Problem on Polar Plot

[@TutorialsPoint_]

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[@stone8539]

Omega value can be calculated just follow my steps 1.send the 90 to LHS [~(-180+90=-90] 2.get the equation as (-90)=-tan^(w) - tan^(w/2).... {~remove negitive sign both side} 3.apply tan on both sides Tan(90)=tan(tan^(w)+tan^(w/2)) 4.we have formula.. Tan(a+b) 5..1/0=tan(tan^(w)+tan^(W/2))/1+tan(tan^w)*Tan(tan^w/2)........{~WRITE TAN 90 =1/0} 6..1/0=(W+W/2)/1+W2/2......{HERE W2 IS W SQUARE } 7.cross multiply 8. U gets 2-w2=0.......{here w2 is w square} 9.hence u got w=root 2.... Try it and be care full at cross multiplication only this one step i didn't wrote completely... Cross multiplication will me like this ex. A/B=C/D... Cross multiplication we gets.... AD=BC...... I spended 1hr to get it. I hope with my suggestion u all will get it in 10m...

[@rudra.g578]

thats +180 in phase angle

[@winniesnetwork1717]

@sophia

[@noone-og5mg]

Thnks bro🥰🥰

[@soumya21]

thankyou!

[@mygoal9409]

tan a+b formula is wrong

[@arjanghosh8797]

For calculating the omega w value, perform the following steps. Shift 90 degrees to the other side, so -tan^-1(w)-tan^-1(w/2) =270 degrees. Or, tan^-1(w)+tan^-1(w/2)= -270 degrees. Now, apply the formula of tan^-1(x)+tan^-1(y)= tan^-1{(x+y)/(1-xy)}. So, tan^-1(w)+tan^-1(w/2)= tan^-1{(w+w/2)/(1-w*w/2)} = -270 degrees. Apply tan to both sides. So (w+w/2)/(1-w*w/2) = tan(-270)= undefined. Undefined means that the denominator is zero. Therefore, 1-w*w/2= 0. Or, 1-w^2/2 = 0. Or, w^2/2= 1. Or, w^2= 2. Or, w= rt(2). Thus, the value of omega w is sq. root 2 or 1.414.

[@alimran3358]

thank you so much

[@pragatishah3794]

Don't confuse guys.. Phase angle where polar plot touches is -180! Refer her type0 order2 system where she has mentioned it -180

[@TechGeeker]

For those who have doubt in finding Omega Value move -90 to otherside of eqal use -tan^1(x)-tan^1(y) = tan^1((x+y)/1-xy), then take tan on both side...Find w

[@surajdhakate3986]

Kuch nhi samjha

[@rajkumarbrid7467]

By this w goes to Infinity

[@prabhatmihir]

Bro first of all, tan-¹x + tan-¹y = tan-¹[(x+y)/(1-xy)] Secondly after taking the 90° on the other side it sums up to be 270 and tan 270 is not defined.

[@kumarabhineet4595]

@@prabhatmihir Equate the phase expression with -180° and not with 180°

[@sravanimadimi776]

Same doubt here

[@saketfule2697]

W = 1.41 and Magnitude (m)= 0.167 and not 0.85

[@rajdeepbaruah]

Correct I was a bit confused how the hell did she get that value and where did I make my mistake

[@graceghambi5360]

Saket Fule yes am finding the same 0.16 but when making magnitude isn't it supposed to be 1/(w^2......) Rather than 1/(w^1.....) As it is. Please keep in touch @lusangw3 Twitter

[@HirenKherala]

kzbin.info/www/bejne/npzEYoyLbKiHotE

[@nirmalyasekhar3101]

@@graceghambi5360 no it should be 1/(√w^2√........)i.e., 1/(w√.......)

