I would explain that the equation for the height is a parabola. So there are two solutions: one for going up and going down for the 10 ft mark. However, the velocity has a negative sign once starts going down. Once you calculate the time for 15 ft, you define the location. I guess, at least for me if you see the description of the trajectory as a parabola, it is easier to understand.
@connormann9612 Жыл бұрын
is the velocity you found for the final question the same as the final velocity?
@koungmeng4 жыл бұрын
Glad you are back. Haven't seen you in 4 months xD
@PhysicsNinja4 жыл бұрын
I took the summer off but am back now. Looking to make 1-2 videos/week. Thanks for following Physics Ninja.
@jeromesmoral86364 ай бұрын
sir why did you used 9.81 m/s than 32.2 ft/s even though its feet?
@pauloopena36524 ай бұрын
May I ask why the Vy= Voy-gt is not Vy=Voy-gt because the Vo of the Vy would be zero cuz it's from the max height?
@prathameshrumde3027 Жыл бұрын
hi sir can we cal calculate initial velocity v by using formula R = v2 sin(2theta)/ g R = 15 feet = 4.57 m theta = 45 degree if yes then im getting v as 6.69 m/s pls clearify
@abbyberkenyi8175 Жыл бұрын
how would i solve this problem if my problem did not give me and initial height of ball but i have the initial velocity?
@lancepaschal84864 ай бұрын
How could the height of 3 meters and the acceleration due to gravity both be positive
@armelasopjio29862 жыл бұрын
Hello excuse me, is the velocity considere as a force? Otherwise I want to know how the movement on the horizontal direction is made.
@PhysicsNinja2 жыл бұрын
Velocity is not a force. This analysis starts from the instant that the ball leaves the hand. Once the ball doesn’t touch the hand the only force acting on the ball is gravity (ignoring air resistance). It will be the hand that produces the initial force on the ball to cause the movement.
@lourdessalgado91774 жыл бұрын
you are doing great
@user-sh7ov3df6p2 жыл бұрын
Yayyy tysm!! I really needed this!
@themflad3 жыл бұрын
What Math is used in question 2?
@guapdoctor45344 жыл бұрын
Thank you!
@danielshamlian28006 ай бұрын
You lost me at 15:40 I don't understand how all the v sin thetas (I count four of them), only turn into v^2sin theta^2 -- it looks like either half of the equation would be that, but one just disappears. I can't base my studying on terms seemingly disappearing, so I can't use this to study, even if the answers are right. Thanks for trying.
@mulatiedemis3501 Жыл бұрын
good work
@EyaelMekuanint3 ай бұрын
Thank you
@ribandrey64302 жыл бұрын
Oh wait I have another question sir. In 12:59 you showed how to solve the time it takes for the ball to reach the rim, and actually we are doing our research now and we know the t or the time it takes for the ball to pass through the rim. So, can we simply calculate the initial velocity from there like: Vo = L/((cos0)t) ?
@PhysicsNinja2 жыл бұрын
Yes
@nourmakhlouf2628 Жыл бұрын
in 10:56 you said the height was 3 ft... isnt it 7ft which is 2.13 m ?!
@boscomerinoechevarria68443 жыл бұрын
What if you don’t know the initial angle and what to find it
@larsvanmoerkerk29533 жыл бұрын
kzbin.info/www/bejne/apuxdmabibt4ndE
@lincolninniss57812 ай бұрын
Hi, I worked out 3.56 m for the maximum height.
@ribandrey64302 жыл бұрын
Hi Physics Ninja! It was a very informative video! However, I have a question. Is it possible to calculate the force exerted by the player (in your example) without the acceleration and final velocity of the ball given?
@PhysicsNinja2 жыл бұрын
Not possible
@ribandrey64302 жыл бұрын
Ok thank you!
@ribandrey64302 жыл бұрын
Btw how do you calculate the release force when shooting the basketball? Like are there any formulas for it?
@lawdcastentertainment76882 жыл бұрын
@@ribandrey6430 I think for a basketball player, they could measure their max height, where Velocity Y =0 of their throw.
@vikramnagarjuna35493 жыл бұрын
Why did you take long gap bro...
@tatemccune58812 жыл бұрын
I don't think the maximum height is correct. how would it be less than the height of the basketball rim? I got 3.56 m for ymax
@PhysicsNinja2 жыл бұрын
10ft rim is 3.05m… all good
@greerangeminecraft6912 Жыл бұрын
ITS NOT STRAIT forward to the point but its fine i learn something from it
@meshachjones69093 жыл бұрын
God sent
@trhasamare8865 Жыл бұрын
wowowwww.but how can i get acc ?
@Vishnu_the_slayer Жыл бұрын
❤
@fizixx11 ай бұрын
😎
@Thewerwolf Жыл бұрын
Last velocity value -3.18 is actually your value in ft/sec not m/s. Your value in m/s should be −0.99584 m/s. If you us this the angle should be actually -10.5 degree thus 10.5 down from the horizontal. Cheers and thanks you have fun content...