Class 11 chapter 6 || Thermodynamics 12 || Gibb's Free Energy IIT JEE MAINS /NEET | Spontaneity |

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Live Classes, Video Lectures, Test Series, Lecturewise notes, topicwise DPP, dynamic Exercise and much more on Physicswallah App. Download the App from Google Playstore ( bit.ly/2SHIPW6 ) Physicswallah Instagram Handle : instagram.com/physicswallah/ Physicswallah Facebook Page: facebook.com/physicswallah Physicswallah Twitter Account : twitter.com/PhysicswallahAP?s=20 Physicswallah App on Google Play Store : bit.ly/2SHIPW6 Physicswallah Website: physicswallahalakhpandey.com/ LAKSHYA Batch(2020-21) Join the Batch on Physicswallah App bit.ly/2SHIPW6 Registration Open!!!! What will you get in the Lakshya Batch? 1) Complete Class 12th + JEE Mains/ NEET syllabus - Targeting 95% in Board Exams and Selection in JEE MAINS / NEET with a Strong Score under Direct Guidance of Alakh Pandey. 2)Live Classes and recorded Video Lectures (New, different from those on KZbin) 3)PDF Notes of each class. 4)DPP: Daily Practice Problems with each class having 10 questions based on the class of JEE Mains/NEET level. 5)Syllabus Completion by end of January, 2021 with topicwise discussion of Last 10 Years Problems in Boards, JEE Mains/NEET within Lecture. 6)The Complete Course (Video Lectures, PDF Notes, any other Study Material) will be accessible to all the students untill JEE Mains & NEET 2021 (nearly May 2021) 7)In case you missed a live class, you can see its recording. 8)You can view the videos any number of times. 9)Each chapter will be discussed in detail with all concepts and numericals 10)Chapterwise Approach towards JEE Mains/ NEET & Board Exams. ****Test Series for XI & XII**** We provide you the best test series for Class XI,XII, JEE, NEET chapterwise, which will be scheduled for whole year. The test series follows very logical sequence of Basic to Advance questions.& Evaluation of Test and Solution to all the questions at the end of the test. Class 11 Chapter 6 | Thermodynamics Introduction | Reversible and Irreversible Process IIT JEE /NEET kzbin.info/www/bejne/p2ami4ikqLyej7M Class 11 Chapter 6 | Thermodynamics 02 | Heat | Concept of Cp and Cv Of Gas | IIT JEE /NEET | kzbin.info/www/bejne/jGSmf6l8iMlnqJo Class 11 Chapter 6 | Thermodynamics 03 | Work Done by a Gas | Work Done on a Gs | IIT JEE / NEET kzbin.info/www/bejne/onPYXoaAfbOpm6M Class 11 Chapter 6 | Thermodynamics 04 | Work done in Isothermal and Adiabatic Expansion of Gas kzbin.info/www/bejne/mImxqXV8d8uqoNU Class 11 Chapter 6 || Thermodynamics 05 || First Law Of Thermodynamics IIT JEE /NEET kzbin.info/www/bejne/gWLTf52BfdJ7bqc Class 11|| Thermodynamics 06 || What is Enthalpy || Relation between Enthalpy and Internal Energy || kzbin.info/www/bejne/i6a3Yn-EpZqGgLs 11 chap 6 | Thermodynamics 07 || Heat of Reaction | Enthalpy Of Formation | Enthalpy Of Combustion kzbin.info/www/bejne/hamqdoxjrsmioM0 Class 11 Chapter 6 | Thermodynamics 08 || Hess's Law || Hess's Law Enthalpy Change IIT JEE / NEET | kzbin.info/www/bejne/rafRhJKuosuFkMU Class 11 chapter 6 | Thermodynamics 09 | Second Law Of Thermodynamics Introduction | IIT JEE /NEET kzbin.info/www/bejne/l2imqXp3a9aEhqc Class 11 chapter 6 | Thermodynamics 10 | What is ENTROPY ? | Spontaneity and Entropy JEE MAINS /NEET kzbin.info/www/bejne/hJelY5aeqbisY6s Class 11 chapter 6 |Thermodynamics 11 | Entropy of different process | How to find Entropy JEE MAINS kzbin.info/www/bejne/lau8k42PYsyNj9k Class 11 chapter 6 || Thermodynamics 12 || Gibb's Free Energy IIT JEE MAINS /NEET | Spontaneity kzbin.info/www/bejne/pqevnoqwaNmKsJo

[@Ronik_thakur]

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[@Ronik_thakur]

Sir plzz 12th class ka bii start krdo sir hmmm sbii baccho ka future apke hatth mai hai

[@sushilsarkar5865]

Sir organic chemistry kab start hoga?

[@dilkiawaaz2491]

Please make video on log table.

