Physics - Test Your Knowledge: Vectors (27 of 30) Find the Displacement

[@yanyan5195]

i am an engineering student and you're now my favorite professor, i wish all professors teach like you..>3

[@MichelvanBiezen]

Thank you. Glad you found our videos. 🙂

[@wadhax5191]

Thank you soo much I was struggling A LOT. You explained it in a very clear detailed way. you are my savior in physics!!

[@MichelvanBiezen]

Glad you found our videos. 🙂

[@tamale4864]

Thank you. This has been just incredibly helpful. Thank you!!

[@nestiray]

You are a god, online learning is not working atm for me and you are my savior. Bless you with all of my heart.

[@MichelvanBiezen]

Not a god at all, but a simple man with many problems and struggles like everyone else.

[@sreer8250]

I was struggling so much in solving these types of problem.really helped me.thankyouu

[@ashishanand9629]

Thanku so much sir, now u r famous among indian student also.....

[@MichelvanBiezen]

Glad we can help.

[@fermasojeanalvat.8304]

This has been very helpful for me. What a great video and teaching thank you!!

[@MichelvanBiezen]

Glad it was helpful!

[@luisdominguez4703]

OMGGGG I ACTUALLY UNDERSTAND IT THANK YOU THANK YOU THANK YOU

[@MichelvanBiezen]

We are glad the videos are helping.

[@rachelvo9587]

so when they ask for "displacement", I can answer them in coordinate (i,j)? Can I give them a distance? Because after finding the coordinate of S, I square rooted it. S=(74.0^2 + 108^2)^1/2. This is what I thought they were asking for.

[@MichelvanBiezen]

When the word "displacement" is used (instead of distance), they are looking for a vector (which has both a magnitude and a direction). There are different ways in which vector are expressed, but it must be a vector

[@boramawi]

I should agree with your answer. But this is very helpful video for understanding the problem.

[@regiemarinay9906]

This is very helpful. Thanks. I'm now able to solve our activities regarding that.

[@Danleesixoneonetwofive]

You are a great educator!

[@MichelvanBiezen]

Thank you. We appreciate the comment. 🙂

[@petereziagor4604]

Thank you, prof. for this wonderful video

[@MichelvanBiezen]

Glad you liked it!

[@DevCipher]

Shouldn't we use sin with j? And cos with i U have mixed those 2 i guess.

[@MichelvanBiezen]

(the math is correct in the video). You cannot blindly attach cos to i or sin to j. It depends on which angle is referenced. Instead use the definition of sin and cos sin = opposite side / hypotenuse cos = adjacent side / hypotenuse

[@thedarkknightrisesisnotgoo6308]

Sir how can we be able to find the direction with angle

[@hnnd451]

Thank you sir! but i have a question why is that the s vector is equal to the sum of a+b+c vector ? yet the s vector seems to be shorter than all of them combined....

[@rawdahafez3690]

Why we are not able to say that the final displacement is equal to the final point minus the initial point (rf -ri) ?

[@MichelvanBiezen]

Yes, that is correct, but you first must find the final point. Essentially finding the resultant vector is equal to that.

[@peemak1701]

THANK YOU THIS IS VERY HELPFUL

[@MichelvanBiezen]

Glad it helped!

[@fafary7820]

So where I am going to put the measurement of the angle?Is it outside or inside the angle?

[@MichelvanBiezen]

For example when the problem reads: 60 degrees EAST of NORTH, then you draw the angle starting from the north axis and and moving towards the EAST.

[@shreerakshanaik5154]

Please help me with this question.......Reena facing North walks 3 km , turns left and walks 4 km.. again she walks 3 km after turning right. Then she turns right and walks 12 km. What is his displacement from starting point and which direction is she facing???

[@MichelvanBiezen]

The net displacement in the north direction = 3 km + 3 km = 6 km The net displacement in the east direction = 12 km - 4 km = 8 km. The total displacement = sqrt( (6 km)^2 + (8 km)^2) = 10 km The direction = 36.87 degrees north of east

[@shreerakshanaik5154]

@@MichelvanBiezen I have no words to express how to thank you Thanks a lot......

[@janamorchaves8222]

My problem is that I have to push a cart 40m down and then make 90° turn and move 15 m as instructed. You then make 90° turn and move 20 m east Is there any way to solve it, cause the direction where to bend the 90° is not given, im really confused

[@MichelvanBiezen]

It is definitely a VERY poorly worded problem. The firs part: "push a cart 40 m "DOWN" " I would interpret it as moving in the negative y direction which means towards the south. But then it is impossible to be moving EAST after two 90 degree turns. This only works if the initial 40 m where traveled in the EAST direction. And then the 15 m could be moving to the NORTH or to the SOUTH, after which a 90 degree turn will put you back into an easterly direction.