[@rahulvijayan4243]

You should have told what are the x and y coordinates for the beginners

[@Wolfianzero]

super confused on how you got root 2 for omega

[@S-K-Kishore]

Yes, i am also

[@cricketworld3136]

yeah same doubt

[@RamyaRamya-hc3dh]

Substitute phase =180... then we got w as √2

[@KondaThorath]

Explained very good But there is a small mistake i.e. by substituting w=√2 We get magnitude=0.16 Not 0.85

[@girireddy3657]

G(s) should be= 5/s(s+1)(s+2) to get the magnitude M =0.83

[@rohithtammisetty3458]

Madam I have followed your videos regularly. Super explanation. Madam I want how to find K value when phase and gain margin is given by using polar plot..

[@anuragpanda5152]

Bro I have A1 quality weed in my hand take it from me I guarantee there will be no need to find any k or any fucking phase gain.

[@SAIKrishna-eq4zm]

@@anuragpanda5152 😂

[@saikatdas4654]

Ma'am..I think in coordination system....+180° and -180° at same position..But you have to taken two different or opposite position,why Ma'am.

[@sauravmishra4196]

Depending on clockwise or counter clockwise we decide sign of the angle.

[@rajurockzz2647]

In the previous calsses 180°, -180° are at same position

[@HirenKherala]

You're right check this, kzbin.info/www/bejne/npzEYoyLbKiHotE

[@ganapathireddykosuru5710]

Teaching is a piece of cake to u.. mam.

[@malliswariKone]

Really superb explanation madam

[@GRMREAP3R97]

myaaaaaggnicccchuuuuud of the open loop transfer function.

[@Hand_in_hand43]

Hii Mam..... Mam how did you know all the subjects.... U r really great mam

[@maheshnani5498]

W=root 2 the magnitude is 0.166

[@prateek6502-y4p]

I fell asleep watching this. When woke up after a long nap,it was still going on

[@HirenKherala]

Then you should try this, kzbin.info/www/bejne/npzEYoyLbKiHotE

[@-A-Akshith]

See it with 2x speed bro

[@arkasvlogs369]

brief and consise explanation ...as always superb...

[@HAJSTU]

When will i graduate 😭😭😭😭😭😭

[@luv4982]

Kya hua bhai kitne saal extra lge h?

[@HAJSTU]

@@luv4982 I think you're asking me if I have graduated or yet. Yes, I graduated in 2019 💃

[@vinodkancharakuntla1032]

Same problem

[@sachindamar7871]

After clearing your all backlogs

[@m.a.r.k.i.t.o3144]

😂😂 hope you graduate man

[@princers1801]

Mam ..will u explain g(s)h(s) open loop transfer function

[@learningandenjoying9710]

Ma'am aapke lectures super h..... M ki value 0.1666 aa rhi h......

[@weirdoworld384]

Why you don't make a video on Nyquist plot. And polar plot is not Nyquist plot

[@prateek6502-y4p]

She does not know this, she doesn't know anything but 'nothing but'

[@Nani444Nani]

Here u get Tan A + Tan B formula... Ita easy to do... But if u get Tan A + Tan B + Tan C and so on... Which formula u will use... complicated

[@reshmamadala8643]

Mam it's tan^-1(w/2) so it's value is 45 therefore phase angle = -90- 90- 45= -225

[@dhaval9950]

the value of magnitude at w=root of 2 is wrong. the real value of m=0.166666

[@shelinapachal9455]

How u r able to take out the value of w=?!. The first most difficultly I face why she have written +180° in the negative real axis which should be -180° if I consider in the direction of Type2(T2) system which brings down the final equation of phase angle to -180°=-90°- tan^-1(w) -tan^-1(w/2)... Solving this equation by multiplying tan on both sides the value of w becomes infinite

[@shelinapachal9455]

Help me if my concept is wrong.... My exams r near

[@YuvrajSingh-kv1cz]

@@shelinapachal9455 i have exact problem you face and my exam is day after tommarow 😂😂

[@VlogsWithSaqib]

You did it wrong -180° & +180° both are at -ve Real Axis Correct it.. Other things are quite Fine

[@newuser4101]

Right

[@subhadeepray2848]

I got all my doubts cleared ..thank you.

[@anuragpanda5152]

I think you had enough quantity of weed.

