Propagation constant, Characteristic impedance and reflection coefficient

[@max-li5dn]

Thankyou Sir, YOU ARE LEGEND ........ U made my basics clear . U r one of the best IIT professor in india who can teach EMV theory and TL .😍😍😍😍😍😍😍

[@rahulsingh-el5on]

nooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

[@swaraj95]

I appreciate your way of telling a lecture...u fulfill all the characteristics of a professor..

[@souravkumar5021]

sir you are truley define wot does teacher mean...respect u frm heart...

[@jacobvandijk6525]

His explanations are okay, but his calculations are not so good!

[@raymatic1]

beautiful.. way better than any of my professors... I will regard him as my actual professor for my em waves course rather than my actual professor lol... love and respect from New York!

[@jappadadappa]

It's difficult finding a true TEACHER at a collegiate level... These videos are beautifully done!

[@pramoddheram8317]

very valuable piece of knowledge,thank you very much sir

[@kabandajamir9844]

The world's best teacher thanks sir

[@supriyamishra4612]

Thank you so much Sir. You made this explanation much easier

[@seemashekhawat3678]

thank you so much sir for adding more to my concepts

[@samrockseagle]

no words but thank you.

[@pabansapkota8240]

At 11:52 Are we using dB=10.log(Pt/Pr) , for which it got to be the way it is?

[@siddharthsahu6573]

Great sir mja agya🤩🤩🤩🤩🤩🤩🤩🤩🤩🤩🤩🤩🤩🤩😍😍😍😍😍😍😍😍😍🎂😍😍😍😍😍😍😍😍😍😍😍🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥

[@kazeemay]

Thank you, I use this 2pi/lambda equation several time without knowing where its from...

[@KrishnaSharma-kj2ju]

Thank you so much. This is really helpful.

[@rabishankardas5935]

What a Session SIr.... You made the subject look like a piece of cake.....

[@suneeldatta]

very thank ful for providing these wonder ful lectures............

[@BorgMater]

Simply beautiful ...

[@aditikumari3677]

How strange , after watching your lectures suddenly everything starts making sense.

[@abdelrahmangamalmahdy]

44:40 but L = D - X where D is the total distance of the transmission line. L is not simply -x , please correct me if I'm wrong!

[@rahuladesh4260]

you are wrong. Now think about the direction . you were travelling for left to right with was x and than start your analysis for right to left thus it is denoted by -x (L).

[@abdelrahmangamalmahdy]

Rahul Adesh that's the slope but there's a constant missing here which's D "the length of the T.L." L = -x + D because L(0) = D not zero

[@abdelrahmangamalmahdy]

Rahul Adesh I've almost completed this course and I don't find that D very effective, you'll get the same calculations at the end.. but it is a mistake he made. Nobody is perfect!

[@rahuladesh4260]

He has changed the direction of analysis. he does not simply replaced L=-X . A lot of thing has also changed like V+ value which was the value of voltage at source end after replacing it will be value at load end. I think you get my point.

[@rahuladesh4260]

There is whole team of iit faculty for creating a video. So there is almost a zero chance of error. If you find any error than i means you did not understand the concept properly :).

[@abhinandankumar225]

At 23:53 While calculating voltage at x=1,t=100nsec we don't know the phase at that position. But sir has taken the phase 30° which is the phase at t=0,x=0. So I think Sir is missing the phase at x=1. It must be something else. rectify if I am wrong.

[@jacobvandijk6525]

I think you are right. His calculation of gamma is wrong too.

[@aniketsaha7455]

30 degree is the initial phase associated with the wave..An additional phase is added to 30 with position and time..So the explanation is absolutely correct

[@aniketsaha7455]

@@jacobvandijk6525 You haven't considered the square root by mistake..That is why you are getting confused..Consider each term under the square root in polar form and then compute the value..

[@jacobvandijk6525]

@@aniketsaha7455 Basic multiplication: 0.5 x 0.1 = 0.05; the square root of 0.05 = 0.2236 (not: 2.23)

[@aniketsaha7455]

@@jacobvandijk6525 Man you are again making a mistake..You can't take square root of individual components..I would like you to search square root of complex number..Else send me your gmail and let me send you how the values are coming..