[@aryanjain4191]

Sir plz General Organic Chemistry class 11 shuru krwa dijiye na jldi se. Plzz

[@sijjumaddela8717]

Rxn is in equilibrium 38:44 As we know T>dH/dS (then reaction is in spontaneous) Here 40.63kJ/mol then it is =40630 J/mol dG= dH -T(dS) = 40630 - 108.8 × 373.4 = 40630 - 40625.92 = 4.08 Here dG > 0 Then reaction is non feasible

[@nehawankhede5205]

Thank you

[@015priyamvadakumari8]

40.63 - 40.62592 = 0.03 hence ∆G = 0.03 means ∆G greater then 0 ans is b

[@nikitakumari1804]

@@015priyamvadakumari8 approx lenge... reaction eqm pr hoga

[@015priyamvadakumari8]

@@nikitakumari1804 nhi toh

[@abdurrafiquemollah8867]

It should be-4.08

[@madhushreesarkar8013]

Sir, I am a graduate enrolled in MSc now....and as the video is progressing....my regret is also growing... remembering the time when I used to struggle so much during my high school days with these topics and finally sat for my 12 boards leaving these topics. It would had been so good if I would have watched your videos then. You are excellent sir.... these topics are almost of no use to me now, as my subject is life science; but still I am watching each and every video on the topics that I once left in class 11 and 12 and those concepts remained boxed until now. I am watching these just for my own satisfaction. Once again sir....You are the best , best teacher I have come across till date.😊

[@sagargaur4203]

absolutely correct yrr mai bhi

[@velum6370]

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[@saksham5882]

OMG I cant imagine. So many grammatical mistakes. I mean , thanks for making me realize how much of English I actually know(LOL).

[@velum6370]

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[@manantaksali9153]

You are ugly

[@namandhuaan5042]

At 38:42 , option b) non-feasible .Since, ΔG>0, ~4.08

[@HINDIMOVIEEXPLANATION-24]

wrong bro it is in equilibrium first you have to convert it in joules

[@namandhuaan5042]

@HINDIMOVIEEXPLANATION-24 bro i gave the answer in joules only ,... also bcoz it is in equilibrium , we know, T>△H/△S (then reaction is in spontaneous) Here 40.63kJ/mol then it is =40630 J/mol △G= △H -T(△S) = 40630-108.8 × 373.4 =40630-40625.92 = 4.08 Here △G > 0 Then reaction is non feasible

[@siddharthjadeja6991]

2 years old but still powerful content 🙏 4 Years now, Thanks for the likes xD

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Not powerful , it is Thanos 🔥

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Koi content purana ni hota h bhai

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Old is gold holds good in this case

[@vineetapal8399]

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Yes

[@poojasingla8039]

Same here

[@Krishasushh]

4 years ago, but still no one can beat his explanation 🫡

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stilll bro

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Hey are these lectures enough for jee adv

[@shubhamsarkar6694]

Yess , for concept, but aapko question solving ability develop karna padega😊​@@Zerya-f1n

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Still broo

[@bb-gb7jv]

Wow! Thermodynamics is the easiest chapter for me now All credit goes to you

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Try thermo mcqkzbin.info/door/F5ie8yBPVZxVAhx8jKWxtg

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Puri series dekha Kya 🙄

[@chaman4208]

Thermo me bas formule bahut hai, baaki kaafi asaan chapter hai

[@CristicMesper]

Yaa bro...... I want to say same thing also

[@CristicMesper]

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[@haroonshaikh369]

Answer at 39:03 •ΔG=40630-[(373.7)*(108.0) •ΔG= 4.08 = +ve •Therefore reaction will non feasible but if small amount of temperature of 4.08K is provided then it can be feasible.😀

[@arpitadeodikar5177]

same answer

[@riddhishete6563]

But the ratio delta H/delta S is coming equal to T then how is it non-spontaneous/ non feasible? Please tell..

[@YouTubeking-qe2yy]

​@@riddhishete6563fisible = possible = -∆G

[@rajkumarmukherjee9588]

Answer is 4.08. So, delta G >0 that implies reaction is non feasible. Correct option will be b.

[@ShivamThakur-fp1uj]

bro..since reaction is not feasible nd it is in equilibrium..means it remains in equilibrium..so option (c) is correct..

[@guddishaw3991]

The reaction is in equilibrium

[@pikachugirl2216]

But my answer is equilibrium

[@guddishaw3991]

@@pikachugirl2216 yes your and my answer is correct ✌️

[@krishthakkar6292]

Yes

[@nabajyotibora001]

38:45 Delta G=+4.08 hence the reaction will be non-spontaneous.

[@Im47_letscrackneet]

Bhai mera 400 ara hai

[@Sachinkumar30952]

👍

[@amancomputer4868]

​@@Im47_letscrackneetkilo joule ko joule me kR ke kro

[@chhavimalhotra9774]

Answer of the question given at 38:45 is (B) : non-feasible. Also, I wanted to thank you Sir. Because of you, I am now confident while solving Thermodynamics questions. The way you make us understand the concepts is on another level. I don't know anyone else who can match that level of explanation. I am deeply indebted to you. May God bless you with all the happiness that you deserve in life!

[@Krishnash1355]

Yes

[@shivasai303]

Kya answer positive 5 aaya kya

[@shivasai303]

It is in equilibrium

[@yashwardhanmalviya9195]

@@shivasai303 no

[@yashwardhanmalviya9195]

Temperature is less than the required so non spontaneous i.e no feasible

[@samarthsingh4453]

I scored 96 in physics and 97 in chemistry thanks physics wala (cbse)👍💝🤗

[@praveensumanpraveensuman1792]

How

[@aatahumai7778]

​@@praveensumanpraveensuman1792 maybe boards?

