Oxford University Admission Test Tricks !✍️🖋️📘💙

[@hafeezrehman8692]

Excellent 👍 method

[@superacademy247]

Thanks for the feedback! 🙏🔥I'm glad you found it helpful! 💯💕😎👏

[@Sergei_Goncharov]

It is better to multiply both numerator and denominator immediately by √3+√2 and then, without actual multiplying numerator, cancel both sides, because the denominator will result in previous numerator. Also you don't need to divide x^8/x, because x^7 = (x^2*x)^2*x - numbers (coefficients) will be smaller.

[@dinodruding5911]

Why not use Pascal's triangle and binomial expansion?

[@kenhoo3702]

Very easy , (+√12 / -√12 )^7 Do it 7 times .

[@davidseed2939]

x^6=x^4.x^2 x^7=x^6.x ist that easier

[@nigellbutlerrr2638]

All of these types of exercises are quite worthless in the real world. Ask any engineer or scientist. It is really a vanity.

[@dinodruding5911]

What's your point? Perhaps some people simply enjoy algebra problems for their own sake.