Physics - Nuclear Physics (9 of 22) Radioactive Activity (aka Decay Rate)

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Michel van Biezen

Michel van Biezen

Күн бұрын

Пікірлер: 31
@aaronreybonaobra9109
@aaronreybonaobra9109 6 жыл бұрын
I swear this guy knows everything
@jdetres01
@jdetres01 7 жыл бұрын
your bow tie helped me listen better btw. i also love that you showed the few times you made a mistake and how you found out it was a mistake, and humbly corrected it. seeing someone do something completely perfect 100% of the time doesn't help people failing at the subject 90% of the time. so just seeing you forget the negative sign or even finishing the equation on the wrong line helped me see if i were to make a mistake, HOW to correct it! your teaching is more valuable than you may know and i wanted you to know that.
@HaiderAli-nj7tv
@HaiderAli-nj7tv 2 жыл бұрын
Sir at 1:17 why did you multiply negative lambda with the right side of your equation?How, is it some kind rule? I am from cie a levels they never taught us anything like ddt you did on both sides. I think i have asked a very dumb question.
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Not a dumb question at all. Sometimes we just don't see something. Happens all the time to me as well. When taking the derivative of an exponential function: d/dt (e^-at) = -a e^-at
@DarknessIsThePath
@DarknessIsThePath 7 жыл бұрын
If I at the beginning get the decay rate of something, let's say 3070 decays/s in 500g of a sample, and carbon provides 225bq/kg, when you have to calculate the age of the sample, do you always have to take the ratio of the sample to the carbon one?
@MichelvanBiezen
@MichelvanBiezen 7 жыл бұрын
Yes. You have to use the ratio of the mass of your sample to the mass of the object for which you know the reference decay rate.
@DarknessIsThePath
@DarknessIsThePath 7 жыл бұрын
Nice, thanks for the answer.
@aparna8577
@aparna8577 2 жыл бұрын
this was really insightful, thank you sir!
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Glad it was helpful!
@sophielynn9198
@sophielynn9198 6 жыл бұрын
Sir, where does the minus sign go in the final answer?
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
The minus simply indicates that the number of radioactive atoms is decreasing. But when we want to express the number of decays per second, it doesn't make any sense to keep the negative sign. (you can't have negative decays per second)
@ahmadtheaviationlover1937
@ahmadtheaviationlover1937 3 жыл бұрын
@@MichelvanBiezen another way that the minus sign is used for is on logarithms and finding the reciprocal of a value
@khushijain4969
@khushijain4969 6 жыл бұрын
Why did you not mutiply e^-lambda/t to the last equation . That also consists of the rate of decays ?!
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
We did. N(t) is the function with the exponent.
@khushijain4969
@khushijain4969 6 жыл бұрын
@@MichelvanBiezen but you just multiplied the no. Of nucleons and not the exponent in your calculations
@MichelvanBiezen
@MichelvanBiezen 6 жыл бұрын
@@khushijain4969 Yes, when t = 0, the exponential part equals 1.
@philipli1206
@philipli1206 10 жыл бұрын
You are my Savior ! Thank you very much ! Very clear !
@rosakuppelapolye7823
@rosakuppelapolye7823 5 жыл бұрын
Where did you get the 0.693?
@thomaswilson1107
@thomaswilson1107 5 жыл бұрын
The time required for half of the original population of radioactive atoms to decay is called the half-life. The relationship between the half-life, T1/2, and the decay constant is given by T1/2 = 0.693/λ. (Copied off of Britannica)
@curiash
@curiash 4 жыл бұрын
@@thomaswilson1107 correct
@yassinedownpourz
@yassinedownpourz 4 жыл бұрын
ln(2)
@Svajok
@Svajok 11 жыл бұрын
Hey! i thought all your videos on this topic are very clear and straightforward! Also arranged well, and i revised pretty well from them, thanks a lot
@MichelvanBiezen
@MichelvanBiezen 11 жыл бұрын
You are welcome. Thanks for the comment.
@curtpiazza1688
@curtpiazza1688 Жыл бұрын
Excellent!
@MichelvanBiezen
@MichelvanBiezen Жыл бұрын
Glad you liked it!
@hallahkhalil3027
@hallahkhalil3027 7 жыл бұрын
is this GCSE or A level
@MichelvanBiezen
@MichelvanBiezen 7 жыл бұрын
It is not specifically geared towards any specific test, but the videos cover the key concepts of all physics.
@danielvanderstruis1516
@danielvanderstruis1516 2 жыл бұрын
legend
@MichelvanBiezen
@MichelvanBiezen 2 жыл бұрын
Glad you like our videos. 🙂
@judeohaji638
@judeohaji638 4 жыл бұрын
How is carbon 14 one trillion of carbon 12 Why is trillion?
@MichelvanBiezen
@MichelvanBiezen 4 жыл бұрын
it is the relative abundance
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