[@samarthsingh4453]

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[@samarthsingh4453]

@@aatahumai7778 yupp

[@dharmendrakumarsaxena2232]

@@samarthsingh4453 in class 11th or 12th

[@shivamsingh-ek8rl]

At 38:48, ΔG comes out to be +ve i.e., ΔG>0 which means the given reaction is non-feasible. G=+4.05 Joules. :)

[@niladribaksi6236]

Yup

[@helium3983]

No ∆G=-ve As 40630-10880×3734 =-40585290 Which means it is feasible!!

[@kkookkkoo2719]

@@helium3983 nope y'all..it's 108.8 J look properly and it's 40630 J Ans comes to be G is equilibrium

[@PhoenixPlays2]

@@kkookkkoo2719 bro it's non feasible* G =+ve as 4.08

[@kkookkkoo2719]

@@PhoenixPlays2 I don't remember it now lol

[@carl2226]

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Bruh

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Literally😂

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Pls tell me what is meaning of *_Lmfao_*

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yaaa

[@varsharani5697]

U r right

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Madaer cheodh u are right

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What are y doing now bro? jee

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No one can think that What he told in last 7 minute- "carbon reduction" ......is asked 2 times in JEE main 2020 in 2 different shifts...... ❤️❤️❤️❤️❤️❤️ A question from direct Notes

[@saatwikreddy9497]

Oh that's great

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Jyadatar que .. Sir ke notes se aate hai agr dhyan se pura syllabus padho

[@naitikupadhyay9438]

Thanq Mai ignore kr diya thq

[@ms-wy6fu]

Video is of 3 years old ... according to that sir has said...but u are also correct

[@Rohtajjeeaspirant2946]

#38:45 Q(ans): (c) होगा, क्योकि T=∆H/∆G है ( feasibility ke liye ∆G

[@dineshbishnoi6315]

3 saal phle sir ne jo content diya Vo abhi bhi powerful content h Thank you ALAKH sir for this content

[@yashpatidar654]

Alakh Sir is one of the best teacher That I have seen in my life Like for this beautiful teaching Always like his video It is only way that we can give him a respect Well done sir Bright future ahead Shine bright 🌞✨💛

[@aim_mbbs_only]

Aapke jaisa koi nhi sir ksm se apke jaisa koi nhi... Ho skta h baki teachers ko apse jyada gyan ho pr uss gyan ko baatna sbse ache tarike se apko ata h... Aisa ek bacha nhi hoga jo bol skta h ki alakh sir ka pdhaya smjh nhi ata.... U r the best 👍💯

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Hard work done by teachers for students always make us postive🤗because they supply energy by -🙏motivation, guide, provide education etc🙏🤗

[@prajyot2021]

At 39:00 option a is correct It is feasible as G

[@studywallah9642]

Re calcute bro

[@madhavmishra8951]

40630-40582

[@ayanbhunia4200]

sahi hai bro G= -40.58529 i.e G

[@AnkitKumar-zh4ou]

Mera b yhi aya h -40.5829 so it is spontaneous 👍🏼

[@arjit5923]

Sir ji aaj toh ek heart or reply banta hai

[@hamnekiya]

Chemistry wala

[@priyanshuraj7834]

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[@kumarsanu4191]

Answer is:Non-feasible(∆G=+4.08) Given in Q.:∆H=40.63kJ=40.63×1000J ∆S=108.8&T=373.4K By applying this formula:∆G=∆H-T∆S We get,∆G=+4.08 #∆G is +ve therefore this reaction is non-feasible/non-spontaneous.

[@aaryan2137]

Delta H / delta S =40630/108.8 =373.4 ( which is equal to T) Which mean (T=dlta H/ dlta S) That is the condition for equilibrium

[@keertiswarnakar1790]

38:38 Here, ∆G=∆H-T∆S ∆G=40.63 x 10³ - 373.4 x 108.8 = 40.63 x 10³ - 40.62592 x 10³ ∆G = 0.00408 We know, If ∆G > O Process is non spontaneous/ feasible. Hence, the given reaction is *non- feasible*.

[@neha-ps7wl]

But ∆H/∆S=40.63x10°3/108.8 =373.4 which is equal to Temperature then the rxn is in equilibrium

[@rabiyahassan513]

​@@neha-ps7wlsame

[@WASUQUOTES]

Feasible

[@skg2763]

😂😂​@@neha-ps7wl

[@asmityadav000]

Doubt

[@tiredcat6653]

The reversible sign doesn't mean equilibrium. We have not been provided the information whether ∆H has been given for forward reaction or the backward reaction, so if you solve for forward reaction and assume ∆H is +40.63, ∆S is 108.8 then you would get G as +4.08. But if you do it the other way round,means you take Ag2O as product you would get G= -4.08. Since we don't know in accordance of which reaction (forward/backward) the data has been provided,the ans, according to me, would be (4)

[@instinct4844]

Itna dimag kese laga lete ho

[@rahulsinghrollno50ee64]

Forward ke liye Diya hai backward me oxidation ho rha hai heat given by system -ve hota lekin positive Diya hai

[@tiredcat6653]

@@rahulsinghrollno50ee64 Yes, forward ke liye hi diya hai. Now that I have practiced a lot more questions ab mujhe smjh aa rha. G=4.08

[@tiredcat6653]

@@rahulsinghrollno50ee64 Btw oxidation is not always spontaneous toh aise assumption hme use nhi krne chahiye. Data is given according to this *Ag2O--> 2Ag+ 0.5O2* so we should solve according to the given data

[@Mahi_757]

​@@tiredcat6653😮

[@teamblueocean6975]

At 38:46 G= +4.08j/mol Reaction-(b)non - feasible

[@allisarmishta4942]

correct

[@teamblueocean6975]

@@allisarmishta4942 thanks

[@RohitKumar.870]

Ans will be equilibrium. ∆H/∆S= (40.63×10³)/(108.8) i.e 0.3734×10³ = 373.4 Which is equal to given Temperature. i.e 373.4 K.

