Best video of this topic I ever watched on KZbin ❤❤❤❤
@IshwariFartale8 күн бұрын
Nice aapka teaching ne muze all clear ho gaya so thank you sir best teaching and best sir
@doctoekumarsingh70744 жыл бұрын
Amazing session....
@5665-d5w5 жыл бұрын
Also give important questions of 12 board in physics this year expect from you as well as board n Great thanks for doing a very great work
@gordoneli37863 жыл бұрын
I realize it is kind of off topic but do anybody know a good place to watch new series online?
@tadeojayden80953 жыл бұрын
@Gordon Eli I dunno try flixportal. Just search on google after it=) -tadeo
@gordoneli37863 жыл бұрын
@Tadeo Jayden thanks, I signed up and it seems like they got a lot of movies there :) I really appreciate it!!
@tadeojayden80953 жыл бұрын
@Gordon Eli No problem :D
@saniajafarjafar47514 жыл бұрын
finally i got it . thank you alot.
@aswitrishu44654 жыл бұрын
I Got confidence on this topic👍🏻❤️❤️❤️
@doctoekumarsingh70744 жыл бұрын
Crystal clear ....
@TheRaj_693 жыл бұрын
Oh sirr...! Kya padahte ho sirr ap.. thanks for the great work you are doing for the students sir..!
@UVPoetry3 жыл бұрын
These videos is very helpful... thanks for support sir ....& Background music 🎶 mst h 👍
@rajibdutta4829 Жыл бұрын
Thank u so much, this vedio was very useful, especially the question... 👍
@videoxdrive20934 жыл бұрын
Grt sir thx a lot
@cricketlover2801 Жыл бұрын
Gazab ka teaching sir❤❤
@riyatiwari86984 жыл бұрын
Great sir : )
@lakavathomkar2477 Жыл бұрын
Yaa
@doctoekumarsingh70744 жыл бұрын
Upload more videos plsss sir....
@anandikadam27303 ай бұрын
Sir mechanical properties of fluid ke video nhi hai kya 😢
@5665-d5w5 жыл бұрын
Sir make more videos on part we face more difficult in part 2 as well in oscillation
@letsplaygame2667 Жыл бұрын
Bro hard tha aaj test deke aaya hu easy hogaya
@letsplaygame2667 Жыл бұрын
Oscillation ke derivation
@mihikalohar78224 жыл бұрын
Amazing 😁😁
@princyprincy96495 жыл бұрын
Thank u sooo much bhai🤗🤗🤗plzz upload on oscillation plzzzzzz😥
@5665-d5w5 жыл бұрын
Yes sir it's very important
@prasenjittayade8894 жыл бұрын
Good one
@setcrip57694 жыл бұрын
Prove that l=r×p is a pseudo vector
@cricketlover2801 Жыл бұрын
Very Mast teaching sir ❤❤
@doctoekumarsingh70744 жыл бұрын
100% clear
@RavinderKumar-rq1qx2 жыл бұрын
Big fan sir
@huzaifadalal732 жыл бұрын
Thank you sir very halpful
@Riyasharma-n6j11 ай бұрын
Thank u sir 😊❤
@Khushi....wthqthwu2ksg3 жыл бұрын
Derivation of r bar aur p bar ka ans v bar aur f bar kaise?
@learn_o_pedia3 жыл бұрын
r bar means position vector i.e. distance, so derivative of distance is velocity , hence v bar . p bar means Linear momentum. So derivative of momentum is Force, hence F bar .
@Khushi....wthqthwu2ksg3 жыл бұрын
@@learn_o_pedia this is not the correct way of explaining anything to anyone. Aise samajh mein aata toh hum textbook se padh ke sab nahi samajh lete. Textbook me kami kya hai Derivative of distance, is wrong ans. Derivation of displacement is velocity.
