[@abcmedia5049]

Where did the number 58% come from?

[@notweewee]

really interesting approach to solve the problem, it's a great video. ♥️

[@digxx]

Not sure I understand you right, but don't we need to have both inequalities theta > 6.58° K_i > K_min (K_i = initial kinetic energy) for the pencil to at least start rolling and keep rolling?

[@jiaam3269]

Where have you gone dude? Come back!

[@abhiyanampally3764]

How did u get 58%??

[@FuSiionCraft]

There's something no one took into account. What material is he pencil made from ? And the table ? Depending on that, the pencil will roll before or after it's tipping point. So this exercice is void. Thanks to physics, you can save on brain power 👌🏻

[@yeetyeet7312]

Hey awesome video man also could u tell me books or anything that u did to become a ipho medalist it would really help me a lot

[@overthinkingdude3462]

I personally solved all Irodov mechanics and thermodynamics problems and solved about 20 years of prior IPhO and 10 years of APhO problems. If I had time I would have solved electromagnetism from the Irodov. Many people also recommend Krotov instead of Irodov but personally I cannot comment on it since I didn't even know Krotov existed back then :)

[@januargumelar3495]

A great content from a great channel

[@Shan17630]

The animation quality is very good.

[@transtemporal_artist]

Thank you for the video.. i was just going through some ipho papers and i saw the same problem but i didn't tried because i was developing my problems solving skills still developing .... But this video was great it was not very tough just didn't understood how 58% energy got lost after the impact🤔🤔.... Thank you anyways and please upload more 🙏

[@aniketsen6845]

Amazing one🖤

[@overthinkingdude3462]

Thanks 🔥

[@sambhavmishra5423]

Hi bhaiya, Nice to see you here !!

[@aniketsen6845]

@Sambhav 😊🔥👍🏻

[@shivprateek2740]

subbed you deserve much more love

[@gamingzeraora443]

To find the minimum angle, we must equate the torque by friction with the torque by gravity

[@krishgarg2806]

firction is a variable force so its not really a way to get the critical angle. the more precise one is, normal force will shift to the tipping vertex, so friction and normal will be about that vertex, and their torque will be zero about the vertex, so only torque acting would be gravity.

[@kuzikaco7039]

Thank god I found this channel

[@Bonfra04]

great video! what software/library did you use for the animations?

[@xenmaifirebringer552]

Probably Manim, the maths animation engine developed by 3B1B

[@sheershsen2380]

Great content. Keep it going!

[@overthinkingdude3462]

Thank you! Will do!

[@sadnanjuhib]

​@@overthinkingdude3462well you didn't

[@rolandfebrian6711]

8:51 Can somebody explain, why the kinetic energy is lost by 58%?

[@_.Infinity._]

Amazing video my dude. I want more from you.

[@d1am0nd777]

I cant calculate this, but have an idea. You dont take into account the force of friction. In my opinion, depends on properties of pencil and table material, when pencil will slide, it slide with acceleration, and sooner or later it start rolling, when velocity would reach critical point. It colud or couldnt happen btw, depends on material.

[@jatinsharma4476]

Quality is amazing, just a thing- don't relly on simulation observations.. try using the things a student can use whilst in an exam, use simulation to depict already proven things by calculating. For example - You said- for smaller angles like 5° you can see it stops.. well not without a simulation I can't see just like that.

[@crumbopulis]

In other words, to stop the pencil from rolling from a slight impulse. We made it a triangle.

[@Retrotive]

I hope you make more contents!!! I like your videos.