How to calculate LTE Data rate Speed ?| Throughput calculation in LTE

How to calculate LTE Data rate Speed ?| Throughput calculation in LTE
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[@israrahmad96]

When I was learning this in my training it was looking very boring and complicated. Your way of teaching is so easy and simple... Thanks a lot sir...

[@AnandTechnoSolutions]

Thanks Israr..Thanks for your complement..please comment if i am missing anything and I will try to improve that area...also polease suggest improveplease suggest any new topic

[@israrahmad96]

LTE/UMTS/GSM interoperability means selction/reselction and Handover priorities and criterias will be a very useful lecture . Your way of teaching is so simple and easy

[@AnandTechnoSolutions]

Sure i will try to cover this section

[@sukumarane2302]

Explained clearly .Any one can follow easily .nice ! Wonderful ! Expecting more videos from you . Thank you ,sir 👍👍 Expecting similar videos for data rate calculations for 2g,3g and 5 G

[@AnandTechnoSolutions]

Thanks...5g calculation is uploaded

[@malakondaiah1512]

Magnificent class ji

[@balkrishnasrivastava9258]

Super sir, keep continuing to spread knowledge to us Thanks

[@AnandTechnoSolutions]

Thanks man

[@jaythakur2137]

400*25% != 300. please correct it. As 25% resources used for signalling. So you should be multiplying with remaining once. means 400*75% = 300. I hope this help.

[@AnandTechnoSolutions]

Thanks Jay .. for your suggestioj

[@rajendra259]

Wonderful Explanation, Really appreciate you. A person with a basic knowledge can also understand easily from your videos. Thank you

[@rbm004]

Excellent, simple and to the point!

[@AnandTechnoSolutions]

Thanks

[@ApricityTS]

This is best and simple explanation of LTE-FS

[@AnandTechnoSolutions]

Thanks..

[@pranshudwivedi2724]

bahut hi badhiya samjhaya aapne..

[@AnandTechnoSolutions]

Thnaks Bro....

[@SharpKnife523]

Great. very easy explanation.

[@aquibali772]

Thanks for Video, But I think 100800 bits/1ms !=100.8 Mbps, when we used right convergence of Bits to Mega bits than need to divide by 1024, By using this data rate will be 96.13 Mbps, & for 4x4 Mimo It will be 288.39 effective data rate not 302 Mbps.

[@AnandTechnoSolutions]

Yes correct...its only for understanding purpose.....so taken just approx value

[@KidsNehaTalks]

@@AnandTechnoSolutions 100800 bits/1ms =100800*1000 bits/s (here suppose to convert 1ms to sec,so 1ms=0.001=10^-3 sec) 100.8 *10^6 bits/sec =100.8Mbps

[@lakshanrathnakumara9158]

Thank you very much

[@AnandTechnoSolutions]

Thanks

[@ssasidhar75]

Excellent explanation

[@AnandTechnoSolutions]

Thanks

[@PankajSharma-pe2ws]

Wow, Very nicely Explained...Thanks buddy

[@Koimith]

You explanation was excellent, thank you. 👍

[@AnandTechnoSolutions]

Thanks

[@muhudiinyusuf6900]

thanks so much, really you provided a very good information for calculation of PRB.

[@veerojumanasa7948]

thnks for clear explanation

[@AnandTechnoSolutions]

Thanks manasa

[@mayankchandla1502]

Thanks for the video. Which specification provides the no. of RBs available for each bandwidth ?

[@gabrieldelacruz7100]

Mayank Chandla TS 36.211

[@moulanamohammadh6894]

Brother excellent.

[@AnandTechnoSolutions]

Thanks Bro

[@klinsmannhotspur9792]

Very good explanation

[@AnandTechnoSolutions]

Thanks klinsmann

[@klinsmannhotspur9792]

Could you do a video on how OFDMA works with MIMO in LTE?

[@AnandTechnoSolutions]

@@klinsmannhotspur9792 sure..i will try

[@klinsmannhotspur9792]

In particular for DL after IFFT is applied to the subcarrier signals.. thanks

[@3100637]

Thanks a lot for your explanantion!!!

[@AnandTechnoSolutions]

Thanks Bro

[@varakumarisamudrala9763]

excellent

[@rajendrapdsharma1120]

Excellent

[@moulanamohammadh6894]

Excellent explanation bhai

[@swarnban8634]

Overheads will be added bcoz headers from upper layers will be added, Guard band will be there thats why.

[@Daily_Cric]

excellent bro....👍

[@panditram9046]

Thanks for clearly explained bro...........

