Permutation in String - Leetcode 567 - Fixed Sliding Window (Python)

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[@GregHogg]

Master Data Structures & Algorithms For FREE at AlgoMap.io!

[@tauicsicsics]

After watching 3 other videos, this is the clearest of them all, finally understood this problem. Fantastic explanations, pls don't stop making leetcode videos.

[@Amanda-bg7ib]

Better than Neetcode's explanation on the same problem, and more simple/ straightforward too! Came here cuz the neetcode one was too confusing and long

[@rocksays80]

This is a more clear explanation than Neetcode. Solidified the concept right away. Thanks!

[@SHIHJUIheh]

OMG! This is the clearest explanation I have seen! Really hope you keep making videos!

[@GregHogg]

Really glad to hear that

[@ruchikaahujaasm]

Very clear and detailed line by line explanation which helped me to understand the algorithm better. Thank you for your efforts !!!!

[@RupertBruce]

The count array gets rid of the permutation problem and the sliding window trick gives a nicely scalable iteration. Edit: watched to the end... Nice

[@Alex-tm5hr]

Another video you explained better than anyone else! Thanks greg!

[@3227998]

This is an epic explanation! Thank you!

[@GregHogg]

Glad to hear it, thanks a ton!!

[@Yoshi98able]

Really helpful and well explained

[@GregHogg]

Glad to hear it, thanks a ton!

[@aly7401]

Simple and elegant, thank you for the great video

[@GregHogg]

You're very welcome :)

[@yhh4844]

It's easy to understand, thank you!

[@ridasohail4318]

Why we build up s2 count array in the first for loop? Why can't we just build it from start in the second loop?

[@GregHogg]

It's just easier this way iirc

[@markelmorehome]

elegant.

[@nagarjunachenna7773]

drawing tool name please

[@sowoul_]

just do this class Solution: def checkInclusion(self, s1: str, s2: str) -> bool: check = Counter(s1) temp = {} k=len(s1) for i in range(len(s2)): if i

[@philipbrujic4728]

Good video

[@moonlight-td8ed]

you just got a new sub, thank you

[@darkemperor9006]

confusing solution

[@user-jm6gp2qc8x]

again, why don't you stick to dictionaries lol