MECHANICAL PROPERTIES OF SOLIDS 04 || Elasticity : Energy Stored in a Streched Wire JEE MAINS/ NEET

[@PhysicsWallah]

Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on KZbin) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. Class 11 chapter 9 || MECHANICAL PROPERTIES OF SOLIDS 01|| Elasticity : Introduction IIT JEE /NEET kzbin.info/www/bejne/aqPCg6psrLKXoNE MECHANICAL PROPERTIES OF SOLIDS 02 || Elasticity : Numericals on Stress Strain IIT JEE MAINS/ NEET kzbin.info/www/bejne/r6LaYoGcbpaZj6M MECHANICAL PROPERTIES OF SOLIDS 03 | ELASTICITY : Stress Strain Curve |Stress Strain Graph JEE MAINS kzbin.info/www/bejne/bX3WiGCIqcaUitU MECHANICAL PROPERTIES OF SOLIDS 04 || Elasticity : Energy Stored in a Streched Wire JEE MAINS/ NEET kzbin.info/www/bejne/Z2PZiK2phdhjrK8 MECHANICAL PROPERTIES OF SOLIDS 05 | Elasticity :Thermal Stress and Strain ,Poisson's ratio JEE/NEET kzbin.info/www/bejne/nmGXdqqKbq-Wa7s

[@neeruchaturvedi6699]

20

[@tashvimadaan3351]

@@neeruchaturvedi6699 i m not getting it my answer is root 40

[@neeruchaturvedi6699]

@@tashvimadaan3351 under root 400 ayga

[@tashvimadaan3351]

@@neeruchaturvedi6699 but i m not getting that

[@sagunsahu1417]

Sir I have donated RS 1500 in your paytm account. plz check.

[@harshyadav5512]

23:05 Answer is 20 m/s Thank a lot sir, you explained it so well that I'm able to solve these problems now ❤

[@cobratate_andrew]

bro kaahn se padh rahay tum jee ke liye ? pw ?

[@harshyadav5512]

@Cobratate-oq7uk yes

[@vivan_sharma_15]

Which Class?

[@soniapadhi7471]

Physics never have been this crystal clear to me! All credits goes to you sir :)

[@vijaykumar-wu6np]

are you in class 11 ?

[@IG_Ninjaa_3]

Alakh sir op🔥🔥🔥

[@aayushisinghal9257]

Yessssss

[@tannisthapaul3621]

03:10 - derivation 16:10 - derivation with help of spring 20:49 - numerical

[@arpitbalawords1]

I was looking for this in comment section

[@dishajain7466]

ans is option (b) 20m/s... putting all these values, Y= 5×10^8 N/m², (strain)²= (∆L/L)²= (2×10-²m/10×10-²m)², volume= [A(1×10^-6m)×L(10×10-²m)], m= 5×10-³ kg in the given equation....👍👍

[@aishwaryakale2642]

Ty for detailed calculation...

[@Krishnarahul7]

We will get 2/root10 m/sec bro

[@gagandeeptyagi9135]

@@Krishnarahul7 bro tera answer option mey bhi nahi hai

[@mr.karannakum8483]

Aa gaya 20 m/s

[@Masterkeyinc]

@@Krishnarahul7 churhiya

[@freezerballer1078]

Sir aapko to maana padega itna jaldi itne video banadiya...Sir u r really a successful youtuber SALUTE TO YOU SIR...

[@chumtiyehosab5171]

👍

[@maheshwarinenshkhimji]

Lo ho bhi gay🎉🎉🎉

[@always.bhavesh]

THERE IS SENSE OF FEELING IN YOUR TEACHING.................................... ALL THE BEST SIR .KEEP HELPING STUDENTS LIKE THIS FOREVER.