[@hiteshsuryakar7603]

Superb sir now electromagnetics is very easy for me

[@registrationnn]

you really help me a lot

[@roshanbernard5933]

Please help ... Intially V- denotes the backward wave and by the end of the lecture ... it is the reflected wave ... i dont get it ... HOW THE WAVE GETS REFLECTED ?? THE voltage should be used by the load right ...

[@cannibol9009]

At 27:00, isn't the peak value of the backward voltage denoted by V- than V+.

[@rahuladesh4260]

I think |v+| =|v-|

[@Being_anonumous]

both are same in magnitude bro

[@saisravanbharadwajkarri3925]

Wait a min... shouldn't we consider V(total) = |V+| exp(-gammax) + |V-| exp(+gamma x) at t = 0 in which case both should be used when V total =8.66v (given). 8.66v*(1/cos 30 )= V+ + V- ; even if they are equal shouldn't each be 5v each ? Are we assuming there is no backward wave at the t =0, this would change if this t =!0 correct ?

[@aniketsaha7455]

@@saisravanbharadwajkarri3925 Indeed a good argument..I guess superposition is being used..so 8.66+8.663=2|V+|Cosine 30...2 gets cancelled

[@mrmkkryt6485]

At 21:01 where did the pi come from?

[@lastdaysguitar]

Thanks Prof.!

[@paritoshpandey5103]

professors like him should teach other in Tier 2 colleges of India, so that student like me will be able to understand thinks more easily rather than in IITs which is full of genius.

[@devenderkumardevender8582]

Thanks Sir please many videos of attenuator

[@poiuwnwang7109]

Super clear derivation

[@bhartkumar4654]

how is gamma separated into real and imaginary parts at 16:46?

[@jacobvandijk6525]

You might be confused. I was too. But his calculations are wrong. Look here how to multiply complex numbers: en.wikipedia.org/wiki/Complex_number

[@sumitdeswal2008]

nice lecture!!! thanks sir :)

[@vedantjoshi1487]

how to solve the equation at 16:33...? i am getting math error on my calci! plz anyone tell me

[@rgudduu]

very elemental mathematics. What error are u getting?

[@jacobvandijk6525]

You are right. His calculations are wrong. Look here: en.wikipedia.org/wiki/Complex_number

[@jacobvandijk6525]

@@rgudduu Tell that to the prof ;-) He didn't get it right. And you probably didn't get it right too.

[@rgudduu]

​@@jacobvandijk6525, ???? Prof's calculation is correct there. I rechecked. gamma=2.235+i*28.187. Tell clearly what u want to say.

[@jacobvandijk6525]

@@rgudduu Still waiting for an answer, smart guy.

[@mudassirmd8992]

how is 1/alpha effective distance ,,how it is derived from e^-alpha?

[@sanketpriyanka]

thanku vry much.. :D

[@valor36az]

excellent lecture

[@DHAQANMAALONE]

thanks 4 posting this is a great vedeo

[@BasharatMartin07]

can somebody show me the calculation process of finding the (alpha - attenuation) and (beta - phase constant) ??? ..

[@devbratsrivastava9987]

+Mr. Martin You can find the quantity wich if under the root using any scientific calculator. After that, assume gamma=alpha+i*beta. Square both sides. you'll get 2 equations in 2 variables. solve. Alternately, write the quantity under the root in the r*e^theta form, then find the square root.

[@RameezAfzal-nn5uj]

I have problem how to find the phase in this question

[@musabaslee8436]

Great

[@swaraj95]

thank u very much Sir

[@tpmbe]

Thank you

[@sanketpriyanka]

thnku vry much

[@judsonantu2036]

did anyone try out the problem and get the answer as in the video?

[@sanketpriyanka]

thanku vry much..

[@thanishkumar398]

❤❤

[@pillisailaja8226]

what type of explanation its like reading a book be relevant sir