Plz tell me sir raw inactive material batch Mai latai Hai how to be calculate e.g pcm-100000tab x 500mg/1000000=50kg active material use in batch
@proteinengineering0073 жыл бұрын
@Ravi Kumar Question clear nai hain...plz explain what do u wish to calculate
@Youtubers8133 жыл бұрын
In this vice versa, sodium selenite, vit d3, cholifernol etc formul
@rozaparveen61543 жыл бұрын
How do you prepare aqueous acetic acid working solution from acetic acid stock solution?
@proteinengineering0073 жыл бұрын
@ROZA PARVEEN Simply use dilution equation (N1V1=N2V2). before that calculate concentration of stock solution. if u r using bottle of acetic acid, find concentration using specific gravity of the acid from its label.
@gohjiahui79174 жыл бұрын
hi Sir, i would like to ask how do i prepare 65% nitric acid (HNO3 ) and 30% hydrogen peroxide (H2O2) (5:3) ? Can you provide me the calculation for this? thank you!
@proteinengineering0074 жыл бұрын
Hi Goh Jia Hui, thank u for asking question. In order to make calculations, you need to provide details given on the bottles of HNO3 and H2O2 as both are in liquid state. Such as density or concentrations of the given solutions. From that desired concentrations can be prepared.
@hassambhatti97204 жыл бұрын
How to prepare 25ppm solution of Hcl from 0.5M stck solution?
@proteinengineering0074 жыл бұрын
first convert 0.5M HCl into PPM then use dilution formula C1V1=C2V2 0.5M HCl = 0.5 x 36.5 (molecular weight of HCl) per 1000ml = 18.25 gm per 1000ml PPM = (mass of solute/mass of solution) x 1,000,000 PPM= 18.25/ (18.25 + 1000) x 1000,000 = (18.25/1018.25) x 1000,000 = 17922.9 ppm so the stock is 17922.9 ppm Now u can dilute it to make 25ppm, but how much solution you need that must be known. for example if you need 100 ml of 25 ppm, then 100 x 25 = 17922.9 x V2 V2= 0.1394ml so, u can take 0.1394 ml of the 0.5M stock and add 99.86ml of water that will be your 100ml of 25 ppm
@hassambhatti97204 жыл бұрын
@@proteinengineering007 why are we adding 18.25 with 1000? like how can we add mass and volume?
@proteinengineering0074 жыл бұрын
@@hassambhatti9720 PPM = (mass of solute/mass of solution) x 1,000,000 in this case, 0.5M HCl means (mass= molarity x molecular weight) 0.5 x 36.5 gm weight per 1000ml of solvent. As per definition, molarity = moles per liter 1 ml of water weigh 1gm 1000ml water = 1000gm of water
@berwanibrahim41644 жыл бұрын
Hi please how to deal in case of spilling HCl???
@proteinengineering0074 жыл бұрын
@ berwan Mstafa If spilling is on floor, u can use weak base like sodium bicarbonate to neutralize and then soak it off. If contact site is skin, in that case immediately wash it off with plenty of water, u can put some antimicrobial cream. If injury is serious seek medical emergency help.
@sandeepsonania51294 жыл бұрын
Sir how will we prepare 47% Naoh to 20% Naoh?? What the calculation for this?
@proteinengineering0074 жыл бұрын
U can use C1V1 = C2V2 equation. But u need to know how much volume you required of 20%NaOH. For example in case u need 100ml of 20% NaOH from stock solution of 47%, in this case: 47% x V1 = 20% x 100ml V1= 20 x 100 / 47 = 42.55ml so you will take 42.55 ml of 47% stock solution and add 57.45 ml of water.
@ravikantkulshreshtra82154 жыл бұрын
Calculate 20*100/47 =.( Value ) gm Dilute to 100 ml water
@prof.rohansircbsestateboar51554 жыл бұрын
Thanks. How to prepare 1M or 1N acetic acid glacial
@proteinengineering0074 жыл бұрын
u can visit kzbin.info/www/bejne/Y169d4SKmqmJoLM as per definition if u take 60gm (molecular weight of acetic acid is 60) of powder acetic acid and dissolve in 1000ml, it will make 1N or 1M solution. But acetic acid is liquid hence u have to calculate how much acetic acid volume will contain 60 gm of the compound. That is done by using specific gravity (spg), written on the acetic acid bottle. if spg is 1.0, it means 1ml volume of acetic has 1gm of solid acetic acid dissolved in it. So in this situation, if u take 60ml of acetic acid (100% pure with specific gravity of 1.0) and add 940ml water, it will be the desired solution.
@prof.rohansircbsestateboar51554 жыл бұрын
Thank you.
