In this video, I go through a proof for the formula of the volume of sphere without the use of calculus. I've also built an interactive Geogebra applet to see the cross-section in 3D: sites.google.com/view/matholi...
Пікірлер: 23
@MassMultiplayer Жыл бұрын
for some reason i understood everything it make sence. but i also instnatly saw i would have taken my whole life to even consider this. for some reason the water 3d displacement is genius , love it subed to yor chanel
@ChenHongming Жыл бұрын
It is customary now that when you understand the water displacement concept to run around the streets naked shouting Eureka! 🤪
@302ci19687 ай бұрын
Very very interesting, thank you !
@culater Жыл бұрын
Very nice 👍
@blackchicken2243 Жыл бұрын
Very cool video
@ChenHongming Жыл бұрын
Thank you! 😃
@chasejohnson8326 Жыл бұрын
very cool :)
@ChenHongming Жыл бұрын
Thank you for your kind words!
@Filipnalepa Жыл бұрын
For sake of being complete-how do we show that a volume of a cone is r²*h/3?
@ChenHongming Жыл бұрын
That would need another (and longer) video. But I would approach it from proving a square-based pyramid of unit height and base (I made a quick animation of that here: instagram.com/p/CiXFgQapGh4/). Then through scaling and shearing transformations, prove that it works for triangular base. I will also need Cavalieri's principle to explain why shearing preserves the volume. Then using triangular base to prove for polygons then showing that if it works for polygons, it must also work for circles (i.e cone = circle-based pyramid) and circles are just polygons with 'infinite' sides.
@adb0128 ай бұрын
@@ChenHongming ... "If it works for polygons then it works for circles" is fine. But the problem is that it works for squares and triangles doesn't immediately mean that it works for all polygons and hence for circles. I prefer the following method: First, you can calculate the area of the circle with the most-calculus-like thing that the Greek did without actually using formal calculus, which is to slice the circle in very thin "pizza" slices, re-arrange the slices alternatively right-side-up and upside-down to form a rectangle of height r and base circumference/2, and finally define pi as the ratio between the circumference and the diameter to get to pi*r^2 for the are of the circle. Then, obtain the area of a squared-base pyramid in function of the area of the base and the height (as you did in your animation): Vol of squared-base pyramid Vp = 1/3*Ap*h where Ap is the area of the base of the square-pyramid. Then observe that a cone would have the same cross-section area at any height than a square-based pyramid at the same height, and hence would have the same volume. The assertation of equal cross-sectional areas at equal heights can be done observing that a) the cross-section of the area of the square-based pyramid is a^2 (where a is the side of the square of the cross section at the selected height) so area of the cross section is proportional to a^2, b) The cross-sectional area of the cone is pi*r^2, where r is the radius of the cross-sectional circle at height h, so the area of the cross section is proportional to r^2, c) that a and r change linearly from zero at the top to the max value at the bottom and d) that the areas are the same at the bottom. Finally, Cavalieri's principle implies that 2 solids that have the same cross-sectional area at any height also have the same volume. So if the pyramid and the cone have the same volume, and the same base area, then the volume formula in function of the base area also needs to be the same, so Vc = 1/3*Ac*h, were Ac is the area of the base of the cone pi*r^2, so Vc = 1/3*pi*r^2*h. QED.
@maciej1234567810 ай бұрын
9:02 because yellow triangle has 45 degrees
@GolfUB5 ай бұрын
in 2:42 why did you changed the volume formula of a cylinder to be pi * r^2 * 2r instead of pi * r^2 * h?
@ChenHongming5 ай бұрын
I am considering a cylinder that has the same height as the sphere.
@miguelmouta53723 ай бұрын
👍
@Dineshkumar-by9px11 ай бұрын
Awasome
@_learn_for_life_ Жыл бұрын
Ouhhhhhhhhhh 😁
@SimchaWaldman Жыл бұрын
Here is another method I discovered: kzbin.info/www/bejne/j5rTdJxjdpprr7M
@alexglaras5090 Жыл бұрын
Mans pfp is korosensei lol
@ChenHongming Жыл бұрын
And was drawn using Geometer's SketchPad.
@edutech32706 ай бұрын
Bro, without knowing that volume of sphere is (4/3)pi.r^2, how did you state that theorum??You are saying that volume of sphere is (4/3)pi.r^2 and then proving it??
@ChenHongming6 ай бұрын
Using a displacement can, you can work that out experimentally first like the story of archimedes and the king’s crown. This gives you a hypothesis that you can then prove using various methods.