[@abhay.rijwani]

The correct answer is the process remains in equilibrium option c as the exact temperature for equation is 373.4375K and it is rounded off as 373.4 so just put the value of T as 373.4375 ....... it is for those people who got +4.08 as delta G ....

[@baijayantisahoo9603]

Yes & it's reversible also

[@daewanshbansal6173]

The reaction is non-feasible as deltaG is +ve.

[@Mr.noperfectionist]

I got the same answer is it +31.28

[@akashsahu7121]

I got +4.08

[@Mr.noperfectionist]

@@akashsahu7121 lol but being +ve matters

[@akashsahu7121]

@@Mr.noperfectionist hw bhai ji.

[@umesh22]

@@Mr.noperfectionist it's +5.

[@asifikbal2587]

Ans :(c) remains at equilibrium If {∆G∆H/∆S }then the reaction will be spontaneous but the T (temperature) is 373.4K , so that is why the reaction will be at equilibrium 👍🏻

[@bepassionate2026]

How

[@dreammaker2107]

Ur right bro

[@dipanshupandey7064]

no it's correct answer is non feasible

[@prakashroy9772]

Thanks bro your are right,I was confused

[@keyadas6322]

Correct answer c. For reversible reaction delta G=0 so T=∆h/∆s=373.4k

[@dev-lord]

alakh sir is only teacher that didn t ever said to like and suscribe his challen ITS SHOWS HIS GREATNESS AND IMPORTANCE OF US FOR HIM

[@adityaroy1317]

Answer is Non feasible means Non spontaneous..... Thank you so much for the amazing lecture ☺️☺️☺️☺️😌

[@bowtomepsi6302]

at equilibrium no?

[@AayushSinha-er1sj]

It should be equilibrium mann

[@thedamndoor45]

@@AayushSinha-er1sj ∆G≠0

[@dinkarpadghan6480]

@@bowtomepsi6302 40630 Is Delta H and T Delta s is 40626 There's 4J difference So not Feasible

[@vineetgaming5730]

Non spontaneous he is absolutely right

[@kailash4551]

32:20 isko bolte h feel😈, great sir, mere coaching wale to ese relate hi nhi kr pate.

[@kommuravindra1752]

sahi kaha bro

[@exziteplays0001]

17:31 no sir. Your writing is kickass.we can understand easily

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This channel deserves 1M subscribers

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More bro

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We are now at 1/2mil

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No bro this channel desrves 10 M subscribers

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Rohit Mishra jee likne wale 15 lakhs hai na bhai

[@santokhsingh4734]

Thanks sir

[@Curious_swara]

Guys for all those who are confused between option C and B, the correct answer is C- equilibrium.. Try it, putting T=373.4 K And ∆H/∆S=40.63×10^3/108.8 You'll get it. Also in question itself it shows reversible

[@HoraceGudum]

Yes approximation se bhi equilibrium aarha

[@hardjoshi2916]

you are best teacher in the world......... I study only by watching your vedio

[@ggboi1297]

Fail hona hai

[@hardjoshi2916]

Tere baap ki aukat nahi ki fail kar sake

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Me too

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I think you have to work on our English Check out our video spelling, idiot

[@gyanp28]

@@hardjoshi2916 nice reply

[@mohammadaunaisbhat1944]

Dad: kya kar rahe ho??? Me : padhai kar raha hu dad !!! Meanwhile Sir : Tuu hai ki nahiii .... Dad : haramkhor Ye padhai kar raha hai tu.!

[@anovie127ys]

😂😂😂

[@UNKNOWN_16]

Relatable 😂😂

[@ZeeshanKhan-qd1sd]

38:47 ans is (C) at equilibrium apply t

[@skull17377]

Its B

[@ZeeshanKhan-qd1sd]

@@skull17377 can u explain

[@skull17377]

@@ZeeshanKhan-qd1sd delta H is given in Kilojoule so 1)First convert kilojoule to joule 2)then apply T > delta H / Delta S u will see that T is less than Delta H / Delta S

[@ZeeshanKhan-qd1sd]

@@skull17377 got it thnks

[@gauravbhagat2506]

@@ZeeshanKhan-qd1sd because for equilibrium condition is T=∆H/∆T

[@shekharsuman3274]

At 38:46 Required temp. for spontaneity is 373.4375 and the given temp. is 373.4 which is less than the given temp, so its a non-spontanious reaction.

[@chakradityaa9748]

but nearly equal right!?

