Practice Problem: Limiting Reagent and Percent Yield

Once we get the hang of stoichiometric calculations, we get a curve ball. Limiting reagents? Not all of the reactants will react? We might not get as much product as we expect? Let's practice identifying the limiting reagent, calculating theoretical yield, and percent yield.
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[@gB-gm7vy]

I can't express how pertinent your lessons are to my COVID college learning. For Chem and Calc...Thank you

[@unliuniverse2999]

This is a good channel

[@ShxkeGFX]

agreed

[@farhanalam7642]

You are a brilliant teacher of basic concepts. Some other videos I have seen is just focusing on the units and did not go over what these ratios mean. Thanks!

[@circlefont]

I cannot begin to explain how big of a help this was. THANK YOU SO MUCH 🙏🙏🙏

[@Kammerliteratur]

Hey Professor Dave, can you make a playlist with all tutorials and all practice problems combined?

[@krishnaswamy6684]

Thank you for this lesson

[@dalianycamacho]

great way to explain it. finally understand thank you

[@davinderarora3938]

Best practice video ever!!!,thanks a lot!

[@assadaaadinawa5225]

understood better than my chemistry master. you are my life savoir.

[@milanibohlen2283]

best one i’ve found! thank you!

[@johncrosby5964]

Beautiful video!

[@veldanasabra3452]

Thank you!

[@RachealHeather]

Thank you this has really helped me

[@devlama4725]

Hi sir.can u do a lecture on ionic equilibrium

[@Estherawe444]

You explained it perfectly omg

[@tenzindikila2365]

Thank your for your help

[@steadmanjerold1492]

Thank you Sir

[@arvhiebravo9346]

Thank you so much

[@cameronholloway5222]

i had passed my exam with really high marks thanks keep up the great work =D

[@mjxstte]

oh my gosh thank you so so much, you saved my day!! 😭

[@cristianmirasol1538]

Thank you

[@nicholasvrentzos7290]

What if there are two products? How would the second method work?

[@Barry88487]

Thanks sif

[@robertstanley9633]

Thank you! 2 hours later, I solved how the answer was received. Many thanks! Just subscribed!

[@jothamwainmut8462]

Thank you very much😁 I'm certain that I will pass my test tomorrow 😌

[@xdsagecat3920]

did u?

[@hex7378]

Where did you get the 2.89g at the end?? 8:37

[@krishnaswamy6684]

I think you really explained this concept really well. Thanks a lot! But I am confident on how you got 2.89g?

[@fahad_sul9]

Its given

[@farahaslan09090]

+1

[@hamzakedir9914]

Finally understand 😌

[@desireehaiflich6836]

big question: why did you multiply the 0.0712 by 2/3? O just need some help with that.

[@desireehaiflich6836]

wait nvm, i saw the other part of the video LOL

[@judy9680]

the dave grohl of chemistry

[@shovandeb9905]

Awesome sir !!

[@mwelase]

you're the best

[@sniperammow4865]

well since i did not get the mark i wanted in chem i have to redo grade 12 U chem :( this will be useful again i guess.

[@bhavneetkaur6668]

👍👍👍 very nice

[@coss0420]

7:30 where did the 140.28 came from Im so confused please help.

[@BuffaloBuffaloQuasar]

sorry might be too late but that's the molar mass of si3n4, thats how you convert moles to grams

[@sasrutha7304]

Bro in this how did you divide N2 with a molar mass of 28 that’s the sulfur mr rite??im talking about the first question.

[@ProfessorDaveExplains]

N is 14, so N2 is 28

[@wooshyk6583]

@@ProfessorDaveExplains why dont we multiply silicon by 3 when theres 3 of it

[@jeev6034]

I dont udnerstand how you got 0.0804 mol Si.

[@farahaslan09090]

How are you find the Actual Yield????

[@ProfessorDaveExplains]

By doing the experiment and weighing the product.

[@xiaoyu1691]

dam 2019 is 2 years ago ]

[@galiciaangelnicolechristia9585]

how did you get the actual yield

[@mustafakamal-jt1db]

It is given in the question

[@skookiz]

Literally studying for my final the morning before 💀💀

[@Nour-Abou-Noweir]

How is the silicon the limiting reagent ?! It has a larger no.of moles than Nitrogen in both cases!!!!! 5:10

[@ProfessorDaveExplains]

You have to consult the stoichiometric ratio.

[@Nour-Abou-Noweir]

Oh oh.. Very nice I got it. All thanks

[@akrammohmed6775]

علاوي حبيب كلبي ابو حسين

[@almamctaggart5787]

Where does the 2.89 g come from when finding the actual yield?

[@ProfessorDaveExplains]

That's the actual yield given at the start of the problem.

[@almamctaggart5787]

Professor Dave Explains ohhh thank you so much! Great video

[@russianemaeegay9096]

Where does the 1mol?

[@fabianmartinez5896]

@@ProfessorDaveExplains P.S next time mention how YOU GOT IT!!!!!!! but thanks

[@ProfessorDaveExplains]

@@fabianmartinez5896 it’s a made up number. This is a practice problem.

[@gabriellaluescher6476]

He looks kinda like lin Miranda

[@KeejeMass]

I’m never gonna get this 😐

[@jaspervillanueva6985]

Trust me you can. It just takes time

[@jaspervillanueva6985]

I recommend that you check out Tyler Dewitt's video tutorials first before diving into this kind of videos

[@ayanda_m4240]

My actual yeild is often bigger 😭😭😤

[@desireehaiflich6836]

you probably divided the 0.0238 by 3 again. I did that too

[@xXoommaarrXx]

This isnt your voice mate.

[@ProfessorDaveExplains]

Um, yes it is.

[@nothingnew4287]

papi chulo

[@vinoriawareba9438]

Thank you so much sir 🫂,you really helped me..