[@janamorchaves8222]

You are right sir,maybe there's some error on my modules, thank you so much for the time and explanation. I appreciate it a lot.

[@Galo2112]

Thank you

[@MatthiasMubita]

This is excellent

[@MichelvanBiezen]

Thank you. Glad you liked it. 🙂

[@nguyendk410]

Dear Prof. Biezen, the theta angle would be 55.33 degrees. How could I know that it is North of East or East of North? Thank you so much.

[@MichelvanBiezen]

You need to use the compass directions and look at your drawing. UP is N DOWN is S RIGHT is E and LEFT is W For example the 60 degree angle vector B makes with respect to the vertical can be called 60 degrees EAST of NORTH or it can be called 30 degrees NORTH of EAST

[@mapleleaf922]

why do you use sin and cos in part c? shouldn't it be tan and cos?

[@MichelvanBiezen]

The trig functions used for C are correct.

[@djbagasina1564]

May I know what is that I and J direction?

[@MichelvanBiezen]

i direction is in the postive x-direction j direction is in the positive y-direction k direction is in the positive z-direction

[@얼음소년]

Thank you~❣

[@pewkachu1263]

hi but dont we use cos theta for the Ax and sin theta for the Ay?

[@MichelvanBiezen]

We cannot assume that. It depends on the situation.

[@Sadraansarii]

Michel van Biezen sir but how can recognize the situation

[@val-zv3ko]

i still dont freaking get why u use which trig on whay angles is this just a geometry thing?

[@sanda834]

Thank you very very much sir

[@MichelvanBiezen]

Most welcome 🙂

[@riyon1918]

Thanks prof!

[@MichelvanBiezen]

You are welcome! Glad you find the videos helpful. 🙂

[@jayr1018]

Hi, good day, how can we find the direction of the displacement in this problem. Can we use the inverse tangent for this? Thank you.

[@jayr1018]

Hoping that you could see this question sir, thank you

[@MichelvanBiezen]

Yes, if you want to find the direction of the total displacement use tan^-1 (y-component / x-component)

[@godwintayas8957]

Is it possible to find the displacement of Vector A to Vector J? I'm having a hard time figuring it out

[@MichelvanBiezen]

Subtract the one vector from the other, and then find the magnitude of the difference.

[@huzaimkhan9269]

Thank you sir...

[@dirtyharrysgun2020]

THANK YOU

[@MichelvanBiezen]

You're Welcome!

[@dddddw9590]

how did you know to use sin and also cos and why use both?

[@MichelvanBiezen]

Use the definition: sin = opposite side / hypothenuse cos = adjacent side / hypothenuse

[@mwizanyimbiri2253]

Vectors mathematics

[@MichelvanBiezen]

Yes indeed. 🙂

[@naniwoo7197]

Hi, I'm a freshmen in civil engineering and I've been having problem on solving displacement because I don't know which procedure I should follow. About your solution sir, may I ask where does "i" and "j" come from? cuz' I'm having trouble understanding the solution with the curiosity still bugging me. ☺️

[@MichelvanBiezen]

i, j, and k and the directional unit vectors for the x, y, and, z axis

[@captainboomerang7635]

nice ka jaigs

[@feliciavallerie433]

thank you sir please be my husband

[@MichelvanBiezen]

Thank you, but that ship has sailed a long time ago. 🙂

[@josuearcos2023]

You are wrong

[@averagestudent5222]

What's wrong? (I'm new to this)

[@d.kentertainmenteducation1620]

Thumbnail of this question solution is wrong but professor explain its questions solution right

[@lexterbiggayan6110]

after getting the sum of x and y, shouldn't you use pythagorean theorem after? please repond, thanks:))

[@MichelvanBiezen]

That depends. We were asked to find the displacement, which is a vector quantity. That is why the answer was in a vector format. If the question asks for the magnitude of the displacement, then we would need to use the pythagorean theorem to find the magnitude of the vector

[@lexterbiggayan6110]

@@MichelvanBiezen thank you!!

[@angelsiaboc4012]

@@MichelvanBiezen wow! thank you. I was gonna about to ask the same question too. thank you for ur answer sir, this rly helps me.

[@lilieontan9846]

thank you

[@MichelvanBiezen]

You're welcome!