[@trishasarkar3053]

@@chakradityaa9748 i found the value of delta G, which is coming positive, so it should be non spontaneous

[@Sahil-gb1jh]

Sir answer of homework question is Option B - non feasible As change in G is + 4.08 J / mole ( approx )

[@BaljeetKaur-ks3hu]

Exactly

[@satviksai1738]

delta g ki value kuch aur aa rahi hai +346 approx

[@Sahil-gb1jh]

@@satviksai1738 meri yahi aa rahi hai bhai

[@satviksai1738]

@@Sahil-gb1jh bro process likh sakta hai kya....plz!

[@Sahil-gb1jh]

@@satviksai1738 Non spontaneous

[@izzatamin5997]

for the question at 39:00 delta G = +ve so reaction is non feasible.

[@mohitsangwan2430]

No Bro it is at equilibrium ∆G comes out zero and equilibrium sign is also there in the reaction😊😊

[@god-xm7th]

@@mohitsangwan2430 yes

[@positiveperson789]

@@mohitsangwan2430 yes

[@plazmachazer8023]

Thank. You sir for your amazing work i am in my drop year and i cant explain that how much i needed this thermodynamics lecture Because aaj tak hum kahi se samaj nahi paaye the entropy, gibbs energy etc... Love from west bengal :) Thank you sir

[@sonuGupta-ju5ek]

I'm also bro. Isiliye to har din wait karta hu ki lacture uplode ho wo bhi thermodynamics ke upar.

[@marvelseries5457]

plazma CHAZER

[@plazmachazer8023]

@@sonuGupta-ju5ek yep brother ...

[@shreyagowdaabuddingdoctor7898]

All the best bro for your neet exam as a 12th studying student i know how challenging the situation will be while studying for neet and u have to prove yourself

[@tiredcat6653]

I literally commented the same thing. Very few people have the knowledge of this chapter and Alakh Sir is one of them.

[@binay3347]

At 32:20 sir if T∆S > ∆H then it would be non spontaneous because non favourable condition is greater than favourable.

[@firefree9526]

Yes u are right

[@rai-here9090]

When T∆S is small

[@binay3347]

Hello friends I think you can also understand it like, in this case sir remark ∆H as a favourable so for spontaneous process it must be Exothermic so temperature must be lower than ∆H/∆S. Not greater than ∆H/∆S. What's your idea about it.

[@ubaidinamdar9535]

@@binay3347 for spontanity the overall value of dG should be -Ve So TdS must be greater than dH i.e T should be greater than dH/dS

[@binay3347]

@@ubaidinamdar9535 but for that particular condition sir given that ∆s itself negative.means unfavourable. Therefore for the spontaneity |∆H|>|T∆S|

[@aaryangarg1938]

38:45 Answer is (A), The value of G = -27 j/mole, Thank u Sir

[@nandurajiv1243]

B is correct.u r wrong

[@aaryangarg1938]

@@nandurajiv1243 How

[@nandurajiv1243]

@@aaryangarg1938 delta G will be +4.08j/mole.. so B is the answer

[@aaryangarg1938]

@@nandurajiv1243 show me your calculation, plz

[@ranjeetkasana3535]

Mera answer h Delta G =+4.08 J/mole.. Hence, non feasible... 😊😊

[@souravsharma5465]

Mera ni aya..

[@kshitijtarende1096]

Mera bhi aya

[@Future_iitian_]

38:47 c remains at equilibrium

[@gaganreddy5002]

39:00 Answer is C). Remains at equilibrium

[@rohan_n_out]

@Om Patil nope ....he is correct

[@ajaygojiyadadubhai755]

It is non feasible reaction... Delta G = +4.08

[@pavansai5513]

@Om Patil no bro check your calculations

[@ndalover_hindustanjindawaa3226]

Wrong

[@ndalover_hindustanjindawaa3226]

Ans is Non Feasible

[@entertainmentenjoyfunny6770]

*Thank you so much sir this topic is very important for class 11 and 12 also*

[@sonuGupta-ju5ek]

Bhai 12th me kaise. Because mai bhi abhi 12th me hu

[@entertainmentenjoyfunny6770]

sonu Gupta Bhai chemistry me Chapter Electrochemistry and Polymersaur bhi kahi organic ke chapters me ye theory ka kafhi use Hai

[@sonuGupta-ju5ek]

Okk & thanks....

[@snsingh7528]

Entertainment enjoy funny sszz

[@heksqer1022]

@@sonuGupta-ju5ek In metallurgy and metal extraction, there is this part called Ellingham diagram, that part needs some prior knowledge of thermodynamics GIbb's constant. And Electrochemistry and Kinetics use the equation G = -RT ln(K)

[@babitagoswami352]

38:48 The reaction will be non spontaneous ( ∆G>0 ) *Non feasible*

[@ravinain3766]

Yess

[@niteshpandey3892]

Yes ∆G>0 Non-spontaneous , non-feasible

[@crazymusafir5088]

4 years old but no less than live interactive classes for students till date....Thank you so much sir for implanting in me a huge interest for this chapter....

[@AyushPandey03]

38:50 Mera to do answer aa gya😁 non feasible bhi aur remains at equilibrium bhi😎 When I used ∆G = ∆H - T∆S 👉 Non Feasible And again I found T = ∆H/∆S 👉 remains at equilibrium

[@GURBANISTATUS_]

∆G= ∆H-T∆S Pe to ∆G=-ve aa rha h to feasible hoga n?

[@xihadimran1600]

Which will be the answer?

