Prove 3^n if greater than 1 + 2n

[@cj-cs7lm]

in the end, for n=1 is not true. rather, i think, since it's true for k and k+1 and k>=2. then 3 to the n > 1+2n for all n that are in Z | n>=2

[@Sheldoncollier]

Yes, I should have written n=2.

[@Xtymoon]

there is a mistake in the maths, am i wron? you implied that 3(1+2k)=1+2(k+1)...

[@Sheldoncollier]

No, I didn't imply that anywhere.