[@ananyagupta6075]

timestamps 03:10- derivation 16:10 - derivation with help of spring 20:49 - numerical

[@rajeevmeena2933]

The answer of last question is 20 m/s L=0.1 meter ∆L=0.02 meter Area =10^-6meter^2 mass = 5×10^-3kg volume =10^-7 meter^3 Force = 100N and answer velocity = 20m/ s

[@SapnaSingh-pw9uh]

Very good bro its rught

[@medicophilic..learnwithshi8667]

Yes it is right ans👍

[@Priiiiiiiiii65]

Bhai Tera itna complex solution dekh ke mai lecture chorke jaane wali thi....😐😂 Anyways jokes apart....best of luck

[@devilkiller7463]

Right ans 20

[@mahekwadia2625]

Can u tell me u convert g to kg so 10^3 aana chahiye na

[@ravikeideas4355]

Others: 5 lectures in 5 days..... Me: 5 lectures in one day.....😀

[@harshrawat1716]

Great ho 👌👍

[@yash10]

Me 15 lectures in a day😎

[@sanskarrauniyar3265]

F***

[@vedicbhandari8776]

bhai ye syllabus mai hai kya 2021 cbse ke plzz help

[@BrainBoost3699]

@@yash10 really??

[@SumitSingh-by7tp]

Jab physics mein kuch samajh na aaye to kewal physics wallah ke pass jayein

[@jyothiparadesi1647]

Bilkul sahi baat ki hai.... ☺️😊

[@teenisroasting6834]

Mujhe abhi bhi nhi samjha...😶

[@deviladitya2075]

Aur agar jindagi me kuch samajh na aaye to kiske paas jana hai

[@skstarsharif]

@@teenisroasting6834 tumse na Ho payaga

[@Rchang3110]

Ryt

[@jonaswalker2322]

One like for Alakh sir

[@jurigoswami953]

Why to like u??? We'll like his channel

[@satvirsingh9527]

@@jurigoswami953 😁😁😁😁😁😁😁😏

[@maheeadhikari9899]

@@jurigoswami953 yes u r right.....✌️🤣🤣🤣

[@rudrajyotibanerjee5826]

@@jurigoswami953 Right Brother

[@sakshigupta5384]

same answer !!!!!!

[@lakkimavi]

2023-2024 ATTENDANCE DO JALDI!

[@keshavcool5461]

Last question is asked on mains 2019 thanks sir

[@sushilkumarsharma2711]

Sach me

[@keshavcool5461]

@@sushilkumarsharma2711 yes.. I mean the question type was same only numerical values are different

[@sushilkumarsharma2711]

@@keshavcool5461 yes

[@malaysinghbisht3103]

Bhai konsa college mila?

[@vishallodhi7096]

@꧁༒DR DALA ꧁༒ omg

[@carguy7480]

Timestamps: 1:00 formula 3:00 derivation

[@tony7835]

Me in examination room while drawing FBD of wire Turuuuuur turrrrrr.....ikaaaa......turr . Everyone:. 😑

[@shiva.g2076]

Marshmello Official 😂😂😂😂

[@memesteraliya8176]

😂😂😂

[@vikramsingh8738]

🤣🤣

[@RAJBPATEL1]

At 7:17

[@jayyadav7583]

🤪🤪🤪🤣🤣

[@nirakadhikari4741]

nobody in the world can teach like you sir . respect for you

[@harishrangra8096]

answer to the question is 20 m/s first find force by formula of- young's modulus =FL/AdelL Then find potential energy by the formula in video then use formula Potential + kinetic=Potential + kinetic(kinetic in Lhs=0 and kinetic on RHS = MVxV/2 there you go

[@siddharthsagar3221]

Sir the answer is 20m/s. I have gained confidence in physics just because of you, thank you sir ☺️❤️

[@pikurazz-zu8mo]

Solution

[@pikurazz-zu8mo]

Mere se nhi hua

[@billionairemania]

@@pikurazz-zu8mo potential energy stretched wire = ke of that rubber =1/2*kx2=1/2 mv2

[@jony-v7x]

BROTHER CAN U TELL ME WHY HE AGAIN MULTIPLIED L/L

[@uniquegamingff3343]

​@@jony-v7xL/L gives value 1 so the following derivation does not change if we multiply whole by L/L ..and then gamma × ( area × L) (∆L/L)^2 × 1/2

[@srinivasreddy6835]

Sir.i am one of the biggest fan of physics wallah. Thank you very much sir.

