Stress on an Inclined Plane.MP4

[@IamJustJosh_]

I spent hours and hours trying to understand this, but this video has cleared it up for me in 10 minutes! Thanks!

[@drusle6]

Brilliant explanations, and done without editing! Best available mechanics clips on youtube, I don't know how lecturer's in Sydney have a job after watching you. You make them look like mumbling fools. You're on the ground level of the next generation of education and I truly hope you prosper and grow in this field. Keep up the good work mate!

[@RKO36]

You're always very good at explaining things, Prof! Thanks.

[@verygood6625]

The way you drew the figure in the first sight explained every thing, great job. lucid and clear. Thanks

[@updownleftrightish]

You are such a good teacher, I watched you as a student, I now watch you as a teacher and you hit home runs every time. Your videos are invaluable for many to fill that gap by giving the correct and detailed background of the theory.

[@Rajdsmart]

I tried many Vdos out there, but yours is the best and was able to understand the concept very clear !! Thank you very much

[@singha2927]

The good teacher is a teacher with excellent art skill

[@purdueMET]

I hope this means that my drawing was OK. I think all Engineers should take art classes :-)

[@animiztothepoint3156]

i have read many articles on that topics but this was the best lecture which gave me more understanding than those articles

[@autogordel]

better explanation than any person or book gave me, thanks! I finally get it now.

[@stephensmith8743]

If only youtube was around when I was in engineering college. These videos would surely have been very helpful!

[@DJ-Equations]

Beautiful explanation. Straightforward and great use of examples

[@olivermiddleton1100]

you are a saviour my man.

[@arjunrai4937]

Great teaching skills much better than here in India in 2022. Thank you professor.

[@matthewoverton2206]

Very good, clear, concise, easy to follow video. Thank you very much, its made it clear for me!

[@pradeepkarna]

GR8 ONCE AGAIN,,,,GUESS WHAT ..MY SEMESTER EXAM IS TOMORROW AND I AM LEARNING FROM UR VIDEOS...

[@sanjeevkushwaha7614]

THANK YOU SIR You reduced a one hour lecture into 10 minutes.

[@CADable]

Very nice explanation Professor. This lecture is excellent for undergraduate students.

[@arianabedi]

I think there are only a few videos in your channel that I haven't seen. Right now I am WAY ahead of my mechanics of solids class :D thank you so much!

[@gromajor]

simple and clear explanation, I made some progress. thanks to you. :) have a great day.

[@ankitmahato7050]

Thanks a lot sir. Love from India ❤️🙏

[@purdueMET]

You're most welcome. It's great to hear from a viewer so far from where I live :-)

[@purdueMET]

You are most welcome. I'm glad the videos are helpful. I like to collect KZbin hits. If you like these videos, please help me spread the word :-) - RMF

[@shamdamdoobley4266]

dude I love you so much, my teacher for materials as sweet as she is, she is not good at explaining and I need your help

[@20hawkar10]

For once we have a mechanics of solids teacher that does not make the assumption that everything will come to us naturally and goes through everything in a slow but steady manner ensuring the viewer is taking in a good amount of information. Looking forward to future videos

[@suzelion6729]

this video explanations is clear, big up im like super dumb in strength of material but this video actually helps

[@purdueMET]

Thanks, I'm glad it helped :-)

[@CandidlySubtle]

Thanks! I'm studying for the FE exam and I have no experience in Mech. Eng. The study guide does not explain concepts at all! Though, in the book, they solved the problem using the Transformation of Stress Equations. I don't understand which angle to plug in for those equations. If you ever do a video on that, please let me know. Thanks!

[@hayaankhan3022]

sir u have been amazing al the time i wish our professors were qualified as u are :)

[@طالبعلم-ض7ذ]

Big like from Jordan

[@purdueMET]

Big thanks :-)

[@isagumus1]

So well explanation thanks !

[@jaffarkhan4487]

very helpfull video.... waititng for more videos

[@purdueMET]

Thanks very much. It's great to hear that these videos have been a help to you. RMF

[@ORion807]

Sir can you please explain me how the cross sectional area become bh devided by cosin theta

[@sadiasaeed9608]

sir can you please give me your whats app number. I need a help of person like you, in my thesis work. please its request. waiting for your positive response.

[@akshaysaraf6865]

u taught it soo well!! thank u sir!

[@sugarlaura22]

Thank you! Great Video. Explained perfectly.

[@christinaMaher3]

what about if i have a bending force perpendicular to the block i have and a torque acting on the block(torisinal force stress ) so how do i calculate these stresses on an inclined plane????????

[@prasanth-ky2pn]

thnq sir.... east or west u r the best....

[@Johnvincentvivek]

Sir thank you for making such videos i am a die hard fan of yours.

[@Joules120]

BEAUTIFUL!

[@DaniloSilva-wf2zp]

Thanks for such excelent explanation!

[@loi7827]

How did u find out the shear stress cross sectional area? 4:00

[@juliocesarambriztapia7641]

The cross sectional area is the same as the normal stress area. It is the component of the force what makes the difference

[@anuragdaksh4659]

Thank you so much sir .... This topic is cleared😊😊

[@kenule4032]

thank you so much for this video. Was wondering if you have a video showing an explanation of stresses on an inclined plane in a two-dimensional stress system.

