Program To Print All The Divisors Of A Given Number | FREE DSA Course in JAVA | Lecture 12

Data Structures and Algorithms Free Course (Learn DSA Without Paise) Playlist - • Data Structures And Al...
We are up with the lecture 12 of our much awaited dsa course in java.
In this lecture we will understand the logic behind printing all the divisors of a given number.
Check out the complete video to learn the logic and program for finding the divisors of a given number.
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[@arushitandon4766]

with all due respect , sir, your voice is like music to my ears.

[@yoigee]

for input 6 it is printing 1,2,2,3,6

[@mohithnr1253]

next level teaching..........tq so much sir

[@shameershamee0]

Great!

[@abdusselamspahiu2151]

this video was so scientific and inclusive, liked it very much

[@_sarthakmisal]

Code has correction check for 20 4 repeats 2 times

[@rajatmoraniya6368]

if(n%i == 0 && n/i != i && i

[@Cricket_facts1845]

Why it is happening?

[@modhugumudiushasri2330]

thanks for the great content sir. and your teaching skills are amazing..

[@parthbadkul3524]

but your code has a flaw for values like 6 which has ODD divisors it will duplicate the divisors

[@arbazahmadkhan9128]

Love to watch your video

[@TAPACADEMY]

Thanks for the constant support to our videos. Keep watching.

[@hrithikrudra4292]

Awesome

[@TAPACADEMY]

Thanks Hrithik. Do subscribe to our channel for regular updates.

[@abhishek_______.]

sir, there's a problem in that 2nd loop statement where the numbers are iterating in reverse order, let's suppose if there is a number 90 whose factors are to be printed then in the 1st loop i will go from 1 to 9, then after coming from the 1st loop i value will become 10, now in the 2nd loop i will start from 10 and go still 1, if you divide 90/10 again 9 will get printed so basically the output is going to be like this : 1 2 4 5 6 9 9 10 15 18 30 45 90 so to avoid this problem in the 2nd loop you must add one extra condition that is " i ! = (n/i +1) " then this repeatation problem will not occur. I hope you look into this problem and find it useful. Thank you sir for providing such a wonderful course for free.

[@shhivanshh]

Good observation, thanks

[@parthbadkul3524]

thank you

[@yesican_iwill5090]

this code will not work for n=20

[@sreenijanarayana8468]

very good explanation sir.....but, for input:40....this logic prints 4 two times...as i in the first loop exceeds 4 and becomes 5....so initialization in the 2nd loop has to be i=i-1.

[@abdusselamspahiu2151]

but you have to do some homework yourself, that u just did.

[@abdusselamspahiu2151]

i fixed it by replacing '!=' '

[@ShivKumar-py4oe]

when will be the course complete

[@TAPACADEMY]

We are uploading one to two lectures on a daily basis. The course to be complete within 1.5-2 months

[@rajatmoraniya6368]

for 20 it is 4*5 and 5*4 put this condition in second loop if(n%i == 0 && n/i != i && i

[@rahulgaikwad593]

for 90: 9 is printing 2 times so i resolve this by adding one more condition in second for loop: if( n%i == 0 && i != n/i && i*i

[@munibakhan-du2bj]

can you plz explain

[@anukaran1307]

if (n % i == 0 && n / i > i) put this condition instead, this denotes all previous values of i should not be printed in the second loop