XI_75.Buoyancy, Barometer

Physics, Class XI Chapter : Properties of fluid. Topic: Buoyancy, Archimedes principle, Barometer. Classroom lecture by Pradeep Kshetrapal. Language : English mixed with Hindi.

[@khalilmaluk]

Great service to humanity

[@rajsamnani3287]

nice videos for understanding physics concepts very easily. Make interest in physics

[@chanderveersingh7630]

thank you sir...you made many students' interest in physics.

[@nakulnandi7707]

The students in ur class r very lucky sir as they are taught by you............

[@khalilmaluk]

Excellent work

[@priyaprasad9663]

please explain working aneroid barometer

[@karan1276]

sir i think when rho=sigma(36:27), the body will stay where it is left it need not float with it's surface with liq, because the net force on body on body is zero.

[@nakulnandi7707]

Hello sir,,,, l wanted to ask you a question that how can I contact you....... In which school do you teach sir???? Please reply when you see this message.........

[@vigneshcool35]

Dear sir, in calculating the dipping of boat, how the up thrust = the weight of the person gets into the boat,please explain Sir...

[@minatosenju4700]

Sir what will happen when we increase the surface area of the container.... Will the height of mercury be still 760mm.

[@bindhyachalgupta5571]

Great teacher !!

[@vigneshcool35]

Sir, In barometer what will happen if we increase the area of the container,the height above free surface will change or not?..

[@deveshabhyankar8050]

Sir the topic measurement of pressure difference( Gauge pressure) is missing in the lecture

[@jainsid123456789]

Respected Sir .. as you said ..Relative Density = Density of the sub. / Density of the water but in many books I've read ... relative density = density of the sub / density of water at 4 degree Celsius !! why so sir ??

[@vishakaathresh3623]

Actually relative density=density of sub/density of water at 4 deg celsius. this is because it is at 4 deg celsius that water has a density of 1000 kg/metre cube. when sir has said that Relative Density = Density of the sub. / Density of the water, he actually assumes that water is at 4 deg celsius and has a density of 1000kg/metre cube. I think that answers your question...

[@jainsid123456789]

thank you so much :)

[@shaikhzoya2002]

sir we have derive formula for volume of solid=loss in weight(divided by)density of water. but sir loss in weight is equal to upthrust so i think we need to be more precise and formula should be volume of solid=loss in mass (of solid) divided by density of water so that gravity will not be included.sir am i right or it does not make any difference.

[@anaytaamisha7995]

shaikh zoya even i have the same doubt

[@shaikhzoya2002]

Anayta Amisha since i had this doubt 4 month ago i have cleared it up.actually loss in weight =buoyant force=weight of fluid displaced by solid =mass of fluid displaced multiplied by 'g' and mass of fluid displaced=volume of solid multiplied by density of fluid so loss in weight of solid=volume of solid multiplied by density of fluid multiplied by g .and by arranging this equation and taking volume of solid on one side we get volume of solid =loss in weight divided by both -density of fluid and g.so here there is mistake in video there should be g as well.

[@remod-souza]

Sir, when v immerse 5kg wt solid, why dnt the upthrust bcmz 5kg?

[@dudefx8971]

that is bcuz density of block is more than water so vpg>vkg where p is density of block and k is density of water. easy yaar!

[@armankhan-pn2uk]

sir your videos have helped me a lot in physics... but to whom should i refer for physics and chemistry to get my concepts clear

[@VikasKumar-te6ey]

sir how can one contact you??

[@008shivam]

sir hydraulics is missing ?

[@VarunSharma-xl1we]

Thank you Sir...!

[@VarunSharma-xl1we]

Respected Sir,, Sir,this video is XI_79.....You have already uploaded XI_75...:)

[@jintujintubarman5793]

sir many many thanks

[@arpitapancharia3463]

Sir, you should start uploading 10 day crash course for medical & engineering aspirants. We will be very thankful.

[@avinashdubey1806]

Thanks a lot of sir

[@himanshushekhar3421]

Sir. Thanks a lot

[@airtel1730]

Got it