pH calculation for a polyprotic acid

7-6 This video describes how to calculate the pH for a general polyprotic acid, and carries out a numerical example for a 0.1 M solution of carbonic acid.

[@keggeria7249]

I have a final tomorrow and this greatly clears up titrations of polyprotic acids. I was always confused when to use Ka1 or Ka2 and you do a great job telling which one to use.

[@ariamodir4750]

Helped me understand the material very well for my final tomorrow. Thank you.

[@guillermojarne2803]

You are really good at explaining!

[@malshakakodikara4681]

You're a great teacher. Thank you

[@weeb_slayr_6948]

This was an amazingly helpful and clear video. Thank you!

[@kub8675]

Great explication, thank you

[@muhammadzeeshan5335]

extremely helpful lecture. Thanks

[@pancaker1793]

Youre a godsend! Love your videos!

[@MariaFernanda-yv8tw]

Thank you very much! Such a great explanation!

[@Selorm__]

Herh Chale thank you wai 🎉😂😂😂

[@Noobskism]

Great Video, this helped me a lot! Thanks!

[@adelinepangilinan2979]

very helpful. fyi is the ka1 written incorrectly?

[@techno-sorcery9852]

Very helpful video. Thanks!

[@hamedbarzinmehr]

This method of yours may be useful. But one should keep in mind that equilibrium concentrations never change . In the second equation the equilibrium concentration of hydronium is greater than that in the first and that's wrong . The true way of solving this problem is by writing proton balance and mass balance equations and then use approximations

[@chaera-vr5wv]

Thank you!

[@Ankita-vu5fk]

extremely helpful

[@ranasamir9462]

great explanation. thank you!

[@ryankorman8258]

Great video, thank you!

[@nicoletsang8884]

when writing a diprotic acid reaction of sulfuric acid, H2SO4 + H2O --> SO4 + H3O, there's a missing hydrogen on the product side, so how do you write the correct equation?

[@nucleophile]

Why you do t change H2CO3 conc. after HCO3- disociated, why it's not [H2CO3]=0,1-2,1*10^-4 - y

[@amandaalfonso8330]

Thank you so much! Help so much!!

[@DeniseP]

very helpful Thank you

[@shaqsquacks3886]

this video rocks!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

[@estiakahmed804]

Thanks

[@thewisefromwest6941]

Thank you sir

[@abhi_sndhu]

Thanks Sir.

[@cavelinguam6444]

Nice. Thank you.

[@princetonokwuoha7826]

hello how can i reach you please? i need an analytical chem tutor

[@lesliegeorge8050]

Nice!

[@maimohamed439]

الله يسترك يا حاج والله

[@chathunikulathunga3039]

It’s true when they say bald men are good at everything;))

[@user-uy6uu8cz7n]

عراقي وافتهمتلك

[@ramavittal3494]

How do you got pH =3.89

[@ramavittal3494]

PH =3.68

[@maanavsingh1914]

@@ramavittal3494 You take the negative log of H+ Ion Concentration. -log[H+] = -log[2.1X10^-4] ~= 3.68 ; pH = 3.68

[@mjones7356]

Thank you!