@prof.rohansircbsestateboar51554 жыл бұрын
@@proteinengineering007 Thank you
@madhurimadas87044 жыл бұрын
how to prepare 0.1% solution of 1ml when stock is 100X
@proteinengineering0074 жыл бұрын
u need to define what 100x means or u need to change working in term of x not in %.
@gangavati50144 жыл бұрын
@Madhurima Das your question is incorrrect. U can make 0.1x from 100x or u can also make 0.1% from 100%.
@Royalclassic79474 жыл бұрын
sir i have 35% of hcl i need 5% of concentration hcl in 200ltrs of water how to do that i am not chemistry knowledge person kindly help me with this ?
@proteinengineering0074 жыл бұрын
U can use dilution equation: N1 x V1 = N2 x V2 where V is volume and N is concentration 35% x V1 = 5% x 200L V1 = 28.57L Add 28.57 Liter of 35% HCl in 171.43 Liter of Water.
@farahnafis4 жыл бұрын
sir thanks. how to get 171.43 liters??
@proteinengineering0074 жыл бұрын
@@farahnafis sorry, i couldnt see your question earlier.. water =total volume - volume of HCl= 200-28.57 = 171.43l
@indhusuresh40354 жыл бұрын
How to prepare 1% NaOH from 5% NaOH?
@proteinengineering0074 жыл бұрын
U need to define how much volume of 1% NaOH you want to prepare. Then U can use dilution equation.. C1V1 = C2V2
@ravikantkulshreshtra82154 жыл бұрын
How to make fe std solutions with the help of ferrus ammonium sulphate 1ml = 0.1mg
@proteinengineering0074 жыл бұрын
What exactly do u want to prepare?
@ravikantkulshreshtra82154 жыл бұрын
Iron (fe) std solution
@Vinodsingh-ts5wx4 жыл бұрын
How to make 80% of 20 ml acetone
@proteinengineering0074 жыл бұрын
If your stock solution is 100% acetone. Use N1V1=N2V2. Accordingly, 100% x V1 = 80% x 20ml, V1= 80 x 20 / 100 V1= 16ml So you will take 16 ml of stock solution and add 4 ml of water to make 80%, 20ml acetone from a stock of 100%.
@RUPAKUMARI-ov4px4 жыл бұрын
How to prepare 5percent acidic pyragallo solution
@proteinengineering0074 жыл бұрын
u can dissolve 5 gms of pyrogallol in final volume of 100ml. how much acid u have to add would depend on your need and applications to have acidic solution.
@microbiologist4334 жыл бұрын
hom to change ppm into percentage?
@proteinengineering0074 жыл бұрын
yes...it can be done as PPM = (mass of solute/mass of solution) x 1,000,000 lets take an example of say how to convert 20% NaCl solution into ppm using above formula, mass of solute= 20gms mass of solvent= 100gm so mass of solution = 100+20 gms ppm= (20/120) x 1000000 ppm= 1,66,666.67
@newborns97544 жыл бұрын
I have 4%w/v NaOCl in 5litres gallon. How to maake it 10%
@proteinengineering0074 жыл бұрын
Your stock (4%) is lower than working solution (10%). So dilution is not applicable. u need to concentrate your volume to 40% of the original. (both liter and gallon are units of volume, using either is fine)
@newborns97544 жыл бұрын
@@proteinengineering007 it reads as this" minimum assay approx. 4%w/v available chlorine. And is a labrotary reagent" when I bought he told to dilute in 10litres of water for a litre of the solution and use to disinfect surfaces. I doubt will it work.
@newborns97544 жыл бұрын
Also how to use and dilute or not ?? The chemical I bought for Rs. 1415 for 5litre container.
@proteinengineering0074 жыл бұрын
@@newborns9754 ok..what i understood is, you have got concentrated solution of sodium hypochlorite to be used as disinfectant. it has 4% chlorine which is = 40,000ppm. as per instruction if u dilute it 10 times by adding 1 liter solution in 9 liter water, it will still have 4000ppm chlorine. 1000ppm chlorine is known to be good disinfectant. That should be sufficient for your job. so, u just follow instructions given with the chemical. it will work.
@newborns97544 жыл бұрын
@@proteinengineering007 Ah!! Clap clap.. Thanks for the time and info, and still replying on this video.. Keep going!!
@nishakadam35754 жыл бұрын
0.8 percent solution prepare how
@proteinengineering0074 жыл бұрын
Your question is incomplete. U also need to know how much volume of 0.8% is required. I assume U need to prepare 100 ml of 0.8% of any compound. In this case U need to weigh 0.8gm and dissolve in some volume of solvent and finally make the volume to 100ml. If u need to prepare more or lesser volume , amount can be calculated accordingly.