In this video I explained how to integrate a function with argument containing absolute values.
Пікірлер: 86
@Michael-dh7wf17 күн бұрын
Engineer student here, you saved my life i have my calculus exam tomorrow
@fenkabdulqadr68212 жыл бұрын
Those who stop learning have stopped living 😍😍 Hey from Halabja Kurdistan n plz keep up that good job sir
@mahmudvlogs80692 жыл бұрын
Bruh u do math in a natural way Thanks a ton
@jhbryann11 ай бұрын
Thank you for such a thorough, clear explanation. I am taking AP Calculus BC as a rising Junior and this was very helpful. Have a great day!
@PrimeNewtons11 ай бұрын
Good luck!
@RicardoPerez-zc4ej4 ай бұрын
Gracias Sir. I am engenier and I enyoy a lot with your videos.
@lakshya4876Ай бұрын
Bro💀💀☠️☠️😭😭😭
@herayusuf63992 жыл бұрын
Thanks a lot . I was struggling doing this type of intregrals . You made my day !!! Best of luck
@KBM8532 жыл бұрын
Your videos have helped me gain confidence in calculus
@user-gu2me2mi7t5 ай бұрын
Hi Mr, thank you from Papua new Guinea 🇵🇬
@PrimeNewtons5 ай бұрын
Hello there!
@killer_queen23142 жыл бұрын
Hi sir one of your students here😁
@PrimeNewtons2 жыл бұрын
Hello @Killer_Queen231
@Zoooooooooooo Жыл бұрын
Hi queen killer
@wristocrat11 ай бұрын
Sir, I am very thankful for the incredibly clear and logical explanations of the concepts. So many instructors prefer a muscle memory approach. This method makes it easier to apply the information.
@RedManE36 Жыл бұрын
I was hoping this was going to be shown in the "long way", however the first part of splitting the equation into 2 individual equations with individual bounds helped answer my question and got you a like.
@nurii35853 ай бұрын
you're the goat man
@jmich74 ай бұрын
I love this guy.
@punditgi Жыл бұрын
Another excellent video! 😃
@DIgitalEthiopia-12Ай бұрын
it's good teaching way
@justinemulenga277824 күн бұрын
Nice explanation sir 🤝📚⚡
@anonymous125402 жыл бұрын
Thanx a lot Sir☺i am happy to have found this video after seaching for it for quite some time🙂Bravo!!
@danielgresham97232 жыл бұрын
I LOVE YOUR HAT. THIS VIDEO WAS SO AWESOME AND EDUCATIONAL. THANK YOU
@PrimeNewtons2 жыл бұрын
Thanks
@anythingandeverything3487 Жыл бұрын
You sir are a lifesaver
@joshuaowolabi730 Жыл бұрын
This is just beautiful
@terminator.co-2 жыл бұрын
you just made my day from your smiling🌼
@juliovasquezdiaz24326 ай бұрын
Gracias por el vídeo. Me gustó. Saludos desde Perú
@nopegaming20294 ай бұрын
thanks a million ! this helped me understand it more .
@PrimeNewtons4 ай бұрын
Glad it helped!
@connorgriffith4664 Жыл бұрын
I love your energy
@surendrakverma5553 ай бұрын
Very good. Thanks Sir 🙏🙏🙏🙏🙏
@spdas59427 ай бұрын
Really you are a good teacher. ❤ you from India.
@MeshackNathan3 ай бұрын
This was insightful,thank you so much sir
@bignibba38011 ай бұрын
your strategy for integrals is awesome! thanks for the tip
@PrimeNewtons11 ай бұрын
I appreciate that
@Senn_S7Ай бұрын
Thank you very much for your instructive video ❤
@tacitoaugustofarias7941 Жыл бұрын
EXCELENTE EXPLICAÇÃO.PARABÉNS. BRASIL
@PrimeNewtons Жыл бұрын
Thank you!
@SamuelAjibade-ny3tu4 ай бұрын
Thank you so much. Muchas gracias, senor❤
@bishoyekramy3535 Жыл бұрын
you are very good keep it up
@optimisticidea17212 жыл бұрын
tnx sir,by the way your smile was so interesting. keep it u!
@roselaswai628 Жыл бұрын
Thanks mwalimu, maths is enjoyable
@KanoShampene-wi4qt Жыл бұрын
i had no idea thank you
@rihamission48711 ай бұрын
Nice video brother. But the last 2 maths you showed were wrong. Because the functions are not even continuous over the concerned intervals. So they are not integrable and the fundamental theorem of calculus doesn’t apply here. Other than that, your handwriting on the blackboard was very satisfying and the method of evaluating the integrals you showed is gonna help me a lot. Thanks.
@zerodegreescelsius4 ай бұрын
Thank you!
