Particle on a circular track: speed required for a full loop

[@atila8623]

Love your content .thanks for sharing ❤

[@MissPiggyM976]

Curious and interesting !

[@shlokdave6360]

Incidentally, I was working on a very similar problem. In that question a starting velocity of sqrt(22Rg/5) (

[@DrBenYelverton]

Ah, OK! I get sin⁻¹(4/5) for that first part using the equation derived in the video. From there on you can resolve the velocity into components and treat it as a projectile. Next video is already recorded and should be posted tomorrow.

[@shlokdave6360]

@@DrBenYelverton Yes sir! Same approach, same answers! Thanks for verifying them for me.

[@peterpoli2839]

Could have went straight to the condition of 0 contact force at the top of the loop (when theta = 0).

[@DrBenYelverton]

Indeed, I've taken that shortcut in the follow-up video I mentioned, but wanted to justify mathematically why that works at least once!

[@Thomas-d4v7k]

I don't see how there is a normal reaction when there is no force acting against the surface

[@DrBenYelverton]

There is a force acting on the surface, equal and opposite to N by Newton's third law! We don't usually bother to draw this on the diagram as we only care about the forces on the particle.