Problem on Mechanical Translational System

[@hamiltondamilola7134]

you have helped me alot today. i am having a control sytem exam now and youre my saving grace

[@nathankiplangat3519]

hi madam, indeed you have a call and a willing heart to teach, i really appreciate you madam, thank you so much

[@khanpage9133]

Mam you such a great teacher you always help me to understand the topic easily suxh a great skill of teaching 💕

[@tigistmisganaw1532]

You are the best teacher i ever know.

[@ele_02daniel_madagascar91]

Your way of teaching if wery 👍good, and I know nothing about Control systems after classes. But Your videos helped me a lot

[@edutechguruengineeringlear4280]

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[@muhammadbutu2694]

I realy found your tutorial videos very helpfull,more appreciation to your effort in explaining this topic,thanks .am final year student of mechanical engineering

[@aboodatiyat6255]

rip

[@edutechguruengineeringlear4280]

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[@majjiprasad]

Your teaching method is so great. If you are making any mistakes pls edit that portion before uploading so that it will give more confidence to student community.

[@utsavpatadiya9036]

Yes you are right

[@MShazarul]

She corrected her mistake.

[@Dishanksahu]

I think its better when she doesn't edit, it also makes students familiar where they can do such mistakes

[@UltimateStudy]

@@DishanksahuYes, You are right

[@edutechguruengineeringlear4280]

@@UltimateStudy kzbin.info/www/bejne/joScpoaJpsShpq8

[@JYTheAviator]

Not gonna lie, this is quality content

[@eswarraja6531]

MAM K2 Is between y1 and y2 so we need to take k2(y2- y1) Which u mentioned in previous video

[@sammyxf6992]

Mistake yeah she had to take

[@thisisamanali]

Abe sale pura video to dekh le pehle

[@gedifegnayinetaw1531]

your teaching method is so great.

[@fatobamichael7980]

You are excellent in your teaching, you just save by day!

[@sonymax1563]

Mam for m2 the force of k2 is common for m1 and m2 so it must come as k2(y2-y1)

[@shaikaneeq9973]

Ya correct

[@tejakrishna6801]

Testing your IQ😂

[@edutechguruengineeringlear4280]

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[@nani_alpha]

Actually for m1 we should take y2-y1

[@edutechguruengineeringlear4280]

@@nani_alpha kzbin.info/www/bejne/ioW5o6atj7OiqJY

[@poonamchand2710]

I really appreciate your work and lecture delivering method

[@SubhashChandra-ym3tj]

Madam is beginner but hats off to her for her great efforts.

[@RealWattson]

She's not a beginner sir - probably this is the first lecture you've watched - She's good

[@qudratullahgujrani3292]

Ma'am your are a best teacher May Allah All teacher give lecture as ma'am

[@VishalVishal-mm9yq]

Amazing teacher she is...🥰

[@abeltamene3625]

wow what a great skill to educate your so unique mam God bless love from Ethiopia long live our teacher

[@edutechguruengineeringlear4280]

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[@lorenfernandezj]

You're great!. Thank you very much, you explain very well. Greetings from Chile.

[@hemahemavathi3642]

Mam .... I like ur teaching soò much 😘😘😍

[@omkarrane5867]

is there a mistake in second FBD? you must clear it k2(y2-y1)

[@dshirisha4867]

Same doubt...bro

[@shamrosekhan8046]

Same

[@muhammedshafikp9964]

Watch the video till the end. It was a mistake and she corrected it later

[@edutechguruengineeringlear4280]

@@muhammedshafikp9964 kzbin.info/www/bejne/joScpoaJpsShpq8

[@Omisutagaming]

Explain me this

[@nicolasbamamou94]

Just great, no body is perfect... J'apprécie beaucoup votre effort and committment.. thanks a million

[@petera.k.8735]

Thank you for the clear explanation. Was helpful to me.

[@mylynvarona5507]

Very well explained. More examples please.

[@eduardopalacios8852]

Thank you for the explanation. I really needed help

[@edutechguruengineeringlear4280]

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[@AbdurRehman-rb1yw]

In a free body diagram of M2, the Fk2= K2(y2-y1) not K2Y2

[@ooichinhun]

She got mentioned at the end

[@raniaalioueche1840]

Mrs. Swarna i hope you have a beautiful life, god bless you thank you

[@yongsok1134]

Dear madam, just want to know why we do not consider the gravity force here? Thanks

[@kaizaid]

We must..