[@BraveGamer2016]

Thank u so much I have an exam tomorrow And u helped me

[@ORion807]

Sir can you please explain why the cross sectional area become bh devided by cosin theta.....

[@dorairajvijayan8155]

Sir, how does a Normal Force produce a shearing effect on an inclined plane?

[@ibrahimraza394]

thank you very much you make it vert convenient for student like me

[@XanderMande]

Is it only applicable for forces who have the same magnitudes in both directions?

[@anoop150587]

nice learning videos .. particularly fr me bcoz i need to recall everthing learnt earlier

[@ranvijaysingh8671]

Awesome video,thanks a lot Prof 😁😁😁😁

[@psycho4570]

SO helpful 🙏🏼 thanks

[@adarshkorde7848]

Nice explanation,Thanks.

[@Hh12358]

Thank you professor.

[@amosmwangi1741]

Thanks for this lesson

[@ImranHossain-pt3ye]

you are great sir....

[@aliarind]

420th like! Great video, clarified the confusion for me. Especially love the correlation to the breaking of columns on an angle

[@king0vdarkness]

Dear Prof. RM French, Thank you for your videos they are very helpful! Please if possible could you do a cantilever beam connected to another wall, with pin joints at a section in the beam, or a similar problem and explain what happens to a beam if you(after solving it) add another moment. Thank you in advance. Best wishes!

[@margaritacarmona-carriedo7503]

EXCELENT VIDEO BTW!!!!! THANK YOU!!!!

[@awaisawan8846]

Very nice

[@hariprakash1992]

hello sir.. that was great.. could u make a video on understanding moments nd forces in a piping system

[@Ajay795]

thanks, helped me with my work

[@sebastianospina131]

Really helpful, thank you!!!

[@zVincoo]

you are a god sir, thank you so much

[@Some-one99]

Hello sir plz try to deliver in clear tone . Anyway it's so good and easily visualize able

[@GenaEnSamIAm]

Ten out of ten!!!! Thank you!!

[@fatimaezzahrahilal6699]

Sir why did u use both shear and normal stress here thank u

[@juliocesarambriztapia7641]

When you have an inclined plane, your axial force always have two components, therefore, unless it is 0 degrees both type of stresses are present in the element

[@weasleypotter7105]

Fn = Fcos0 Fs = Fsin0 Im usin trig but its not working can you explain it ?

[@romarssieverything9667]

that was great!!

[@warrensze321]

Thank you very much!!!

[@sagarkonnur2861]

Superbbbb.. ..

[@abdirahmanfiishey5774]

Thank you sir it is an amazing.

[@knowledgezone8748]

its too amazing thnax

[@VimalKumarVV]

thank you so much...

[@sanjaykumaryadav9723]

"please" also calculate stresses on an oblique section in a) two mutually perpendicular directions, b) subjected to simple shear stress c)subjected to direct stress in one plane and accompanied by a simple shear stress d)subjected to direct stress in two mutually perpendicular directions accompanied by a simple shear stress.

[@arielamzalak8562]

Awesome!!!

[@shenci9767]

thank you!

[@samflockhart6615]

Thank you !

[@cwl6814]

thank you so much!!!

[@UncleLimage]

I still don't understand why A= bh/cos(theta).

[@91099Babar]

Nice and thank you .

[@rupeshkumarpandey8727]

Why bh/cosθ = A/cosθ ?

[@purdueMET]

Because A=b*h. A_theta=A/cos(theta). Thanks for watching my videos. I hope they are helpful. I wish you the best in your studies :-)

[@kakbar10]

thanks again !

[@asarebediako1330]

Thank you sir

[@tamizhtamizh412]

Tq so much ❤

[@emeldahowell3705]

why is A=bh/cos theta

[@emeldahowell3705]

i get it now ...But how is A=AthetaCOStheta from geometry

[@satyenderkumar9332]

Thanks a lot sir.

[@husnainhyder6713]

nice 3d drawings

[@souravsingh3025]

Thanks.

[@rudhajassim9469]

thanks a lot

[@arianabedi]

Your very welcome :D

[@abcarin0O0]

good video

[@johnkupa8885]

Thanks Sir

[@patricko911]

thanks

[@Rohitme99]

thxxxxx sir

[@rmmalimet]

He's dreamy.

[@Rohitme99]

thx sir

[@aniketverma4736]

great

[@daysharing6061]

best

[@purdueMET]

Thanks :-)

[@GenaEnSamIAm]

Like Like Like!!!

[@hossamsaid3230]

First of all better use X- Axis and Y -Axis not N & S , for simplicity. Secondly if we consider such case , then it shall be Cos Degree on S and Sin Degree on N . Thanks

[@Bendaua1]

Man! You need better lightning.

[@purdueMET]

I sure did. What you can't see in the video is the light stands I had in my little office. I never really got it right, though. This video is pretty old. Check out the newest ones with the cool LED lights - way better. Thanks for watching :-)

[@rajulanjewar8516]

Level he nahi hai

[@ahmedkorim7658]

thank you sir

[@kaleabembezaalem1637]

thanks