Putnam Product in an Integral??? [MIT Integration Bee 2015]

[@filipeoliveira7001]

I’ve seen this little cascading double angle trick about 98 times by now

[@Silver-cu5up]

same lol

[@bingchilling8384]

Where do you find content like this? Looks kinda interesting.

[@filipeoliveira7001]

@ I found it doing some training for the hardest national university entrance exams in Brazil

[@filipeoliveira7001]

LMAO I DO MATH OLYMPIADS AND DID EXACTLY WHAT U SAID AT THE START

[@ACertainMan]

sin(n)~n for small n this is the fundamental theorem of engineering

[@PranavShewale-s1d]

Brother n is tending to inf not zero 😭😭 this is opposite of this

[@ACertainMan]

@PranavShewale-s1d n is the argument of sin, the dummy function inside sin is tending towards 0 as a whole

[@xa12anuranjan99]

Please take some good integral from indian engineering entrence exam jee advanced

[@b.afreeshooters146]

Can you solve this: integral(from 0 to pi) of x^2/(asin^2x+bcos^2x) wrt x pls?

[@Silver-cu5up]

i shall try XD

[@b.afreeshooters146]

Thank you 😊

[@Dharun-ge2fo]

Is it [-(pi)^3]/[4.root(ab)]

[@Dharun-ge2fo]

Bro did you get it, my answer is definitely wrong. Just checked by putting a=b

[@sinekavi]

Can you teach feynman rule of integration or has it been already covered?

[@Silver-cu5up]

it has already been cover

[@maxvangulik1988]

sin(x)=2sin(x/2)cos(x/2) =4sin(x/4)cos(x/4)cos(x/2) =... =2^n•sin(x/2^n)prod[k=1,n](cos(x/2^k) P(x)=lim[n->♾️](sin(x)csc(x/2^n)/(2^n)) u=2^-n P(x)=sin(x)lim[u->0](u/sin(ux)) P(x)=sin(x)/x•lim[u->0](sec(ux)) sec(0)=1 P(x)=sin(x)/x I=int[0,pi/4](sin(x))dx I=cos(0)-cos(pi/4) I=1-sqrt(1/2)

[@xa12anuranjan99]

Its too easy try some of good jee advanced integral problem

[@Ijkbeauty]

that good jee dick 😫😫😫💦💦💦💦

[@calculusworld9548]

Bro jee advance also took integral form these exams like putnam,mit, Berkeley tournament, others too also, no doubt this is easy

[@buzzybola]

Integral Insanity!!!