Practice Problem: Calculating Equilibrium Concentrations

[@michelcoil1882]

At 49 I still love Learning.

[@MySSS03]

thank you for the video, however it would've been really helpful, if step by step shown for the last part calculation. Would be great help for new beginners.

[@GeminiLeo2305]

Yeah. i'm stuck on that

[@toho5198]

U guys still need help with it?

[@colesherborne3631]

@@toho5198 yes

[@toho5198]

@@colesherborne3631 well you have to do it in steps. First you cube 2.09 since it has a 3 indice. Then you times that by 4.26. Now since this value on the right is being divided by nh3 as it is on the bottom, you have to times it on both sides to cancel it out. So you times that value by 0.006. Hope that helps!

[@sophiamaccalester412]

@@toho5198 thank you for explaining… my guy first just said “with a little arithmetic” like we aren’t here for math help

[@azadprasad856]

Congratulations professor Dave for becoming a father!

[@AmigoGabe]

thank you! im trying to remember some of this stuff from last year, but what do you do if an equilibrium for a certain molecule comes up as a negative number???

[@carolinepodolski]

What if I am not given the concentrations numbers (4.26) & (2.09)

[@snipermilar9734]

wow...this method is so easy...the one we're taught in book is too long n difficult to understand..hope my teacher won't reject this method

[@slstats7948]

Nice❤️🤗 From Sri Lanka 🇱🇰

[@carlosshennlopeziii2724]

How did you get 2.33?

[@Rxn836]

Multiply the .06 by the reciprocal of the denominator which is (4.26)(2.09)cubed over one

[@marrycarrr]

Where did u get the 4.26 and 2.09 M? I can't understand

[@carolinepodolski]

I also want to know this

[@alfredoparrilla9508]

This is still useful to this day

[@hansmorales4802]

so how did u get [NH3]^2= 2.33??

[@cannibalpotato7492]

You multiply 4.26 x (2.09)^3 and then multiply it by 0.0600

[@reagananderson7874]

@@cannibalpotato7492 thank you so so so so much! i was so confused XD

[@استغفرالله_واتوب_اليه1]

@@cannibalpotato7492 thxxxx

[@layshaaybar9126]

@@cannibalpotato7492 the result is 23.3 not 2.33 so I'm confuse

[@msabbasi01]

Professor it's easy for me to calculate those values but I don't understand how to solve its units to get moldm‐³ as its unit. Could u please explain that?

[@amtulbasit7295]

Love the intro

[@kellydonchi8577]

well you said "now just a little bit of arithmetic" well what is the arithmetic :-)

[@begmuhammethajyyew]

2.09 raised to its 3rd level then the product is multiplied by 4.26 and again the last product is multiplied by 0.06,

[@kianarosario5723]

where are you getting 4.26M for N2?

[@YouTubeTutor7]

hypothetical values

[@theredmonkey236]

What if you're just given Ksp?

[@moomenpervaiz]

Very important videos sir These videos are like Cadberry small pieces large Taste

[@ibrahimjklahai3781]

Please me to solve this problem "(a)The masses of certain pharmaceutical have a mean value of 4 g with a standard deviation of 0.2 g. Assuming that the masses are normally distributed and a pharmaceutical is chosen at random, what is the probability that (i) it has a mass between 3.55 and 3.85 (ii) differs from the average by less than 0.35 g (b) If 1000 of the pharmaceutical from (a) above are taken, how many may be expected to weigh more than 3.7 g?"

[@josephsisay5373]

if u solved it could u comment the answer please

[@SonnenLyfe]

yeah a little bit of arithmetic would be pretty important don’t ya think 😂

[@NzenwataDavid-so4hw]

It's just multiplying 4.26 by 2.09 and 0.06

[@hoh1113]

Thank you so much you helped me

[@akashsunil7464]

Proffesor I have a doubt why is the concentration raised to the power of stochiometric coefficient

[@AS-rr9km]

That is asked for when discussing Equilibrium. It is strictly NOT the stoichiometry coefficient when referring to Kinetics equations! I hope that helped :) Google coefficients for equilibrium vs Kinetics and it should explain better than I did!

[@DungNguyen-dj2ut]

You try to give the video more brightness it will be great if you do

[@malavikaanilkumar7630]

Dave sir nu മലയാളി പിള്ളേർ ഒണ്ടോ.... 🤩🤩

[@malavikaanilkumar7630]

👼

[@Serenity4world]

That's great 👍

[@ameyasuryawanshi2655]

Jesus is a good teacher

[@tusharkush7]

From where did you get your PhD?

[@ProfessorDaveExplains]

i don't have one

[@tusharkush7]

@@ProfessorDaveExplains Are you really a professor or you call yourself one?

[@tusharkush7]

But you're going good

[@ProfessorDaveExplains]

i used to teach organic chemistry, now i do this.

[@MisterRorschach90]

Doing this stuff in school was one of my favorite parts of the day.

[@limecordial1114]

what if the NH had a power of 3? you cant square root it

[@begrateful9836]

Cube root it?

[@noemi593jd2]

That cannot happen as it would unbalance the equation for that chemical reaction. This means that if there is 3NH3, N2 and H2 have to change their coefficients (only if possible, because 3NH3 is not a reasonable result as it will be hard to equal the number of moles per atom from the reactants (N2 and H2) with the number of moles per atom of the product (in this case as you mentioned, 3NH3). However, if there was a chemical reaction with a product with a coefficient of 3, it will be cubed. And as a result, when trying to find the concentration of a product, at the end of the calculation when the product we want to know is at the left and the concentrations of the reactants are on the right, we have to eliminate the exponent of the product, 3. So, to do that, cube root the result of the multiplication of the concentration of the reactants, and that's it. Hope it answered your question

[@havingfunislife9810]

it is so simple question but i am preaparing for jee advance and there that type of questions will not come as jee advance is very tough and tricy an in this question we got all the values and we just gone to put this in the formula

[@christine-vs9fs]

How do we get the ammonia concentration?

[@tysonla181]

You uh just square root it

[@havingfunislife9810]

just put this values and just use basic mathematics and solve by the way are you from which country?

[@spongep4745]

lmao your intro

[@jessicae7]

You didn’t even show how you got the answer tf

[@hamptonbrown6118]

ALL HAIL CHEMISTRY JESUS

[@briandead3513]

The image is too offensive

[@ProfessorDaveExplains]

wut

[@faithelias2798]

God loves you all

[@MeowFacegmailcom]

I did it XD

[@delwlr]

قصرت

[@ENTJ616]

It is not a great problem tho

[@tysonla181]

Explain?

[@stephanierose8708]

thanks! your video helped me with my hw, but you didn't explain why you have to get the square root of the answer?

[@noemi593jd2]

Actually is simpler than it seems. When solving for x, you try to get rid of all the rest to reach a result. In this case, when calculating the NH3, we know that it has 2 as its exponent because there are two moles of NH3. Back to the problem, 0.0600 is at the left of the equation, but in order to find NH3, 0.0600 is multiplied on both sides to eliminate it from the left, while also moving (NH3)2 to the left. Now, the equation looks like this: (NH3)2 = (0.0600)(4.26)(9.13). 9.13 is the result of (2.09)3 by the way. Now, to remove the exponent of NH3, both sides are square-rooted. After multiplying the concentrations of the reactants and square rooting the result, it will give you 1.53. Hope it answered your question.

[@humayunnawaz5138]

hey the 1st comment 2nd like yaaaaaa😯😋

[@Дмитрийорлов-н7э]

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