Physics: Basic Statics w/ Ladders

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Stephan Pichardo

Stephan Pichardo

Күн бұрын

Пікірлер: 33
@carterjones155
@carterjones155 29 күн бұрын
Thank you so much! After struggling with a similar problem that had a very unhelpful solution I came across this video and I was immediately able to understand the concept and apply it to my problem. 10/10
@AkpunkuDaniel
@AkpunkuDaniel Жыл бұрын
Thank you so much! this was so helpful. I was thinking that we were going to resolving the triangle into its x and y components. you got yourself a new subscriber. keep up the good work man!
@ptyptypty3
@ptyptypty3 5 жыл бұрын
Thank YOU!!.. this video was PERFECT from Beginning to End!!.. I think it's safe to say that even a 5th grader could have learned from this.. :) .. You are very Clear and stepwise methodical.. and that's what WORKS.. :) .. thanks again...
@neadedios3106
@neadedios3106 2 жыл бұрын
you're a saint
@valeriereid2337
@valeriereid2337 2 жыл бұрын
Thank you very much for this excellent explanation.
@dagmawitsegaye5258
@dagmawitsegaye5258 2 жыл бұрын
You are amazing👌
@oxalicfn9615
@oxalicfn9615 4 жыл бұрын
What if the wall also has friction
@averyalexanderarnold1885
@averyalexanderarnold1885 3 жыл бұрын
There would be an additional force in posetive y axis
@fatihtekin3471
@fatihtekin3471 3 жыл бұрын
I got confused with the FN. Why you did not consider the force acting on x-Axis at that point since the ladder stands inclined to the ground. (other than Fs). That should be FNy and FNx, right?
@krossyt5031
@krossyt5031 2 жыл бұрын
Thanks man!
@dendoinks
@dendoinks 2 жыл бұрын
Thank you very much 🙏
@theharv1490
@theharv1490 23 күн бұрын
Tysm!!!!!
@abrainttadeo2216
@abrainttadeo2216 4 жыл бұрын
how did you calculate the Fw? at the last part
@sha9855
@sha9855 6 жыл бұрын
why is the horizontal gravitational force not a part of the horizontal forces?
@StephanPichardo
@StephanPichardo 6 жыл бұрын
We cannot really say that there is a 'horizontal' gravitational force, although I think I know what you might be getting at. The gravitational vector is just that, and it points toward the ground as drawn. It does not have components on both axes, since it is not slanted with the coordinate system established as it is (cos90 = 0). Gravity does play a part in the horizontal axis however, because it is embedded in the definition of friction (indirectly, as part of the normal force).
@fisherofmen489
@fisherofmen489 4 жыл бұрын
why did u use fg and fw as the forces in the torque equation
@StephanPichardo
@StephanPichardo 4 жыл бұрын
Those are the only forces that are a nonzero distance away from the 'hinge' that I chose, namely the point where the ladder meets the floor.
@fisherofmen489
@fisherofmen489 4 жыл бұрын
@@StephanPichardo thx
@Kruzeda
@Kruzeda 4 жыл бұрын
The coordinate system you used here is weird for me, why do you take the cos component for the gravitational force of the ladder instead of the sin component, and the sin component for the normal force? To me, coordinate system you set here, implies that you take the sin component of gravity (since it acts downwards) and the cos component of the normal force (since it acts to the right)
@TheDarkNightRising
@TheDarkNightRising 3 жыл бұрын
Because if u were to draw x and y component of Fg u would see that the force perpendicular to the ladder can be represented by Fgcosø (not actually theta symbol)
@mickytube1935
@mickytube1935 4 жыл бұрын
Helpful tnx sir
@asdfghjkl6506
@asdfghjkl6506 5 жыл бұрын
Which software do u use
@StephanPichardo
@StephanPichardo 5 жыл бұрын
It's Microsoft OneNote along with quicktime player on Mac for recording,
@asdfghjkl6506
@asdfghjkl6506 5 жыл бұрын
@@StephanPichardo thanks but are they free
@StephanPichardo
@StephanPichardo 5 жыл бұрын
@@asdfghjkl6506 Quicktime comes with MacOS and I believe OneNote is a free download from the Mac and Windows App Store.
@asdfghjkl6506
@asdfghjkl6506 5 жыл бұрын
@@StephanPichardo thanks
@TripleAceAAA
@TripleAceAAA 3 жыл бұрын
How the heck is the y component perpendicular to the ladder, it isn’t lol…this makes no sense and how is the x component of the fg force perpendicular to the ladder cause it isn’t either …like what
@StephanPichardo
@StephanPichardo 3 жыл бұрын
Hi, I’m sorry you’re having trouble with this explanation. If you’ll look carefully, you’ll see that none of the vectors I drew are perpendicular to the ladder. Our vectors are oblique to the ladder, since it is slanted and the coordinate axis that is easiest to work with is not. For example, the force of gravity is simply straight down as it always must be.
@Corsaka
@Corsaka 5 жыл бұрын
how do you draw so accurately
@StephanPichardo
@StephanPichardo 5 жыл бұрын
I use a Wacom Intuos tablet. I think most of the others on KZbin who make tutorial videos use similar equipment: www.wacom.com/en-us/products/pen-tablets/wacom-intuos
@metsycats
@metsycats 6 жыл бұрын
very helpful, thank you
@aaronngulube3729
@aaronngulube3729 3 жыл бұрын
Nob
@be4913
@be4913 2 жыл бұрын
why don't you just use 2.5sin(53) to find the perpendicular radius to the force of the wall, and then divide 2.5 by 2 and do 1.25cos(53) to find the perpindulcar radius to the force of the ladder. would that be incorrect? it seems much easier to me
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