Inverse Hyperbolic Functions - Derivatives

[@Goblinlorde]

Mr Patrick JMT you sir are the biggest legend of all legends. I hope you sleep easy every night thinking how much you have helped students get through university/college. Take care!

[@chelsijones5970]

I don't understand why teachers can't just make it this easy.

[@jessicagalli108]

I pay to go to school and have a professor "teach" me this - when in fact 100% of my calculus knowledge comes from Patrick's videos.... hmmmm...

[@manishasaini2324]

So true! ;)

[@MarkMcDaniel]

Some instructors just can't teach, it's sad. I'm thankful my Calc 1 instructor last semester was excellent. Going my Calc 2 instructor this next semester is decent.

[@carlykiller]

8:10 that sqrt(x^2) is suppose to be sqrt(-x^2)

[@JesusMartinez-zu3xl]

I know this video is pretty old but you made this topic easy to understand!

[@AsKitchenYT]

Who's watching this on Sept. 12, 2018? Hi! I just wanted you to know that your videos helped me a lot to understand things that I don't when it comes to calculus! Thank you. You're awesome!

[@patrickjmt]

no one, yet... it is only sept. 11

[@AsKitchenYT]

@@patrickjmt Ohhh. I'm from Philippines. I think that's why. 🤔

[@karuneshmatadin377]

shoot 1 day late

[@hoojks]

i LOVE YOU. With all the calc2 proffessors @ my college having a rate my proffessor rating of 1.5 below and sucking. you will help me pass my class

[@made2320]

I was wondering when you were simplifying at the the end (8:12), you simplified the square root of x^2 to x, but wouldn't it be the absolute value of x? That wouldn't be the same answer then, right? This video's about 3 years old so I don't know if you still check these comments but I thought I'd give it a try.

[@marcelkruger5187]

Thanks so much for the video (time 0:28) especially. Found out my entire page I was given pertaining to the derivatives was wrong,

[@techlance]

Thanks Patrick...i learnt alot

[@NguyenLe-wl9is]

In the last problem, how the square root of x^2 becomes x while x from -1 to 1? Thank you.

[@theimmux3034]

How should I go about integrating 1/(1-x^2)? Came here looking for some help and found that both arctanh(x) and arccotanh(x) could be substitutes. Which one is it?

[@lambertsempundu9317]

that's great job brother. keep it up.

[@patrickjmt]

Thanks, will do!

[@derickdewitt1807]

THANK YOU SO MUCH. I was using the wrong formulas until I saw your Video!! Thank you!!!

[@lanfordvideos]

You were probably using the non-hyperbolic inverse trig functions. They are definitely not the same.

[@patrickjmt]

@imwithdumbhead i factored it out, what i did is correct.

[@imwithdumbhead]

at 2:44 you forgot to multiply everything by 2. (found in the last term; derived from 2x)

[@abdullaahmed4933]

8:10 the root of x square is not x , but IxI , isn't? am i right?

[@ntandokazibaxana7367]

Thank you soooo much for this!!!!! Very helpful!

[@MeLol369]

Help please integral of (csch (t^1/2 )coth(t^1/2))/t^1/2 The argument and denominator is actually square root of t.

[@lizchatham5940]

Hey, thanks for these vids. You're pretty awesome.

[@RichPerez]

Why does the absolute value of x have to be less than 1 for the derivative of inverse hyperbolic tangent but greater than 1 for the derivative of inverse hyperbolic cotangent?

[@jay-leandrouchiha3369]

Rich Perez observe the graphs of both functions and you'l see

[@patrickjmt]

yes, that is exactly what happened : )

[@AlexanderAV]

Hey Patrick question; are you a student or a TA or something? All ur vids are going parallel to my eng. I course!

[@waadii6351]

Thanks very helpful

[@rohangiga]

I LOVE YOU PATRICK

[@zaproud]

hey many thnx for this lesson but is there a cool way to sae theses derivatives in my mind and not to forget them ? i hope you answer me

[@samanpaydar4415]

Nice job you are awesome 😍😉

[@k0shtim]

By the way isn't arcsecx = 1/x sqrt x^2 -1 ?

[@adambarnhart4225]

Love the videos.

[@abdullaahmed4933]

Thanks very much

[@patrickjmt]

ha, thanks :)

[@Yu2Kal]

@horrabletypoe Its not arc its just ar , its different with the hyperbolics

[@manishasaini2324]

Thank you!

[@bethovenzamora6343]

I am only 7 years old when this video was uploaded And now watching it cuz i have midterms tomorrow 🤣

[@ryukenlmaoyes]

thanks

[@adnansomani8218]

ur a genius

[@Burpeekanksss]

such a beneficial

[@dutchbunny409]

you are awesome!

[@TheKaveshan]

shot 4 da help. im at ukzn in s.a

[@400080vikkash]

at 2:05 I dont get why the der of the bottom was simply two and you didn't use the power rule bringing down the 2 power?

[@civilwater5076]

awesome

[@mzia8925]

I think u got the derivative of the inverse sec (arcsec) wrong for the last one.

[@sebastianhilscher8072]

Muhammad Siddiqui he canceled out -2x with 2 and got x, minus missing, dont know if that played a role

[@redgefleming1535]

u 2πr there was two negative sign multiplied together

[@redgefleming1535]

I think the error was when he square root -x².

[@kingXofXhell]

quick question need answer ASAP Y=Coth^-1(sin2x)

[@moizabbasi1286]

herro

[@bubushhh]

7 years later, has this helped you in any sort of way?

[@karimkhan1312]

please refer cable hanging between 2 poles-- please explain how to plug values in y= a cosh u

[@godfredagyei-frimpong2656]

thanks man

[@imwithdumbhead]

@patrickJMT cool. didnt see that comng. sorry

[@karimkhan1312]

please explain hperbolic radian -- thank u sir

[@sosoal-malake4010]

I think ther are error in write the value for csch^-1

[@sexibrian]

Do you teach at any university? Because you sir need too become a professor and get paid for what you do!

[@JustSemantics]

Hehe, 1:19. (x squared times the... other function.) Got tired of saying hyperbolic? :D

[@akcreation4782]

Chacha samjh gayli

[@nobelathemba]

2024 I'm here

[@patrickjmt]

yes, yes you are

[@HamletSlaya101]

Instead of always saying hyperbolic, you should say "hype" its alot quicker. like "arc 'hype' sec of xyz"