[@HirenKherala]

kzbin.info/www/bejne/npzEYoyLbKiHotE

[@HO-rp5kc]

Thank u mam youre doing a great job

[@harishd4287]

you are doing the great job mam

[@david8079]

Very well explained maam keep it up 🔥

[@HamletsCooking]

Pura plot axis - 180 and +180 galat hai

[@eduinformation5106]

Yeah!!!!! 😄

[@NikangVideos6377]

Madam...., please get your concepts clear. And there is difference between coordinate and quadrant

[@muslimah_905]

mam order aur type hum srf denominator say judge kartay hai ?? agar numerator mai b koi s term ogi ??

[@kamaljeetkaur1804]

This is so helpful.. thnnku so much 👌

[@rajkumarbrid7467]

The procedure use for w is wrong think so...there is another procedure in which we have to convert the denominator of the transfer function into value having only real parts (i.e by cross multiplying) after that the we will be getting a imaginary parts to in the numerator which we have to make equal to zero (ex - num = 15w +j(5w²-10) , then we have to make (5w² -10 = 0) then we will get w = +-√2) and if do same in this example also we will get w=+-√2 ...but magnitude will be 0.166. hope this may help..

[@14rishit]

putting theta = -180 also gives us w=root2

[@mohammedsalihc8023]

What are the differences between different types and orders of the system

[@shubhamhire9390]

Itni videos dekh chuka hu sab samajh me aa jata hai bas graph nhi ban pata

[@cricketworld3136]

what if omega(w) in the numerator.then the angle is what ? (maybe i guess +90)

[@r.asokan627]

Now I can understand that concept thankyou very much keep it up

[@diamondchandvarshi7855]

How do u find the modulas of 1/jw...???

[@safwansadi5156]

Watching in 2x

[@janavisikarwar7211]

😂😂😂😂😂😂😂

[@HAJSTU]

Me in 1.75x

[@MATHEMATICSBYNITianHimanshu]

me also 2x mja aata hai

[@S-K-Kishore]

1.75

[@arjun199784]

How did u draw the direction explain it...how else can we understand

[@franciscomorenocasa]

Why do you insist about the Open loop T.F. of unity FB? You are drawing the Polar plot of a Transfer Funtion: C(s)/R(s) whatever the system is

[@sravanidumpati3886]

Can u explain briefly how w=√2

[@GRMREAP3R97]

sravani dumpati substitute fie with 180 degrees in the phase angle equation.

[@jithendragn6926]

Bro first we need to find the intersection with negative real axis, then rationalize,thn equate imaginery part to 0, thn u will get w=✓2

[@sds6218]

First substitute fie as 180°than move the 180°on RHS side than move tan inverse on LHS side use the trigonometric formula of tan inverse x + tan inverse y =tan inverse (x+y)/1-xy than solve it

[@Sancharisanjay]

Thanks drlng......it's helps a lot....thank you so much madam.......

[@surajdhakate3986]

Ma'am please give brief explanation we are not Einstein....

[@नमस्कार-ड7त]

Thank you Ma'am 🙏.

[@tatikolyethendher382]

Very easy to understandable

[@lelouchzxc_]

suuuper usefull, thanks!

[@pavankumarenugula5637]

Mam could you remove this onscreen sentences explanation as we are not seeing what you are explaining.

[@HemanthKumar-kx9zy]

Explain how to convert magnitude and phase angle into real& imaginary

[@HirenKherala]

You can find your solution here, kzbin.info/www/bejne/npzEYoyLbKiHotE

[@jithendragn6926]

I got M= 0.166 😎

[@riddhesh5541]

same bro

[@rajurockzz2647]

Exactly

[@thefallendictator]

same here

[@chandikaraj1511]

Same

[@RiteshkumarSingh-ii2kh]

Very nicely explained mam!!! 👌

[@shubham_ram5377]

Mam how can we derive transfer function from graph?

[@sriramgelli-0094]

s+2 is not in the time constant form

[@speedstudy1136]

How to calculate intersection mam

[@HirenKherala]

kzbin.info/www/bejne/npzEYoyLbKiHotE

[@ankurjyotisaikia3776]

If we get any natural number I numerator other then 1 then how can we do

[@adityakapoor920]

how can we equate Fie equation with 180 degree.

