Physics Question: Which Hole Will Shoot Water Further? Python Model Included.

[@ajejebrazor4936]

I would love to see the simulation of the tank draining! Thanks for this nice detour!

[@fizixx]

This was eye-opening. I've not done this with more than one opening, so the furthest one was a nice surprise. Will have to play with this.

[@williamperez-hernandez3968]

Since the initial height of water, with respect to the floor, is the same for the three cases, let it be H. Therefore H=h + y. The equation for water's range is x= 2×sqrt(Hy - y^2). So dx/dy = 0 gives y=H/2, thus a hole at middle of the water's initial height will shoot the furthest. This results in the curious result that x_max = H, exactly the initial height of the water inside the tank!

[@GregHoke]

Had the exact same idea!

[@padraiggluck2980]

As the streams leave the tank the volume of water decreases.

[@DotPhysics]

yes - that is true, so this is just a very short time interval. However, now I want to model a draining tank with three holes.

[@godphysics2473]

About the comment you made that the distance should be the same independently of the planet, I’m not so sure about cuz you need to consider the atmospheric pressure. Could you clarify that, please?

[@Universon-wi7mx]

It would not depend on atmospheric pressure, because the pressure at the bigger opening equals the pressure at the small hole as they are both open to atmosphere. So both they cancel out. You can confirm this with Bernoulli's theorem.

[@godphysics2473]

@@Universon-wi7mx I see it now, thank You!

[@Universon-wi7mx]

@@godphysics2473My pleasure