[@hameedhussein3601]

If zero position is taken to be that at which the system is at equilibrium with gravity, then gravity can be ignored in the analysis.

[@islammuddinilsevar6051]

very good teaching.

[@lucky-qz7vx]

Superb class mam

[@bola5671]

I'm taking this class in about 2 months. I'm going to try to be ahead of my class

[@shreedharshah1148]

Thank you so much ma'am, the video helped a lot.

[@musicforalmighty]

Super explanation Sister.....👌👌👌👌

[@rojocs]

Madam you are my life saver madam

[@rajatruhela1126]

madam wahan p k2(y2-y1) aaega..... koi baat nhi, mistake sabse hoti h..

[@cyrrender]

perfectly explained thank you!

[@ShravaniPrashantNirgude]

in the second body digram its should be K2 + ( y2 - y1) right?

[@parthdandawate7245]

In this problem where is mg component ? because that is also a force and is to be applied on both the blocks M1 and M2. That particular mass multiplied by acceleration due to gravity (i.e g = 9.81 m/s^2) has to be applied on both respective blocks in the free body diagram of both the blocks. My question is why is it not included in free body digram as well as rest of the problem. Thank you.

[@ugochukwu2765]

This acceleration due to gravity is still an acceleration which is the second derivative of displacement, which is there. It's just that in this case you know the value of the displacement

[@ugochukwu2765]

And also there is no Laplace transform of g😌

[@MShazarul]

mg component is ma where a is acceleration due to gravity.

[@parthdandawate7245]

That mg component is applied in downward direction which should be there in this case

[@edutechguruengineeringlear4280]

@@MShazarul kzbin.info/www/bejne/joScpoaJpsShpq8

[@yubaljerome]

Hello,does the force fk2 pulling away M1 or pushing in? Am confused 😕

[@banothusandeepsandeep760]

Madam u r teaching so super 👌 Madam I need cs exam important questions for exam plz 🙏

[@gm1445]

Thanks mam for this this video☺😌

[@leonardmboloma5281]

Great teaching madame

[@laughingedits2172]

Love you so much mam.... ❤️

[@miragharzayev8002]

thank you so much. it saved my project :D

[@mdzeenath7008]

Thank u so much mam🙏

[@saribarif189]

What will we do when we have both spring and damper in series connected to mass.

[@biakliantonsing8303]

exactly what i wanted to know!

[@emimenft]

me2

[@nagasurinageswararao622]

In that case we have to consider mass between damper and spring as zero so that now we have two mass bodies one with zero mass and another with given mass and rest of the process I same hope u understand

[@SubhashChandra-ym3tj]

(Y1-Y2 )*K2 is for first body . The reaction is on second body or negate the. - (Y1-Y2 )*K2 so it becomes (Y2-Y1 )*K2

[@nainabhatia375]

What will happen if frictionless surface is given ? Will the Damper element become =0 ?

[@bharatchauhan4316]

Very good sister

[@shabbirhaidri7498]

Great respect for you

[@abhilashpaul9237]

Thank you madam.

[@ganapthiestates1508]

Mam can you please clarify why you taken fk2=k2(y1 -y2) in FBD1 if one end is fixed?

[@bfireflyb4]

I am wondering the same

[@osahenesafoakwasikantanka7654]

Thanks for the correction

[@shwetahegde8850]

Thank u very helpful

[@rajeshwari0111]

applied force = opposing force not according to newton law, but by ambert's principle

[@Chandhru_1947]

Rest in peace....

[@creativev4222]

Thank you ❤

[@bharatsoma8724]

For M2 we are not having fixed end ,but why you are taking just k2*X2?

[@siddharthprasad3458]

Wo + k2(y1-y2) hoga , unhone sirf y2 likha hai

[@chandreshpaswan1330]

M2 ke liye Kiya ja Raha hai isliye K2(Y2-Y1) hoga

[@IronMan_2.1]

How are the directions of Fk1 & Fk2 same???

