Plug Flow Reactor (PFR) Molar Balance Equation // Reactor Engineering - Class 9

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We apply the Molar Balance Equation to a Plug Flow Reactor.
A Plug Flow Reactor is a reactor designed in "tubes" or cylindrical pipes.
We design it for a Plug flow; which is obtained with turbulent flows.
It has an inlet, outlet, generation and no accumulation. Since the process is in steady state, there is no accumulation!
The operation of these reactors is continuous and cheap to invest.
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[@olikaadzalia9129]

Thanks. Ur explain was better than my lecturer

[@ChemicalEngineeringGuy]

olika jalika You are always welcome! I used to have teachers that did not explained at all as well haha... Anyways, hope you like the video and in general my project! Please share the video with your buddies so we get more people in the community and grow faster... and get more material of course!

[@sakshishrivastava6626]

only video which explains how plug flow works on youtube. Thank you so much. It helped me a lot

[@ChemicalEngineeringGuy]

XD Im glad it helped you!

[@camibabyy]

You make learning these concepts so easy and stress free. I cannot thank you enough.

[@ChemicalEngineeringGuy]

You're very welcome! Im glad that you are enjoying it =)

[@ChemicalEngineeringGuy]

I'll be making a course on this subject soon =)

[@azeem25]

You Are "The Guy".Thank You Very Much Sir.

[@ChemicalEngineeringGuy]

Thanks! Im glad you liked it!

[@marleneiv]

Oh my goodness thank you soooo much for explaining this to me! I finally get it!!!!

[@ChemicalEngineeringGuy]

Marlene Beaulieu. Hey Marlene, thank for your comments, I really appreciate them.. I'm happy you liked the video... Thanks for subscribing! I will be launching a course on Reactor Engineering and Kinetics... Stay tuned!

[@al38261]

Thank you so much!

[@ChemicalEngineeringGuy]

You're welcome! thanks for the comment!

[@gauravjyotid.kalita3417]

Excellent

[@ChemicalEngineeringGuy]

Thank you! Cheers!

[@amirmehanhenriksenkhorshid4448]

Hey the CEG thanks for nice and complete clarifying the concepts. I have a small lack of explaining the final term we got for each kind of reactor. ie. what is the interpretation of the volume in the last equation? is that the volume necessary to reduce the molar mass entered of species J to the specific molar mass at the outlet! (btw well done)

[@richardaversa7128]

Molar mass is constant, the F variables are molar flow rates. V is interpreted as the fixed volume of the tube required to reduce the molar flow rate from the specified inlet value to the specified outlet value.

[@richardaversa7128]

For anyone put-off by the calculus gymnastics used in this derivation, there is another way (no offense to Chemical Engineering Guy, that's indeed the traditional way it's done). Take the steady-state GMBE (dropping the j subscript for convenience) F₀ - F + int(0 to V) r dV = 0 and differentiate both sides with respect to V: d(F₀)/dV - d(F)/dV + d/dV[int(0 to V) r dV] = d(0)/dV The first two terms can be evaluated easily by visualizing F₀ as the flow rate at the very beginning of the pipe, and F as the flow rate some volume along the pipe. It should be clear that F₀ is constant (with respect to location in the pipe/volume along the pipe) so d(F₀)/dV = 0, whereas F depends on the location in the pipe/volume along the pipe so d(F)/dV is nonzero. The third term in the GMBE is straightforward to evaluate by the fundamental theorem of calculus ("part I"); just as d/dx[int(a to x) f(t) dt] = f(x), so d/dV[int(0 to V) r dV] = r. Thus the GMBE becomes -dF/dV + r = 0 which yields the design equation dF/dV = r with no need to appeal to infinitely thin slices.

[@ChemicalEngineeringGuy]

No offense taken my friend, actually Im glad you point other way to do it, its all about understanding and there are many approaches to do so! Thanks for your comment Richard!

[@daniyard2012]

Hey . Thanks for good explanation, I am not good at differential equations. Could you please explain what the division of Change in Flow rate across control volume by delta V mean in simple words? What kind of transformation it brings? Do we analyze it then at level smaller than delta V? Thnaks.

[@ChemicalEngineeringGuy]

Well, the change in flow rate depends only in the "x-axis", that is, length. Then, if we relate to an area, this will be volume. Thats why dF is related to dV, for every change in volume, there is a change in flow rate of species "i"