@Amitkumar-my2vu4 жыл бұрын
Oscillation wale chapter ki vedeo banayiye sir please😫🙏🙏💓🙏💓🙏💓🙏💓🙏💓🙏💓🙏💓 Sir your teaching scillis nice
@srushtibavistale288 Жыл бұрын
Thank you so much sir❤
@vinayakkedar3465 жыл бұрын
Like your vedio
@studylover832 жыл бұрын
Very helpful video sir Thanks 😭🙏make more tricks and video for difficult subject physic
@narendaramenaria49834 жыл бұрын
thanks
@yashchavan6788 Жыл бұрын
Thank you so much sir
@Durvaaaaaa18 күн бұрын
Yeh question kaha ke hai
@paravaiztantary13483 жыл бұрын
Thank you sir
@coclover58133 жыл бұрын
Thnx sir
@Underground_48913 ай бұрын
Sir Aap Ka Channel Toh Gaya
@BLACKGAMING-uw7lcАй бұрын
Kaha😂
@rekhapadma140Ай бұрын
Nice teaching sir 🎉
@sgarceusgamerff576927 күн бұрын
Sir all chapters ka derivation ka video banao koi koi chapter ka nahi mil raha hai
@learn_o_pedia27 күн бұрын
CLICK on below link and Go in Playlist section. There you'll find majority of Derivations. We'll try to come up with pending ones as well very soon... youtube.com/@learn_o_pedia?si=0luxhzG8wQ2cZ09f
@balakshikshasadan4252 жыл бұрын
Sum for practice answers Question 1- 1.5 hrs Question 2- 4000 Joule
@marvellitegaming17933 ай бұрын
Not a 4000 joule bro right ans is. 2400 j , i think you add the W2²+W1²
@harshalpatil97373 жыл бұрын
Sir angular momentum ke formule me linear momentum que lete hai
@GetflytoFreedom2 ай бұрын
Is this for bsc 1st yr
@hasmukhsingh83882 ай бұрын
No Bsc 3rd year
@GetflytoFreedom2 ай бұрын
@hasmukhsingh8388 nope I am in 1st yr and this is in my syllabus though 2 yrs gap so that otherwise I would be in 4rth sem
@altahiirrr Жыл бұрын
Kartik aryan 🙄😹
@Shorab_goswami Жыл бұрын
😂
@amitkumarmohanty45012 жыл бұрын
Sir app achhe to padha rhe jo par vector ko app ye kya bol rehe ho or kyun bol rehe ho "bar" Ye ky hai sir jii
@kaleenbhaiya9002 жыл бұрын
Usko bar bhi bolte h bro
@THeAbHI9752 жыл бұрын
@@kaleenbhaiya900 😂
@kaleenbhaiya9002 жыл бұрын
@@THeAbHI975 are bhai tum yha kese pahuch gye🤣....bahut tej ho rhe ho 🌝
@kaleenbhaiya9002 жыл бұрын
@@THeAbHI975 bhai apna to fir bhi nikal jaayega paper ye amit bhai ka pta nhi kya hoga bhai ko vector aur bar bhi nhi pta😁🥲
@THeAbHI9752 жыл бұрын
@@kaleenbhaiya900 jindgi batch join ki he kya tumne?
@TheAnimammal3 жыл бұрын
Please listen to me because I have something very important to tell you. If you define something to be a vector which is the cross product of two vectors, and one of those vectors is momentum, then out of the three vectors, the one vector that is going to be conserved is momentum. In other words, angular momentum is going to change when the radius changes because that is how it is defined. Your derivation has two errors in it. Firstly and most obvious, the cross product is not commutative. Secondly, and less obvious is that you cannot put the cross product operator through the product rule because that neglects the angle of the cross product which is the most important parameter. In other words, you implicitly assume that sin(theta) is 1 which makes your derivation nonsense. Angular momentum is not conserved, we have been making a stupid mistake.
@akashkumarsingh80002 жыл бұрын
I guess u r ignoring the fact that angular momentum is conserved only when external force(torque) is zero. When the external torque is zero will the radius change?... Think about it as a system.. inside the system with torque =0 angular momentum remains conserved.
@akashkumarsingh80002 жыл бұрын
And also even in a system if radius changes then angular velocity will also change to counter that change.. and hence l remains constant
@TheAnimammal2 жыл бұрын
@@akashkumarsingh8000 I guess it is perfectly reasonable to claim that the likely centuries old probably invented by Newton himself, demonstration is wrong, sir. After I have used it to make my proof, sir. That is called #shiftingthegoalposts and it is unfair and irrational evasion, sir. Please stop being evasive and accept that 12000 rpm is objectively unrealistic, sir?
@akashkumarsingh80002 жыл бұрын
@@TheAnimammal there is nothing " shifting the goalposts" here kindly read the exact law ... system is mentioned and in physics reference is important...rest I don't know wdym. Can you elaborate your theory?
@TheAnimammal2 жыл бұрын
@@akashkumarsingh8000 of course you shift the goalposts, sir. I show you a centuries old example and calculate the prediction according to existing physics and you claim that my proof is wrong because existing physics is wrong. That is literally insane, sir. I use the example to prove physics wrong and you, instead of accepting what is proven start claiming that the centuries old example is wrong. That’s the definition of shifting the goalposts, sir. Pleaded try to behave reasonably, sir?