[@sachin5633]

me too.......

[@dhairyachauhanbhardwaj4717]

sir ans. is second option that is 20 m/s

[@ayushgtm]

Numerical Answer is [b]- 20m/s

[@rehman3692]

Kaise?

[@jacksparrow9399]

Ha bata

[@ayushgtm]

@@jacksparrow9399 sab kuch de rkha h fir bhi nhi kr paa rha h kia dekh, vol=area*length(org) Convert it into meter. Convert krke vol=10·⁸ 1/2*(5*10⁸)*(2/10)²*vol=1/2*5*v². 1/2,5 will cancel out. V²=400 aayega V= 20m/s

[@ayushgtm]

@@rehman3692 check above solution👆

[@nishatripathi7156]

@@ayushgtm bhai vol. 10 ki power-7 aayega 1mm square =10 ki power -6 m and 10 cm original length which is 10 ki power -1 metre multiply and volume = 10 ki power -7 m

[@wcc3zone960]

20m/s is the correct option sir. Thanks pandey sir for sharing your knowledge.

[@aminaakhter3334]

20 cm per s

[@NitinGupta-fu8uy]

20 m per sec

[@SaniyaJaineet]

2024...main bhi ye video..peak per h....omg....❤😮

[@royalclassesmarhowrah]

Sahi bola

[@BhavyaJoshi-r6v]

Yoo

[@rajraj-pu5uo]

One more hit film directed by physics Wallah released for students so enjoy😍😍😘😘😘🤩🤩🤩

[@jayantabehera9539]

house full

[@liyakatali8199]

Full superhit

[@megastudiohnk1831]

Superhit

[@foxyari7930]

✍️👌🤙🤚🤞✌️

[@SaloniMai]

Answer of last question ---- 20m/s Solution ----1). Strain = dl/l. = O.02/0.1=0.2 2). Vol= area *lenght= 10*-6. *0.1=10*-7. ( As. 1m*2=10*6mm*2) 3). 5g=5*10*-3kg Now just put it into formula explain by sir ❤ 🎉🎉🎉20m/s ANS😊

[@AmarNath-w7w]

Bro 0.02 kaha se aaya😢..waha to 0.12 n hoga.. pleas explain 😢😅

[@muskanmi941]

It says to find dl (difference)=12-10=2 ​@@AmarNath-w7w

[@AmarNath-w7w]

@@muskanmi941 ooh

[@priyanshiijaiin5384]

Sir you’re doing a very good job by helping everyone and I wish may god always keep you happy and hit like whoever agrees with me

[@aarav.129]

After converting all the values into standard form, U =10^0, =1joule, then equate it with Kinetic energy of missile, we get v^2=√400=20m/s, option b. Thank you. 😇

[@manishbisht7647]

answer : is 20 m/s (take units in meter and also convert 5g into kilogram then put value in formula) make sure :-- [1mm^2 = 10^-6 m^2]

[@pallavikaranwal3944]

Correct

[@revengeroffire6546]

@@pallavikaranwal3944 hi are you in class 11

[@darshemotion15183]

Yess

[@manishbisht7647]

@Mohit Malgaonkar hi

[@manishbisht7647]

@Mohit Malgaonkar yes bro

[@thebigbang4747]

ANSWER OF LAST QUESTION 1/2(5*10^8)(2*10^-2/10*10-2) (10^-6*10^-1) =1/2*(5*10^-3) *v^2 after solving this we get v=20m/s Therefore (b) option is correct

[@yuvraj7258]

Plz explain 🙏🙏

[@pakhi90345]

