Thank you so much! After struggling with a similar problem that had a very unhelpful solution I came across this video and I was immediately able to understand the concept and apply it to my problem. 10/10
@AkpunkuDaniel Жыл бұрын
Thank you so much! this was so helpful. I was thinking that we were going to resolving the triangle into its x and y components. you got yourself a new subscriber. keep up the good work man!
@ptyptypty35 жыл бұрын
Thank YOU!!.. this video was PERFECT from Beginning to End!!.. I think it's safe to say that even a 5th grader could have learned from this.. :) .. You are very Clear and stepwise methodical.. and that's what WORKS.. :) .. thanks again...
@neadedios31062 жыл бұрын
you're a saint
@valeriereid23372 жыл бұрын
Thank you very much for this excellent explanation.
@dagmawitsegaye52582 жыл бұрын
You are amazing👌
@oxalicfn96154 жыл бұрын
What if the wall also has friction
@averyalexanderarnold18853 жыл бұрын
There would be an additional force in posetive y axis
@fatihtekin34713 жыл бұрын
I got confused with the FN. Why you did not consider the force acting on x-Axis at that point since the ladder stands inclined to the ground. (other than Fs). That should be FNy and FNx, right?
@krossyt50312 жыл бұрын
Thanks man!
@dendoinks2 жыл бұрын
Thank you very much 🙏
@theharv149023 күн бұрын
Tysm!!!!!
@abrainttadeo22164 жыл бұрын
how did you calculate the Fw? at the last part
@sha98556 жыл бұрын
why is the horizontal gravitational force not a part of the horizontal forces?
@StephanPichardo6 жыл бұрын
We cannot really say that there is a 'horizontal' gravitational force, although I think I know what you might be getting at. The gravitational vector is just that, and it points toward the ground as drawn. It does not have components on both axes, since it is not slanted with the coordinate system established as it is (cos90 = 0). Gravity does play a part in the horizontal axis however, because it is embedded in the definition of friction (indirectly, as part of the normal force).
@fisherofmen4894 жыл бұрын
why did u use fg and fw as the forces in the torque equation
@StephanPichardo4 жыл бұрын
Those are the only forces that are a nonzero distance away from the 'hinge' that I chose, namely the point where the ladder meets the floor.
@fisherofmen4894 жыл бұрын
@@StephanPichardo thx
@Kruzeda4 жыл бұрын
The coordinate system you used here is weird for me, why do you take the cos component for the gravitational force of the ladder instead of the sin component, and the sin component for the normal force? To me, coordinate system you set here, implies that you take the sin component of gravity (since it acts downwards) and the cos component of the normal force (since it acts to the right)
@TheDarkNightRising3 жыл бұрын
Because if u were to draw x and y component of Fg u would see that the force perpendicular to the ladder can be represented by Fgcosø (not actually theta symbol)
@mickytube19354 жыл бұрын
Helpful tnx sir
@asdfghjkl65065 жыл бұрын
Which software do u use
@StephanPichardo5 жыл бұрын
It's Microsoft OneNote along with quicktime player on Mac for recording,
@asdfghjkl65065 жыл бұрын
@@StephanPichardo thanks but are they free
@StephanPichardo5 жыл бұрын
@@asdfghjkl6506 Quicktime comes with MacOS and I believe OneNote is a free download from the Mac and Windows App Store.
@asdfghjkl65065 жыл бұрын
@@StephanPichardo thanks
@TripleAceAAA3 жыл бұрын
How the heck is the y component perpendicular to the ladder, it isn’t lol…this makes no sense and how is the x component of the fg force perpendicular to the ladder cause it isn’t either …like what
@StephanPichardo3 жыл бұрын
Hi, I’m sorry you’re having trouble with this explanation. If you’ll look carefully, you’ll see that none of the vectors I drew are perpendicular to the ladder. Our vectors are oblique to the ladder, since it is slanted and the coordinate axis that is easiest to work with is not. For example, the force of gravity is simply straight down as it always must be.
@Corsaka5 жыл бұрын
how do you draw so accurately
@StephanPichardo5 жыл бұрын
I use a Wacom Intuos tablet. I think most of the others on KZbin who make tutorial videos use similar equipment: www.wacom.com/en-us/products/pen-tablets/wacom-intuos
@metsycats6 жыл бұрын
very helpful, thank you
@aaronngulube37293 жыл бұрын
Nob
@be49132 жыл бұрын
why don't you just use 2.5sin(53) to find the perpendicular radius to the force of the wall, and then divide 2.5 by 2 and do 1.25cos(53) to find the perpindulcar radius to the force of the ladder. would that be incorrect? it seems much easier to me