Proof: Triangle altitudes are concurrent (orthocenter) | Geometry | Khan Academy

[@ashwinarora7561]

all the videos of khanacademy are a life saver

[@muhammadjavid3681]

I would like to request the tutor to make a video on how to find and prove the orientation of vectors!

[@bruceedward3079]

Beautiful, simple and elegant proof, thank you

[@xedgesharpz6525]

Ok, now my question is why all the perpendicular bisectors are concurrent.....

[@yjl5373]

The meeting point is the circumcenter, and that can be proved very easily

[@4ltrz555]

@@yjl5373 he has probably found his answer by now lol

[@TechToppers]

@@4ltrz555 😂

[@sourthakjackmcober29]

One of the regretful comments to have. But it is what many would wonder. Nothing wrong

[@ch3zin]

Amazing!

[@tapaspal2968]

How is centroid of a triangle is equal to the orthocentre of medial triangle

[@Z-eng0]

Nah, it's that the circumcentre of a triangle is the same as the orthocentre of the medial triangle. Which is rather curious in my opinion, and I was rather shocked by that, I never knew how I might go about showing that a triangle's altitudes are concurrent, considering that altitudes felt like those vaguely defined/drawn lines that are only parallel to the opposite side or its extension, felt too vague so didn't expect the proof to be this straightforward

[@hedonism13]

The new art history videos - will they be being embedded on the KA website soon?

[@Nitrodino7875]

i dont see how people dont WATCH THESE

[@muhammadjavid3681]

If two vectors A and B are non zero vectors and A=√2B then what is the orientation of these vectors means parallel,anti parallel,coplanar and concurrent? Can anybody explain?

[@amithandge1018]

Multiplying B vector by a pure number (√2 here)will only affect the magnitude not direction so they are parallel co planar vectors

[@rajeshkumar-ec4vj]

Pls could u give the proof for concurrency of meadian s of triangle without using vectors

[@lifestyle9709]

use the ceva's theorem

[@TechToppers]

@@lifestyle9709 Or better, use midpoint theorem. It's way more elegant and pleasing.

[@sathvikkotapati7530]

To prove the concurrency of altitudes

[@kevinmathewson4272]

the crime is committed at 2:35

[@dannyram1989]

Thanks for pointing that out, thought I was going crazy.

[@akulbhendeofficial2585]

Math antics is better than this one

[@SkillUpMobileGaming]

I'VE GOT A FUCKING FINAL TOMORROW...............

[@johnchristopherlicayan4065]

Hell yeah!!

[@CJhakeV]

Meh. I already know what 1+1 is..

[@spiderjump]

is there another way to prove that orthocenter is concurrent?

[@TechToppers]

I know 2, vector and coordinate geometry.

[@sathvikkotapati7530]

But I know a simpler way

[@guygremaux2512]

Illuminati