Thank u so much❤❤❤

[@upasnagupta9804]

L=10cm=0.1m ∆l=2cm=0.02m Area = 1*10^6m^-2 potential energy rubber = kinetic energy of missile gama =5*10^8N/m^2 gama *strain = stress =5*10^8*0.02/0.1=10^8= stress Now, 1/2*10^8*0.02*1*10^-6 *0.1=1/2*5*10^-3 v^2 Now from here v^2=400 hence v=20m/s is the correct answer

[@vigneshnayak3617]

Tq for ur answer

[@combat6480]

Hello friends take W=F/2 *∆L (force is not uniform.so take its average as F/2) Y=F/A*L/∆L : F=Y*A*∆L/L ------ substitute F so ..W=Y*∆L*A/L2*∆L*L/L W=1/2*(∆L/L)^2*A*L W=1/2*(STRAIN)^2*VOLUME

[@hawkeye5611]

*Solution* 1/2*YA∆x^2 / L= 1/2 mv^2 Put all value in metre and the convert 5 g to kg. Ans 20 m/s will come.

[@AhinDas2506]

Thanks bro

[@pratimamishra6785]

Can u pls tell me why we have to convert 5 g into kg?

[@hawkeye5611]

@@pratimamishra6785 to bring answer in SI unit

[@sukdeepsingh7253]

Answer of last question is b.20m/s. Volume would be 10^-7, strain is 2/10 and mass is 5×10^-3,( all are converted into metre from cm and mm and g to kg). On putting values,the answer is 20...😊😊

[@shaizahmed9346]

Can u please say me y u hve to convert gram to kg ???🤔

[@fromnavodaya9403]

@@shaizahmed9346 SI unit of mass is kg

[@sarveshchoudhary2312]

Tq bro

[@sarveshchoudhary2312]

Tq bro

[@ZakirKhan-zu1mt]

Great has no limits As you have no limits of teachings So you are great

[@drpsychogaming1888]

Ans is 20m/s^2. Strain is unitless So there is no any conversion of cm into m You gyzz understand what i want to say

[@prateekgupta6108]

Bhai volume ka tu hoga

[@fromnavodaya9403]

👍

[@User76515y]

Thanks a lot

[@bishukumardas9114]

Answer to this question is 20 m/s sir.

[@alokkumarsingh8366]

plzzz tell the valuebof strain and stress??

[@ASH_x_007]

@Swapnil Reddy kannada na ri

[@mehulmehta253]

Mera 200 aa rha hai??

[@shivsagarchauhan7644]

Sir apki wajah se mai raat raat bhar jaag kar bina bore hove jaldi jaldi backlogs chapters cover kar le raha hu. Thank you sir 😊❤️💟💗💕💞

[@SWETASINGH-xc9eo]

Bhai tere pas aur koi option bhhi nhi hai isliye tu kar le rha hai agr tum sincere hote to tumhara backlog hota hi nhi 👍👍

[@gurutsavarora6348]

@@SWETASINGH-xc9eo gr8 answer sweta

[@arunavochattoraj5390]

​@@SWETASINGH-xc9eo bhai apna dimag lagana band karo or use appreciate karo gyaan dene ke alawa

[@anushkamaurya7440]

Answer is 20metre/sec . That is option B. Thank you sir for imparting such conceptual knowledge with full focus and fun.

[@richasinha2286]

How ??? Can you explain it please

[@Endlesspath03]

Comments mat padho video dekho

[@kirtisharma9280]

Kon kon tution Nahi padata only alakh sir ke lecture dakhata hai hit like😍😍😜😜

[@BS-yd9xz]

magic life me

[@sushilkumarsharma2711]

Im

[@rohitpal8704]

Me also ❤️

[@sks8623]

Mai bhai

[@NishaYadav-dd5bj]

Me

[@kotalifeupdates4953]

Tussi toh cha gayee sir 💛💛💛💛 👍👍👍👍👍👍👍 🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻 💖💖💖💖💖💖

[@YamiSahota]

Your explantion is mind blowing sir. thank you sir . 😀

[@Error360.]

