Proving the Function f(x) = sqrt(x + 2) is One to One(Injective) using the Definition

[@xetro8190]

Where can I ask my doubts to you

[@jessexd3251]

Hey nice video. But won't you end up getting a=b everytime if you replace x with a and b in any equation?

[@TheMathSorcerer]

nope, not if it's not 1 to 1:) like say f(x) = |x|, if we we let f(a) = f(b), we get |a| = |b|, this doesn't mean a = b:) We could have like |-2| = |2|, but -2 is not the same as 2

[@jessexd3251]

The Math Sorcerer Oh ok thankss

[@chapmanchapman3994]

How about f(x) ^2 = x+2 ? Is it injective ?

[@dennisong8270]

Oh wow. Thanks.

[@harshitraj8409]

Great

[@TheMathSorcerer]

thank you!

[@kishorsingh8846]

Nice

[@TheMathSorcerer]

Thank you❤️