Practice 10.9 || Thevenin's Equivalent Circuit || Dependent Source

[@Vintage162]

thanks sir

[@ElectricalEngineeringAcademy]

Welcome dear.

[@fozayel999]

Thanks a lot sir

[@tulangakingkababayan143]

you have a step by step solution in the @node 2 ??? specially how (V1-V2)+20(8+j4)+(V1-V2)(1.6+j0.8) become V1(2.6+j0.8)-V2(2.6+0.8)-20(8+j4) ????

[@ElectricalEngineeringAcademy]

Just open everything and re-arrange. Last part is not -20(8+j4) rather 5((8+j4)