This lecture explains the PYQ on Uniqueness & Existence in ODE Short Cut Tricks CSIR NET 2011 to 2023
Пікірлер: 61
@debajitroy73005 ай бұрын
one of "The" best channel for net,Gate,JAM
@divyaraju-y4k3 ай бұрын
best channel i ever seen thank u sir! pls continue more
@mathbasicbox52493 ай бұрын
❤❤ what a approach
@shivamupd10 ай бұрын
It's very helpful video for us.
@mymathspartner60192 ай бұрын
Nice video sir, thankyou sir
@Ayoknyising10 ай бұрын
Sir you are alys great... ❤
@SADDAMHUSSAIN-mw3cv10 ай бұрын
Superb...
@yashodhas11744 ай бұрын
Thanks a lot sir, for this wonderful and informative class..😊
@anshikathakur70853 ай бұрын
Such a great explanation thanku so much sir means a lot God bless uh with lot of success and more❤
@alokkprajapati2 ай бұрын
Thanks Sir ❤
@professorragavan97833 ай бұрын
Thank you sir
@simisaharan87545 ай бұрын
Nice explanation sir.
@mathbasicbox524910 ай бұрын
Thanku so much sir ur great sir
@bakulmanna712310 ай бұрын
Thank you so much sir ❤❤
@shyamnagar891710 ай бұрын
Tnkyu sir ❤
@professorragavan97835 ай бұрын
Thank you sir!
@triptikumari902010 ай бұрын
Thank you 👍👍 Sir
@justiceforsidhumoosewala622510 ай бұрын
Nice explanation sir ❤
@ritutiwari46874 ай бұрын
Nice ❤
@Manish-uq5le9 ай бұрын
Thank you sir❤
@theexpress854 ай бұрын
No words 🙏🙏🙏🙏🙏🙏🙏
@easymathematics134110 ай бұрын
Ever greatest sir
@ronneysaini776310 ай бұрын
Thanks Sir❤❤❤😊
@simonrai73004 ай бұрын
Thank you Sir. ❤❤❤❤
@parveenkumar805010 ай бұрын
Thankyou sir
@RanjangamingYT747712 күн бұрын
1:3:25 check y=y0 e^x Then y0 non zero but y0 positive and negative ho sakta ha some time increase and some time decrease Therefore, not monotonic
@nishajyoti58968 ай бұрын
एक्सीलेंट 🎉
@mamtakeswani306610 ай бұрын
sir please make videos for solutions of ring theory and group theory
@subratpradhan35816 ай бұрын
Sir has no videos on Group and Ring theory, he has mastery in applied portions + Real Analysis+ CA + Linear Algebra
@SasankaKayal-b8s10 ай бұрын
Sir please making vidios for super tricks solution of algebra group theory and ring theory .....other vidio are very helpful ...so thank you so much sir ❤
@ronneysaini776310 ай бұрын
Nahi banayenge sir
@naveed63962 ай бұрын
At 7:01 what about the case when A0.
@Seema-jf9nr4 ай бұрын
Answer to last ques " blows up in finite time" is option B not D, sir plz recheck
@subratpradhan35816 ай бұрын
🙏🙏🙏 Thanks sir 50:16
@memebaaz400510 ай бұрын
Superhlb
@poojasingh72003 ай бұрын
As you told in this vdo e^x is unbounded function this is correct but e^z is bounded function ....how can you say We know that non constant entire function is unbounded So e^z is also unbounded function
@sibashishdas88067 ай бұрын
1:06:33 I think it's z=1/1+t
@someshnogia20096 ай бұрын
Yes you are right.
@Ekshivbhakat10 ай бұрын
Thank you so much sir for helping us 🙏🙏
@vindhyavijayan38264 ай бұрын
Sir in 1st question Since every polynomial is continuous atleast one solution will exists. How is possible for no solution?
@Kawaionnanoko87772 ай бұрын
Maybe the roots lie in the complex plane
@anshukumartiwari13614 ай бұрын
Result @7:03 is incorrect for A
@kshamashreek61263 ай бұрын
Last question... i think the right answer is option b
@meghavar10 ай бұрын
Sir WhatsApp group join ni ho pata iss link se
@shefalithakur45804 ай бұрын
In 1st question :- a polynomial and its derivative is always continuous and bdd so it satisfies Lipschitz condition Hence there is a unique solution in an interval containing 0 (d) is true
@Zeelkhokhariya3 ай бұрын
Option D is correct😊..!!
@poojasingh72003 ай бұрын
@@Zeelkhokhariyayeah D is also correct bcz It's taking about A solution That is one so
@sibasankarbarada41697 ай бұрын
But sir e^z is unbounded because it is entire
@naveenpondara49037 ай бұрын
No bro e^z is bounded
@VlogswithJay5 ай бұрын
My dear brother who told you that e^z is bounded its unbounded
@naveenpondara49035 ай бұрын
@@VlogswithJay Haa yes...
@VlogswithJay5 ай бұрын
Bounded or unbounded ?
@naveenpondara49035 ай бұрын
@@VlogswithJay if there is no condition for real and imaginary parts then it is unbounded