[@raghavagrawal5111]

@@GURBANISTATUS_ negative nhi zero aa rha hai Wahan 40.63 KJ diya hai Answer c hai

[@usharaothotakura7557]

∆G=∆T-∆S ∆G=40.63-(0.1088)(373.4) =40.63-40.62 =0.1 =0>0.1 So the reaction is not spontaneous or not feasible (Convert 108.8 J into KJ)

[@ThanksFor3Ksubscribe]

Hii If T=dh/ds Then this process will be at equilibrium See now T=373.4 Which is equal to dh/ds=40630/108.8=373.4375=373.4 So finally answer is a Option C Process 😊remains at equilibrium

[@Kanchan-s-q7s]

Your ,answer is not correct watch point you had given to your equation properly

[@soyaa5817]

@@ThanksFor3Ksubscribe WRONG .....

[@harisindhu704]

(c) at equilibrium is correct as if we check the value of ratio of delta H to delta S , it is equal to the given temperature value=373.4.

[@nancysingh174]

No bro the ratio comes out to be,555.42. so T is smaller than delta h/delta s, means non spontaneous

[@arpitsuman4010]

Pranam guruji🙏, 38:42 - Answer is b) Non-feasible because ∆G = 4.08 (after calculation), so ∆G > 0, therefore not feasible

[@deepabishtcreator3735]

It will be 47. 6 you might forget to multiple heat with 1000 because it is in kilo joule otherwise your answer is correct

[@vaibhavjain1914]

38:51 answer would be B) non spontaneous as △G is 4.08J/mole

[@sashwatrana4573]

yes you got the exact ans

[@kajals.8780]

Same answer

[@duelist8637]

how is g 4.08 ?

[@pcm3568]

@@duelist8637 just use ∆G=∆H-T∆S Where ∆H=40630J , T=373.4K , ∆S=108.8J Hope it helps....

[@duelist8637]

@@pcm3568 yea but what was the calculation i am getting different value

[@SeemaSingh-oi6ry]

38:45 answer is option B) Non-Feasible with 4.08

[@thousandminusseven3889]

@PICASO ENTERTAINER but 40630 divided by 108.8 is coming 373.4375 so shouldn't the reaction be equilibrium

[@goutamdawar1m736]

Option 'C' equilibrium 38:45

[@thebradlad6215]

How plz update me...

[@goutamdawar1m736]

@@thebradlad6215 H/S is to temperature

[@anirudhmsomeshwara]

sorry but the correct option is (b)... because ∆G=0.004 not 0 therefore the reaction is non feasible👍

[@SachinSinghpw]

Who still loves to watch alakh sir old videos ❤️❤️🔥🔥 👍👍👍👍

[@vinitabhardwaj]

Bro do u know me?

[@manaspremi37]

Meeh

[@SachinSinghpw]

@@vinitabhardwaj yes

[@vinitabhardwaj]

@@SachinSinghpw hehe hi

[@TrainMania_12]

Are you from Aligarh

[@rishabhjha4304]

38:55 answer- (b)

[@buddy8998]

equilibrium Condition bro

[@deadcindrella1296]

It's equilibrium

[@rashwonsingkai7955]

It is at equilibrium.... See{ delH/delS} = 373.4

[@aditipatil957]

Answer is b) Reaction is non- feasible ∆G = +4.08

[@parveenvij1830]

More Mcq kzbin.info/door/F5ie8yBPVZxVAhx8jKWxtg

[@ravinain3766]

Yes

[@kumariallu6766]

Value of ∆G is 4.08 J/ mol since ∆G is positive hence the reaction is not feasible Ans.b)non feasible

[@akashjaiswal2032]

Reaction is in egulibrium bro Option c is correct

[@deepika1050]

@@akashjaiswal2032 yes bro same here..

[@kunwar1163singh]

yes bro even i m getting not feasible

[@parveenvij1830]

kzbin.info/door/F5ie8yBPVZxVAhx8jKWxtg

[@Madeeha_shinkoko]

@@akashjaiswal2032 delH/delS is greater than T so yes, the ans is b

[@8c.riteshgope.329]

38:49 : it remains at equilibrium

[@madhusingh8564]

answer of the question is b)non-feasible. Thank You Sir for teaching us.

[@nitinbodkhe9874]

The ans is C that is remain at equilibrium

[@ashokaggarwal8727]

The correct answer of numerical is: b) non feasible Hit👍 like who got same answer Comment who got different

[@alipbhaumik6242]

It would stay in equilibrium

[@random_2016]

c.) remains at equilibrium ∆H/∆S = 373.43K

[@shivamtalokar272]

@@alipbhaumik6242 भाई कैसे रहेगा क्युकी del G examining 4.08 Bach Raha hai Del G = del H - T del S = 40.63*1000- 373.4*108.8 = 40630-40625.92 = 4.92

[@alipbhaumik6242]

@@shivamtalokar272 see...ur i have taken it out by the ratio process and the the value of the ratio del H/del S came 373.4375...thus i took the first digit without rounding off and del T came equal to del H/del S...if u also multiply 373.4375 with the entropy 108.8 the value Del G would be zero..so it was just a confusion based numbers after the decimal

[@shubhangichaudhari8672]

Sir I'm really your great fan. Your teaching techniques are fabulous.