@user-il8mt2wz9t5 ай бұрын
Highly appreciate excellent explanation. By rhe way, it will be better all math problems to be linked with real world stuff or real-life applications
@LemanBeats7 ай бұрын
thanks uncle 👍🏾
@user-jw8wo1nc3l Жыл бұрын
Well explained🙏🙏 congrats🎉
@PrimeNewtons Жыл бұрын
Thank you
@arwin9191 Жыл бұрын
extraordinary
@dlx0sh291 Жыл бұрын
I subscribe you keep going 😍🔥❤️
@snakechips Жыл бұрын
great video and nice hat
@afifamyouni673 Жыл бұрын
there is 2 mistakes done in equation 2 and 3: in equ 2: x cannot be 0, so the condition should be x>0 in equ 3: x cannnot be 1, so the condition should be x>1
@PrimeNewtons Жыл бұрын
You are correct. I should have excluded 0 and 1 respectively
@afifamyouni673 Жыл бұрын
@@PrimeNewtons i love this video, it came in the right time for me, because i have math test next month, thank you
@yacoubakabore5838 Жыл бұрын
10/10 for explicat°
@jalalgk241511 ай бұрын
legends are viewers ultra legends are subscribers 😍😍
@palmtrees94742 жыл бұрын
💓💪
@user-gm7ub1yn2k6 ай бұрын
謝謝!
@PrimeNewtons4 ай бұрын
Thank you
@domanicmarcus21767 ай бұрын
I am curious how you got that x can be greater than or equal to 1, in the last example? Doesn't 1 cause a vertical asymptote at x equal to 1? Why didn't you take the limit as x approaches 1 from both sides?
@jam933910 ай бұрын
this is cool
@nicolascamargo83396 ай бұрын
Wow genial
@DangNguyen-nl7rc Жыл бұрын
Thanks a lot for your video, my exam is about to start in 5 hours. However, for example 3, since F(x)=(x-1)(x+2)/|x-1| is not continuous in the close interval (-2,4) because of x≠1, does the integral not exist?
@PrimeNewtons Жыл бұрын
Cancel out the (x-1) . The integral exists. That's a removable discontinuity
@hqs95854 ай бұрын
5:54 why are you including in the second integral the value 3, I thought that X needs to be less than three not equal? Thanks. Mayb form -1 to 3+delta and then limit as delta goes to zero? Or else?
@SamyakAditya8 күн бұрын
Thanks
@cwlevi17 күн бұрын
Have U watched Dragon Ball Coz you make math Epic
@jameyatesmauriat61166 ай бұрын
Can you please re-do the equations with the mistakes or refer me to similar videos of yours to show how to correct them?
@jose_p_1020 күн бұрын
Those who stop learning have stopped living I like that 🤔😁
@azuce28604 ай бұрын
I have a question. In the second exercise, we have |x|(x^2+1)/x; and you mentioned that this expression is positive when x > or equal than 0, but what if x=0? Then we will have an indetermination of 0/0. I think that that expression is positive only when x>0 and not equal. Is this right?
@PrimeNewtons4 ай бұрын
You are correct. That was a criminal oversight
@novierjohnabdallahyousefebraheАй бұрын
🥰🥰🥰
@damianhunter54762 жыл бұрын
What would you do if you had the absolute value of x times cos(nx) dx ? I'm not sure how you would seperate this and make 2 integrals of it. But anyways great video enjoyed it very much!
@PrimeNewtons2 жыл бұрын
You will get that in advanced calculus. So, as far as calculus 2 is concerned, this video is sufficient.
@mrbanana6464 Жыл бұрын
@@PrimeNewtons Damn I guess my calc teacher is giving us hard stuff on purpose because we are expected to find the integral from 0 to pi/2 of |8 sin(x) − 8 cos(2x)| dx
@lunaTran-cl8is Жыл бұрын
for some reason i got 50/3 on example 2?
@PrimeNewtons Жыл бұрын
Try going over each step of your work again. I'm sure you'll find your mistake. You should get -22/3
@tsegazeabwendifraw71311 ай бұрын
😊
@Kenny-wp6wp5 ай бұрын
Hi Professor !!!! I have a function with absolute value how can you please help me the following: f(x) = e^|x| + lnx I am asked to calculate . The direction of variation - infinity to + infinity . Definition domain . Calculate the straight line of equation . The equation of the tangent . The area of the function . Graphical representation
@crxissant85958 ай бұрын
Very well explained, thank you for this sir!
@jacksonmunthali938220 күн бұрын
Chimwela
@kutlwanomokhesengАй бұрын
funny how you can learn more from KZbin than in class, lol.
@whisperingocean.26 күн бұрын
There are so many ads in you videos, jeez
@jumpman82825 ай бұрын
The second and third integrals are improper integrals, because the integrands are not defined over the domains of integration. However, in these cases the integrands are only discontinuous on a point, which means that their integrals can still be evaluated by taking the limits of the integrands at their respective points of discontinuity. For example, since 𝑓(𝑥) = 𝑥 ∕ 𝑥 is not defined for 𝑥 = 0, ∫[−1, 1] (𝑥 ∕ 𝑥)𝑑𝑥 is to be understood as lim 𝑎→0⁻ ∫[−1, 𝑎] (𝑥 ∕ 𝑥)𝑑𝑥 + lim 𝑏→0⁺ ∫[𝑏, 1] (𝑥 ∕ 𝑥)𝑑𝑥. I understand that this was not the topic of this video, but I still find it important enough not to gloss over.