24:30 If some one get answer 200 m/sec then cheak a lenth which you put in volume= area ( original lenth) >>>> cheak this length properly becouse i also made mistake and i learn from my mistake 🦖

[@arshsultanpuri2489]

Sir answer is 20m/s. Thank you sir for making lecturers this fast 😄😄

[@pranjultiwari3494]

Sir blue shirt👌 looking more smart👍👍👍

[@Unknownjddj]

Answer of last question is B.20m/s

[@dhirajkumarsingh9569]

23:00 Correct option is 20m/s sir..❤

[@gouravsoni9164]

Answer of the last question is 20 m/s

[@Smarandas.]

23:03 b) 20m/s

[@hopesalive7619]

Thankyou for this amazing video Sir RESPECT from KARNATAKA...

[@manojpoojary4009]

Ellindha thaaavu

[@shreyaskulkarni4805]

Yelli iddiri taavu Karnataka dalli?

[@Sachidanand-yp6nl]

@@shreyaskulkarni4805 kalaburgi

[@wildspray0758]

Bro navu from karnataka

[@BHUTOUPSC]

Happy Teachers Day 2020 I wish you you are my best teacher our favourite teacher in whole universe

[@saimasheikhsaimasheikh459]

Problem ko door bhagana h to Alakh sir g k Pas aa jao sb k SB aapki pta h sir u are best nd best teacher sir agr ap n hote to mere physics k kyaaa hota u are the amazing teacher keep it up

[@yash10]

Ans of last ques. Y=FL/A.delta L F=YA.deltaL/L F= 10^2 N (taking all in si units) Now u can use sirs formula by P.E=K.E, but I use F=ma F=ma 10^2 = 5a a = 20m/s^2 u=0 V=20 m/s

[@deepakbhutani5259]

Bdia bro👍👍

[@yash10]

@raj editz bro energy stored h and energy transfer karti h from one form to another.... missile m kinetic energy h(bcoz of speed obviously) aur usme p.e h ... To uski p.e => missile ki k.e ke barabar hogi nd tab ke=pe hoga

[@CollegeWithHardik]

I'm In 11th in 2022 but still i watching these old lagendry video's ❤️

[@priyanshichauhan7988]

I am also🙋

[@YashKhandoliya]

I am also here...🙋‍♂🙋‍♂🙋‍♂

[@dathanbm8984]

@@YashKhandoliya mee tooo 😁

[@YashKhandoliya]

@@dathanbm8984😄😄😄

[@YashKhandoliya]

@@dathanbm8984😄😄😄

[@VanshSharma-bl1pc]

sir answer to homework question is 20 m/s. thankyou sir for amazing video

[@supriyapoddar1460]

Yes I also got the answer same

[@mdkalim-bx5oy]

yes its 20 m/s

[@jeetubhaiya7083]

How u all got that, mine coming wrong.

[@AdityaRaj-wt7yl]

Can you explain the answer

[@dakshitshringi4910]

Hello vansh were you in D.A.V. public school kota

[@avijitghosh2718]

ans is option-B

[@harshit51778]

Answer of last question is 20m/s... L=10×10^-2, ∆l=2×10^-2, A=10^-6 and m=5×10^-6..... Put in formula

[@mahmed27]

The answer of the question is 20m/s. What a wonderful explanation !