[@AnandTechnoSolutions]

Thanks so much

[@gaurishkadam3839]

Hello, at 8:05 why do you multiply by 2? I understand that there are 2 slots in a subframe. But 20MHz has only 100 RB. 100 RB = 100 * (12 subcarriers X 7 symbols). How can you multiply again by 2 here? 1 RB = 1 slot (12 SC X 7 symbols). Can someone clear my doubt?

[@MITHUNTV]

Network always allocates UE 1 subframe in DL which is called a TTI. Since there are 2 SFs in a TTI we have to multiply by 2.

[@gaurishkadam3839]

@@MITHUNTV Right. It makes more sense to me, if further down the video we convert 100 * (12 x 7) per 0.5ms, to 100 * (12 * 7) * 2 per 1ms

[@jeff830103]

thank you help me a lot!

[@SheysonSanchezSuarez]

excellent thanks

[@AnandTechnoSolutions]

Thanks

[@tanjirahmed6643]

very nice....

[@AnandTechnoSolutions]

Thanks

[@kamalhassanwarsi3799]

Great

[@AnandTechnoSolutions]

thanks

[@klinsmannhotspur9792]

Hi Anand, could I ask you a question? In 4G LTE, the baseband signal is actually at low frequency(a few khz?), but how come it is that low? Say for example at DL, the through put is around 300Mbps( for 20MHz , 64QAM and 4x4 MIMO), meaning that 300Mbps will arrive at the mobile receiver end(assume only 1 user is using all the available RB or 1200 sub carriers), and after all the require process, the baseband signal(bits 0 1) is retrieved but at very low frequency. So now for 1 sec, 300Mbps is waiting the mobile to process, but if the baseband signal is slow, it will take a long time to just proceed that 1 sec of information. How could that possible? Could you please briefly answer my question? Many thanks.

[@AnandTechnoSolutions]

as per my understanding..The use of "high" frequencies has nothing to do with energy. The main purpose of using a "carrier" is to transmit multiple signals of smaller bandwidth over a channel that has much larger bandwidth. though the fact that higher frequencies have shorter wavelengths and therefore can be transmitted more effectively with short antennas is also important for many applications.In Modulation and antenna propagation, the adsorption of the wave makes you to need more energy to transmit.

[@debasisbadal1]

Hello Sir, Can you come with a video where LTE throughput and debugging is explained involving all layers . ?

[@vikramgarg3134]

super explanation

[@AnandTechnoSolutions]

Thanks

[@avisek0101]

Overheading is done in PDCP using ROHC

[@gototcm]

Great explanation. Where did you get for example, 20 MHz=100 RBs?

[@AnandTechnoSolutions]

It is for your understanding...same way you can calculate for 10 MHz or 15 Mhz

[@evensondlovu4982]

1RE corresponds to 15kHz channel and in 1RB there are 12 such channels so 1RB corresponds to 180kHz. In a 20MHz channel, 2MHz is used as guard band leaving 18MHz for transmissions. This therefore means the number of RBs in 20MHz (Effectively 18MHz) = 18MHz/180kHz = 18000000/180000 =100 I hope you got it.

[@AnandTechnoSolutions]

Yes..got it

[@evensondlovu4982]

I am sure you knew this Anand, your video is great. I was just explaining to Tom M.

[@gototcm]

Thanks. Now I understand.

[@Rakeshkumar-kp2lb]

Sir please send the brief throughput calculation of 2G and 3G

[@kumarsunder8750]

super lecture

[@AnandTechnoSolutions]

Thanks Kumar

[@durgeshpal1439]

Create calculation for peak data rate..

[@Lawrencearjun]

THANK U

[@rishika.m9784]

1frame= 1prb??

[@Heavygunner1]

Why 32 QAM not used

[@sunnyteki]

as the system is binary[ real n imaginary]. in a quadrant of space, only 2 power x bits can only be represented using real & imaginary fields.

[@hordevran]

Why you say 0 as gero? :D

[@AnandTechnoSolutions]

My engish pronunciation is not clear🤔 I am working on This and i will come with new quality video......Thanks...Please SUBSCRIBE if it is helpful...

[@hordevran]

No problem, your english is good and video brilliant, just this one word was funny and at the beginning i thought it has some special secret meaning :D.

[@AnandTechnoSolutions]

Thanks BRO 😃

[@goran2858]

excuse me can you share your email ??

[@AnandTechnoSolutions]

Gautamanandsharma09@gmail

[@goran2858]

@@AnandTechnoSolutions thank you so much

[@goran2858]

sorry but i couldn't send an email to this email

[@AnandTechnoSolutions]

@@goran2858 [e-mail]

[@goodeditz1606]

@@AnandTechnoSolutions sir, pl make video on How many UE can connect to LTE cell ?