This is just like almost everywhere convergence implies convergence in measure for measurable functions in measure theory
@andrewxiwu5 ай бұрын
It feels that there might be something about notation. When we define that average random variable, we are creating a new sample space with products, so it is a product of \Omega, but then when we write that probability of \omega (small one), it is not in \Omega, but in \Omega^n now. Am I right?
@brightsideofmaths5 ай бұрын
You are right. I should be more careful explaining notations :) Maybe part 28 helps a little bit to understand the meaning of Omega?