Differentiate logbase5 (xe^x)

In this video, I showed how to differentiate a logarithmic function using logarithmic differentiation.

[@dicaprio7212]

Very detailed explanation, clearer than what my university professor gave,thanks! From Taiwanese.

[@PrimeNewtons]

Glad it was helpful!

[@abhinashdundu5354]

Please solve some questions on coordinate geometry

[@OpPhilo03]

Sir, Your teaching style is very attractive and amezing.😊😊. Love from India .

[@PrimeNewtons]

Thanks and welcome

[@hvok99]

dy/dx [LOGa(B)] = 1/xlna Using this fact and the chain rule we get 1/[(x)(e^x)(ln5)] × [e^x + xe^x] Which simplifies to (x + 1)/(xln(5)) Great video!

[@donewell7427]

Great tutor

[@sudiptoatutube]

The very moment you smile, I hit the like button! I know the rest of the video will be a charm! You are the best passionate Maths teacher on web!

[@jamesharmon4994]

Not what I was expecting. I've seen a lot of Lambert W function videos lately... and my eye was instantly drawn to the "x *e^x" part. LOL

[@jamesharmon4994]

I was expecting this to work somehow: 5^y = x*e^x

[@rayyt5566]

02:07 A normal person: Ignores 1/ln5 because it’s a constant Me, an intellectual: QUOTIENT RULE

[@PrimeNewtons]

🤣🤣🤣🤣🤣

[@gokalpgorduk7685]

Great video as always!

[@PrimeNewtons]

Glad you enjoyed!

[@radhikasahupioneer2004]

Or u can simply tak log5 on both sides and use the differnetation of 5^y----5^y ln5 and later on put 5^y=xe^x

[@marvinochieng6295]

Mans writes better on chalk than i do on a paper.

[@godza4735]

Hello , can you make a video for graph of a function like some radical function and then to find domain , y intercept x intercept, asymptotes , extremes , concavity and these kind of things ? But keep going great video !

[@PrimeNewtons]

I already have those videos. Search Curve sketching

[@odumosuadeniyilukman]

Still waiting for your vedio on vector CALCULUS Sir 🙇@ prime newton

[@PrimeNewtons]

Coming soon

[@Qwexxxy]

Why cant you just apply the chain rule??

[@jbasanth4896]

Why does the derivative of 1/ln5 not become as 0???

[@bipinkarki6663]

? Ur self what's the derivative of 2x , and watch it again, And u will get ur answer

[@jbasanth4896]

Sorry, I made a careless mistake and thank you for rectify my mistake

[@glorrin]

if the original line was in term of log5, I would expect the answer to be with log5 I'll try myself y' = (x+1)/(xln(5)) = 1/x * ( lne^(x+1)/ln(5)) = 1/ln(5) * (ln( e^( (x+1)/x ) ) = log5( e^( (x+1)/x ) )

[@PrimeNewtons]

Nice!

[@syphaxjuba8420]

bonsoir sire vous pouvez utiliser la méthode log5 directement

[@mBOMBZz]

Do some epsilon / delta type proof problems. They always gave me trouble at uni when I was doing my degree

[@noreldenzenky1527]

My result (1+1/x)/log5

[@comdo777]

asnwer=1x isit