[@eshachauhan348]

Answer of homework ques is 20 m/s ..🤗

[@aqeelawan1026]

Same

[@eshachauhan348]

@@aqeelawan1026 ☺️

[@anilupadhyay830]

Yep

[@eshachauhan348]

@@anilupadhyay830 😊

[@rajeshgautam8709]

Yes same

[@maze4030]

Answer is 20m/s Thank you sir. ☺☺🙏🙏🙏

[@pinkikiduniya2697]

Mera to nahi aaraha kaise kiya pls reply

[@amishkumar707]

Unit si me lo ans aajayega

[@DASACHIN2003]

From last question , I understand K.E and P.E relation very much . Thank you so much sir and answer of this question is 20m/s

[@beautygupta2135]

Plzz explain how it is 20m/s

[@rajuljadaun6390]

Last day of 2020,I survived this year watching alakh sir vodeos

[@prasanuniyal9647]

I am also here.... 🙂🙂

[@hajikasana3216]

"Not ker liya mitar de " I like this dialog of alakh sir very much😊😊

[@Harsh_tandon]

thanks a lot for teaching in such an amazing way sir. you help us a lot to be honest more or rather much better than our tution teacher. Thanks a lot sir. answer = 20m/s

[@obaid6284]

@kunalkins no that's root 400 so answer is 20m/s

[@shaguftasiddique8001]

Answer is 20m/s Correct option is B Thnank u for this amazing vdo👏👏👏👏👏💖💖💖💖💖💖💖💖💖💖💖😍😍😍

[@Mr.Pupeteer]

At 11:36 sir told upar niche 'L' Laga do... Sir hamare 'L' pehle se hi Lage hain.......,👍👍👍😀😃😃😃😀😀

[@jethalalgada5]

😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂

[@Mr.Pupeteer]

@@jethalalgada5 hi bro how's is your study going ??😄😀😀

[@jethalalgada5]

@@Mr.Pupeteer Hi😉 Acchi chal rahi he. Tum batao. Waise ham log ek dusre ko jante he kya🙄

[@anantvinayak11]

@@jethalalgada5 are haan tum jethalal ho😆

[@anantvinayak11]

@@jethalalgada5 tumko pura duniya jaanta hai

[@ektalohchab22]

Sir by your bestest efforts now I love studing physics ... thanks sir

[@divakarranjanarya1754]

23:04 answer is 20m/s....

[@meowworld6054]

Sir aapka newspaper me photo aya h usme likha h no. 1 neet ki tayari karane ki best coaching

[@satyanarayanvaishnav8031]

Where where

[@harshitsrivastava3662]

Answer of homework ques is 20 m/s . Your way of explaining the things is just amazing 😊 ....

[@nikhilthevlogger618]

Bhai... Just like a Gullel😅 Jo bhi potential energy hogi rubber ki bo apni energy us Missile ko de dega and bo missile ki kinetic energy ban jayegi... Bas conservation of energy

[@himanshubamola3248]

Correct answer of last question is 20 m/s you just convert (mm)^2 and cm to m .(mm)^2 = 10^-6 m then you can easily solve question

[@vivekpatel7452]

22:6 ans is = option b (. 20 m/s ) July 15 2023 Thank you sir ☺️☺️☺️

[@KarunaPrajapati-v1p]

Physics mujhe bahut pasand thi jab tak mein alakh sir se nhi padh rahi thi ab jab meine alakh sir se padhna chalu kiya h toh mujhe physics se pyar hogya h

[@kanikmittal]

no teacher in this entire ERA I can find who is better than you sir....... Love you Alakh sir..

[@soniaazmi4653]

You are such a great man really.... Thnx sir for give us your knowledge💯📖📚📝...

[@anwesha725]

Lots of grammatical error in ur sentence...

[@sanchit5181]

@@anwesha725 💀💀

[@krishnangshuchatterjee7049]

Sir your teaching is very easy to understand. I appreciate your work. I hope your channel becomes very successful.

[@SHoRtCollection7]

Aree Bhai itna Jada successful hua ki ab admission hi nhi le sakte

[@RakeshKumar-uq7my]

Correct answer of homework question is option b 20m/s.. ∆l,l, A ,m are required to be changed to standard units... Metre, metre, metre square, kg ... Respectively

[@nisharathore8754]

Answer for last question is 20 m/s. Thank you sir 😁😁👍🏻👌🏻👌🏻👍🏻.