[@laxmikatnalli2628]

Yea, they should be opposite!

[@sohamramani6724]

Laplace transform of second order differential equation ......... don't you think it is wrong It is d²y/dt²=s²y(s)-sy(0)-y'(0)

[@akash1000]

You are good, make some videos on grounded chair representation

[@FrankNwosu-l3n]

Thank you ma

[@johnrheuvenbentulan2564]

What is the name of the book or module is that??

[@christypgeorge8471]

nice representation ........

[@thribhuvanmallik3928]

Thank you mam

[@tejasvi7244]

why don/t we consider gravitational force??

[@umeshpandey514]

i think gravitational force is already acting on the system in the condition when we dont apply any force. so we just have to take the force applied and reaction due to that force .

[@jialeding6771]

In this problem, the force is applied to a system at equilibrium condition which means the gravity is already applied and the system reaches its equilibrium condition.

[@nirajjayswal]

the gravitational force between these two closer bodies m1 and m2 is very very small. G=6.67*10^-11...thats why we dont consider it

[@justinchambers3406]

@E lemme guess u read that book on vibrations and came here only to drop some knowledge? lol

[@endalkabebe3195]

it's great

[@byro32271]

Y2(s)/F(s) is just one of the possible system transfer functions.

[@rubeenaap6221]

Thnks miss

[@edutechguruengineeringlear4280]

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[@ishitabhardwaj1797]

Btw great teacher

[@wijiphiswag2842]

thank you so much love you

[@onetechph]

Hi madam, im your student in youtube, in the last part 18mins. I cant understand how did simplify your answer.

[@electricfundas73]

Your lecture is very much helping but why dont we take mg as gravitational force into consideration??

[@isadarc11]

She established as a framework that the initial strains o the springs happen when both masses gravitational forces are applied.

[@tothework]

Awesome 👍👍👍🙆

[@al-bokhari8197]

plz give solution of linear system book by D K Cheng of analogous system

[@kipchumbavincent2837]

Thank you

[@joemathphile3235]

confusion may occur , because of the way you indicate direction of forces, others vertical others horizontal

[@edutechguruengineeringlear4280]

kzbin.info/www/bejne/joScpoaJpsShpq8

[@brianchumba4770]

But madam for k2 its not fixed should be k2(y2-y1)

[@pranshumanohar2178]

WHAT IF WE DOT APPLY ANY EXTERNAL FORCE. WHAT WILL BE THE TRANSFER FUNCTION

[@abramcaparaz3873]

Can anyone please explain to me how fm1 is acting on the side of mass 1?

[@psushma6288]

Tqq u Mam.

[@silveremarkable8240]

why is total force on m2 = 0?

[@maithrinukala3746]

Coz there no applied force

[@athifabasheer4469]

Plz take power system analysis of single line diagram

[@onurmudur]

iyi ki varsın ablammmm

[@karthiksunkara8796]

thank u mam......

[@controlsystems5158]

Why did she used Y1 - Y2 instead of Y2 - Y1

[@jannatulrobaiatmou5607]

Please suggest a book

[@nikhilsunilkumar1]

Thankuuuu

[@jencilysenjon4117]

Here don't we want to consider gravitational force ( Mg)

[@LakshmiPrasanna-b2l]

3 nodes dhi chepandi medam

[@nani_alpha]

Actually for m1 we should take y2-y1

[@prathapmadduri3616]

Tq madam

[@mainadasari9497]

How to find out only y1 and y2

[@edutechguruengineeringlear4280]

kzbin.info/www/bejne/joScpoaJpsShpq8

[@02shyamssuryawanshi85]

3:40

[@Allrounder-6]

Mam agar lecture Hindi me hota to or bhi achha lagta

[@ankitpatel4164]

Mg nhi lgega kya?

[@siddharthbanerjee2816]

should have done FBD longitudinally

[@scientistwayne552]

haaa ndavharwa inini mam

[@chandramuralipavan4370]

To teaching mam

[@ishitabhardwaj1797]

I think she is not tired that's why referring voltage to velocity and f2 k2* x2

[@tanmoyjyotigogoi6285]

with 1.01M subscribers avoid silly mistakes

[@andresnicolasrodriguezsanc4586]

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