[@Shru17]

38:50 question answer (b) non feasible. Explanation : ∆G=∆H-T×∆S = 40.6 × 10^3 - 373 × 109 . = 40600 - 39657 = +ve answer will come. Hence process is non spontaneous / non feasible. ( I took the value approx)

[@p.j.h2401]

38:55 b) non-feasible

[@utube5452]

Your answer is wrong .Actually Temperature should be greater than 373.4 K for a reaction to be spontaneous And since temperature provided is exactly 373.4K Therefore the system will remains at equilibrium .

[@cosmichorizon405]

3, years previous lecture but the vibes is always exclusive❤️❤️ 💓Alak sir 🇧🇩

[@shakiibbbb]

Yaaa

[@m.sadikshaikh7687]

East or west Alakh Pandey sir is the best 😀😀😀😀😀

[@manojsharma215]

Best

[@poojaroutray2699]

Sir u are great....

[@narvadachauhan9500]

Y east y west he is one of the best

[@divyanshsharma4635]

Yes that's the fact. He is legend.

[@suraksharawat7542]

He is not one of the best...he is the only best🌼

[@adiivibes9766]

Exact answer of 38:44 is Non Feasible as the value of ∆G= +4.08 . (We know that "+ve" Value will be Non Feasible In Change in Gibb's Free Energy)...

[@rozydubey41]

39:02 (🔺️G>0) .....the reaction will be non-spontaneous...as I got +4.08.... Is this right??

[@anubhutipali5033]

Yep...I got the same......👏👏👊

[@MandeepSingh-en8vy]

Yes mera bhi vhi aya

[@amannain7036]

love you

[@criticaldamage2046]

Yes I also got same .

[@amitmanhas4962]

@@amannain7036 bai kon sa nasha krte ho 😂

[@AbhishekPandey-xv7zu]

38:48 in this question Delta G is 4.08 not zero and equilibrium reaction is at T = 373.43 and given temp(373.4)in question is less than equilibrium temp so that's why reaction is not feasible..

[@preetibatra208]

Answer is remains at equllibrium And sir we do not need handwriting we need the concepts which you are giving very beautifully

[@mr.dahiya5816]

No it is reversible so remain at equallibrium

[@Navneetrawal07]

@@DAVE-lf9dv ya u r right

[@Navneetrawal07]

The ans is +4.1 so it is non feasible i think

[@Navneetrawal07]

What's the right ans

[@chanakyaborgohain8850]

@@DAVE-lf9dv yes its not feasible

[@Cosmoscuper]

6 years old but the concepts and way of teaching made this video alive for 100 years

[@arifamushtaq3931]

Thanks sir Bchu ka dard vohe smjta h jisne apni life mai b bht suffer kiya ho Love from kashmir due to strikes in previous years and now lockdown I was not able to study properly at home and tuition fee is too high but u helped in this harsh time thanks ❤️

[@iubaidkhan]

yes uh are absolutely right we had face a harsh time in our kashmir. this wil affect our studies a lot.

[@vaishnavirathore5266]

Not a celebraty not a player u are the person who is loved every where .... ❤

[@Us1489]

This channel deserves 10M subscribers. Sir aapke wajah se coaching walo ki waat lagne wali h

[@adiivibes9766]

Soon..

[@ViShNu_16]

bro predicted the future lolzzzz xD

[@Jenish1811]

39:03 ans is option c remains at equilibrium 40.63*1000 -373.4 * 108.8 = 4.08J..

[@122manishasahare2]

Perfect example of A perfect TEACHER 💯🔥🙌😇

[@parveenvij1830]

Mcqkzbin.info/door/F5ie8yBPVZxVAhx8jKWxtg

[@kapillakhera6080]

1:40 Agar Suresh aaj itni padhai kar leta to Gibb's Free nahi Suresh Free Energy hoti😂😂😂😂🤣🤣🤣🤣😂😂😂😂

[@rajaryanvishwakarma8915]

Sir, In the reaction: A--> X + Z, bonds are breaking therefore ∆S must be +ve so the term -T∆s is -ve. ∆H is already -ve so the ∆G should be -ve at all temperature. Can you tell me where am I getting wrong becoz I dont we can assume in that reaction that the ∆S is Positive

[@mudrikagupta7408]

Is it necessary that entropy increases when bonds break?

[@rajaryanvishwakarma8915]

@@mudrikagupta7408 I think it should, I thought about it as my teacher solved one question using this in class ,giving reason that breaking of bonds increase disorder .

[@harshitsingh4619]

@@rajaryanvishwakarma8915 yes breaking bond increases disorderness..

[@sravanthch2879]

Exactly, even I have that doubt! Hope someone who has the knowledge of it replies here

[@sonit9707]

Raj Aryan Prince par bhai low temperature will favour forward reaction in both cases hence making it the most appropriate ans

[@oneshotgamer2530]

Sir the question is at 38:40 sec which answer is approximately +5 so the answer is non-feasible which means non-spontaneous because ∆G=+5(approx) when∆G is (+ve) then the process is non-feasible. Thank you so much sir for this mind blowing concept ❤.

[@saptarshibhattacharya]

Everybody has commented aboit how good the video and Alakh sir is but very few people have actually given the answr which sir asked at 38:44 This shows the ratio of the number of students appearing for NEET or JEE to the number of students getting selected

[@saanviiaintokayy]

khud tmne kiya??

