Excellent animation, thank you so much for doing it!
@meyavuz3 жыл бұрын
Thanks Nico. Glad to hear that
@akhilbiju32452 жыл бұрын
hello, what is the value of delta w and delta k thank u
@meyavuz2 жыл бұрын
Here are the values I have utilized: Randomly chosen and fine tuned. ``` n1= 1.0; n2 = 1.1; c = 3; f1 = 1; f2 = 1.0 - 0.090910; f3 = 1.0 + 0.2; f4 = 1.0; lambda1 = c/(f1*n1); lambda2 = c/(f2*n2); lambda3 = c/(f3*n2); lambda4 = c/(f4*n2); w1 = 2*pi*f1; w2 = 2*pi*f2; w3 = 2*pi*f3; w4 = 2*pi*f4; k1 = 2*pi/lambda1 * n1; k2 = 2*pi/lambda2 * n2; k3 = 2*pi/lambda3 * n2; k4 = 2*pi/lambda4 * n2; ```
@akhilbiju32452 жыл бұрын
@@meyavuz thanks 😁
@meyavuz2 жыл бұрын
@@akhilbiju3245 welcome
@ВладимирСтригалев-е7у10 ай бұрын
One question. There are equal frequencies for f1 and f4, but different wavelength in sample where Vg=0. Group velocity is a characteristic for telecommunication and this case is impossible.
@meyavuz10 ай бұрын
But f1 and f4 do not have same frequencies., they are different. Just stop and count the peaks you will see the difference in frequency. So that scenario theoretically can be obtained