[@narayanammalingamsetti1941]

How to find the k value

[@PIYUSHKUMAR-sq2te]

you are wrong . M is 1.66 not 0.85 at w= root 2

[@Lofi_Music09]

It is -ve axis but w=√2 is a +ve value.... How is it possible.....?

[@HirenKherala]

kzbin.info/www/bejne/npzEYoyLbKiHotE

[@samzenerthpaul4652]

Ma'am i didn't get how you get the value of w=√2

[@tushartyagi8506]

Sm question

[@Venom-hp5zf]

phase value become root2 by substituting 180degrees in the place of omege

[@guruprasadhiremath9182]

Substitute phi equal to 180, that is where polar plot cut horizontal axis and find w

[@mananshah9785]

Guruprasad Hiremath Line is crossing in anti clockwise direction y not -180

[@michalpelic6169]

Yes we know that phi is equal to 180. What do you do with the inverse tan() to find omega?

[@kumarisneharani514]

Omega =root 2 How?

[@rajurockzz2647]

If we substitute w=√2 we get phi=-180°

[@thermalengineeringmanojshe1302]

We are not getting √2 at 180 degree

[@kalyansrirangam1449]

Thanks darling.......... Mam

[@ramrohit347]

I want to thyristor topic mam

[@ronny_ranks]

Thank you very much

[@rajasekharyadav6517]

How to equate that

[@shashikiranjadhav5819]

Thank you mam

[@hruthikr5019]

Wow never knew -180=0 LOLOL

[@Shashi_K_Raja]

I love the way...u teach mam..😊😊... Plz join in my clg so that I can follow ur lectures regularly ......#tremendous #fab 🙏👌lecture..☺

[@HemangJoshi]

If I pass GPSC exam, I will give party to all who have commented here...

[@learningandenjoying9710]

ω=√(2) and M=0.1666 how M=0.85?

[@leonardkibet2811]

Wondering

[@ravisolanki5382]

Mem axis concept not creare

[@rameshkumar11a17]

Tq mam

[@ajithbalakrish7031]

Thank you

[@diyamishra57]

Nice ma'am

[@Mahi-ws1ls]

Omega √2 kese agaya

[@smdshareef2861]

Madam we don't want to calculate the corner frequency?

[@murarimishra9989]

The value of M Is WRONG

[@balutadepalli2742]

awesome lecture

[@creativeofficial5585]

Thoda hindi bhi boliye Didi

[@Timelinesavetime]

Mem W=ROOT ME 2 WHERE

[@Ashish-so3ze]

Very very thank u mam ,

[@althafmhd6240]

Nde ponnu pennpirannolle, w is not root 2🤫

[@jag__g1__rahi]

Ma'am hindi v use kijiye hmmlog bihar se h

[@shozafwali5672]

Thanks

[@adisricreations7278]

Video not clear

[@MATHEMATICSBYNITianHimanshu]

thanks mam

[@nonameno4557]

Root locus all problems solution

[@PMMEAPARVEZASHRAF]

M=.167

[@udaybhaskar1734]

Tq medam

[@d.sudheersunny6690]

How u got w =√2

[@alaahesham250]

use the calculator to solve it for you

[@umeshsingh-du3pk]

Multiply both side with tan.... In LHS angle will be tan(-90) means 1/0...... Now equate both side you'll get the value

[@suzaingul6149]

thankuu soo much

[@sarankumar9894]

Looking so beautiful and

[@yogiaryan2919]

Your pronounciation is really poor .. Sometime it confuses me .. What the hell was that ...

[@shimaaashraf3125]

use captions

[@alexmyladoor4858]

@@shimaaashraf3125 nice one

[@sarveshtiwari8843]

Where is this institute I want to study here plz tell me where is it

[@Manojkumar-uk6tq]

Delhi

[@kakhil1843]

Meru electrical machines teach Chesapeake medam