[@saptarshibhattacharya]

@@saanviiaintokayy Haa bhaiya....maine to kiya 2 weeks pehle....btw, plz bless me that I crack the NEET exam inshallah

[@pahadiarmylover8903]

∆G>0, so reaction is not feasible.... I think that is the answer ......thanks sir for this video.. too good for me....Keep smile sir😀😀😀😀

[@namertakaushik4079]

Glt process is spontaneous

[@abhinavshukla5164]

Remainins at equilibrium

[@aryanphalke7830]

Guys Sabse pahle kilo joule Ko joule me convert karo by multiplying it by 10^3 se fir agar hum saari values Ko approx lete hai to ye equilibrium ya fir spantaneous as Sakta hai par agar hum saari values exact le to non spontaneous(non feasible) aayega Like👇👇

[@nikhilmehta641]

@@abhinavshukla5164 yes option c is correct

[@lekshmi8005]

me too getting non spontaneuos

[@aditibhattacharjee2628]

Sir thank you for what you have been doing for us! So will you please check the video at 31:15 where you have divided the inequation by ∆S. But if ∆S is negative you cannot divide the inequation with that term without changing the inequality. Therefore sir if ∆ H and ∆ S are both negative and for the reaction to be spontaneous so that ∆ G be negative shouldnt T be smaller then ∆H/∆S?

[@CristicMesper]

You are saying correct if you know brother so this is better sir have lot of tensions ...... Sometimes he also do some mistake try to understand it self.... (And I don't message this for hurt your feelings but if still you feel bad so sorry)

[@swarnimasawant9854]

Are you still alive?

[@Ooooodash]

27:30

[@IshaniSharmaOfficial]

What are you pursuing now???

[@AsmiBindlish]

Answer of question at 38:41 is option (b)non -feasible as ∆G=4.1 so ∆G>0 Thank you soo much sir😊❤

[@yashaswinis45]

A DOUBT SIR, at 41:22 in that reaction A-->B + X , the number of molecules is INCREASING so well shouldn't delS be POSITIVE, and so there should be NO DEPENDENCY ON TEMPARATURE?

[@X3NOSAMA]

Yes, you are correct brother. Since moles are increasing, therefore disorder is increasing, so delS=+ve. Now, ∆G=∆H-T∆S ∆G=-ve-T(+ve) ∆G=-ve-T So T doesn't matter.

[@armlink8354]

1:57 himanshi reagent 😇😇🤪🤪

[@thewhitecoat4656]

How lucky you are . Wow

[@kartikchhabra4702]

Khush hoja😂

[@mrbotnoob6213]

Khatam; tata; bye; bye; good bye😂😂

[@ambitiousfrog377]

@@mrbotnoob6213 gaya😂😹🤣🤣🤣

[@kajalchakraborty6189]

The greatest example of randomness is to wake up in the morning and started eating 'chuhaa', 'hati', 🤣

[@nitinswami5538]

Unlogical

[@coffin884]

38:48 The Answer is (b) as the answer coming in + . Thanks sir for helping me.

[@paritawanjari658]

Sir I m B.pharmacy student and preparing for GPAT entrance exam for PG ....your videos help me a lot in my preparation.I was sure that anything which I don't get by reading the book it will surely clear by your videos....In coming Months their will be my gpat exam....plz🙏bless me so that I qualify entrance exam...

[@paritawanjari658]

@Tanishq Saini yes

[@paritawanjari658]

@Tanishq Saini Thankyou

[@yatheendrak4563]

During thermodynamics lectures in my clg went like " This is definition of enthalpy and this is entropy and this is gibbs free energy and there are formulas now do exercise prblms " But sir gave us FEEL about thermodynamics

[@lakshmikumarijha8016]

You are encouraging many youngsters to fall in love with chemistry and physics 😃

[@parveenvij1830]

Thermo mcqkzbin.info/door/F5ie8yBPVZxVAhx8jKWxtg

[@pitamghosh573]

It is so surprising to note that when I finished over with class 12, you were yet to born Sir, but though am an engineer today, where on to become so as one, had to learn lots of chemistry but without a cent percent grasp because of lot of unclarity over these fundamentals. I lament why didn't we have the opportunity like these online platform in our times where we could have done away with our classroom teachers to whom we attended to their classes but had taught us quite superficially to get us carried away without completely grasping and loving the subject. Today your videos are giving succulence to our knowledge asset about the world around chemistry and physics. I love learning and so not wasting my time without knowing the subject where I missed them in my student hey days.

[@billionaireboy9323]

Hello

[@dialoguebaaz320]

38:44 As the reaction is given in equilibrium Hence, ∆G=O So, ∆G=∆H - T(∆S) ACC to given values, 0≠40.63 - 373.4x108.8 Hence, the reaction is not feasible.

[@yuvrajsharma653]

Bro H is in kilo joules therefore it will be. 40630-373.4×108.8

[@anirudhraj775]

awsm sir... thank you! I was waiting for this lecture...

[@swarnimasawant9854]

Are you still alive?

[@IshaniSharmaOfficial]

What are you pursuing now??

[@AniketYadav-nr8tn]

38:50 rxn remains at equilibrium

[@Omshashiranjan]

4 years old but still best content you can get ever