[@parasahuja2815]

Thank u sir for making videos at such a pace keep it up lv from punjab 👌👌👍👍

[@prajapatitechnicalpoint]

Velocity = 20m/s

[@albinmathew9189]

Nope 15/3 m/s

[@prajapatitechnicalpoint]

@@albinmathew9189 no , the answer is velocity 20m/s

[@sunnyarya8406]

@@prajapatitechnicalpoint 20 h bhai

[@PriyaSingh-vk3yj]

Answer of last question 20m/s And yes admitted you're the best physics teacher I've ever got

[@gaganreddy5002]

24:00 Answer: b) 20m/s

[@princegreat5102]

12:51 15:16 20:29 23:48

[@himadribanik4867]

Last question solution:- 1/2 × Y × (strain)² × initial volume=1/2 × mv²....now putting the values we get v=20 m/s....thank me later...

[@khiroodlukhurakhon1625]

Thank you ❤️

[@idyllicc547]

mera exact 20 nhi aaya pr 20 k aaas pss tha thats why i clicked 20 .....thik kiya kya????

[@himadribanik4867]

@@idyllicc547 yap

[@nibeditaswain6985]

Answer of the last qs (Option B - 20m/s).

[@kajalmishra5963]

Right

[@Amitsingh-pe3vn]

Mass 5g=5×10^-3 hoga. Mass ke jagah 5g rakhne par ans 20m/s aa raha hai

[@TheIskconTimes]

Mass ko gram me rkhna hai?????

[@kajalmishra5963]

@@TheIskconTimes thanks

[@jaismineagarwal2767]

Sir's lecture will never old like hcv✌️😎

[@revengeroffire6546]

Hi are you in class 11

[@missrajput6524]

Answer is 20ms-¹ Thankyou sir ❤

[@devvratdubey222]

Answer sir 10√5 which is approximately 20m/sec 🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏

[@aaryana7160]

thank you for the class it's really amazing 🙏 itna hard concept itni aasani se samjha diya

[@vineetmangalraw8809]

Yes

[@beingkashmiri8150]

Respect from Kashmir sir

[@rahulnegi8395]

Again you solve my problems related with this text. Your teaching style is excellent. Thanks a lot

[@SujaanveerYadav]

Alakh sir is best teacher in the world.. ❤

[@IshanKarmakar-js1se]

Answer to last question is 20m/s^2 EXPLANATION: Lenght-10^1m. STRAIN- (2*10^-2/10*10^-2)^2=(1/5)^2=1/25 AREA-1mm^2=10^-6m^2. VOLUME- 10^-1*10^-6=10^-7m^3. Mass- 5gram= 5*10^-3kg NOW, 1/2*Y*STRAIN^2*VOLUME=1/2*mass*velocity^2 OR, (1/2)*(5*10^8)*(1/25)*(10^-7)=(1/2)*5*(10^-3) VELOCITY^2 OR, 10^(8+(-7)-(-3))*(1/25)=VELOCITY^2 OR, 10^4*(1/25)=VELOCITY^2 OR, VELOCITY=10^2*(1/5) OR, VELOCITY=20m/s^2

[@amansidhu5356]

I'll be in +2 soon so sir g +2 ch tuc hi saath de dyo , 😁best teacher ever

[@abhimanyuyadav1344]

Ans of homework question is 20m/s

[@anueswar3639]

2024 attendence please 😊😊

[@Skentyedit]

Happy Birthday, Alakh Sir! 🎉 Your dedication, passion for teaching, and ability to simplify the toughest concepts have inspired countless students.(including me). Wishing you a year filled with success, joy, and endless opportunities.❤

[@Kundan_Rathore_450]

20m/s answer23:24

[@kritikasapra241]

Thank u so much sir🙂🙂 U lectures r amazing I enjoy studying physics....

[@Nitesh..k20]

🤟