PYQs on CONTINUITY| CSIR NET 2011 to 2023

PYQs on CONTINUITY| CSIR NET 2011 to 2023 | Short Cut Tricks

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Күн бұрын

Пікірлер: 88

@sheemanitinsan7235 5 ай бұрын

I went to many institutions and invested a lot of money 💵 but no one ☝️ taught like you …..and you taught so very well 👌 without any fees thank you so much dear sir ❤

@yogendravishwakarma5592 4 ай бұрын

Forget wrong things only take right and good things.

@sheemanitinsan7235 4 ай бұрын

@@yogendravishwakarma5592yes ♥️

@aakashbhuse3170 4 ай бұрын

Because he is recognised by the top Indian scientist in the current time and recently included in the top 2% scientists in the world !!

@sheemanitinsan7235 4 ай бұрын

@@aakashbhuse3170 absolutely 💯 right brother

@shubhamkumartiwari2379 5 ай бұрын

@Dr.Harish garg , at 1:16:37 csir net June 2019 . Sir In this problem options (c) and (d) are also correct.

@supriyarani2645 4 ай бұрын

Aisa content aaj tak nhi mila you tube pe... difficult topic hai isko banane ke liye bhot thankyou sir... kindly make topicwise aptitude pyq

@himanisingh3784 4 ай бұрын

Thankuuu so much sir.your teaching style is excellent.❤❤❤❤❤❤❤kash ap hmee phle

@steel679 5 ай бұрын

very helpful sir `thankyou so much sir .

@pusplatasahu5738 5 ай бұрын

Superb session.....❤

@goutamjana1292 5 ай бұрын

Very helpful sir . Please upload more videos.

@BalajiPadhy-l8f 5 ай бұрын

Really, you are teaching Real analysis, sir; thank you so much for sharing such videos.

@shaswata07 5 ай бұрын

Very helpful ❤

@Achukutty25 5 ай бұрын

My prayers and wishes are always for you sir 🙏

@rashmimalik9769 5 ай бұрын

Bahut jyada helpful h sir ji

@rnithyaraj9498 5 ай бұрын

Tku sir Your videos very use full sir

@ratanprajapatirp3529 Ай бұрын

Thanks you sir aap great ho

@imkunalkapoor 5 ай бұрын

Sir this is very helpful please upload next 2 lecture very soon please your trick very helpful in exam

@yogendravishwakarma5592 4 ай бұрын

Very nice lecture sir....

@riyagoel8939 4 ай бұрын

at 35:40 how did we have discarded the unbounded option(d) .Please provide a valid justification for the same

@dipeshvishwakarma3511 4 ай бұрын

1/1+e^x is cts, one one and bdd.

@pulkitgaming5401 Ай бұрын

Take tan inverse x as example

@charitylyngdoh8912 Ай бұрын

Thanks alot Sir 🙏

@mathematicslovers2888 5 ай бұрын

Very nice explanation, thanks sir

@rajkumarmanna3855 5 ай бұрын

Thank you so much sir ❤

@vandnanamdev4443 4 ай бұрын

Thank you for your efforts sir 🙏

@positivethoughts6419 5 ай бұрын

Really you are great sir ❤

@ankitadangi1655 5 ай бұрын

Very helpful 🎉🎉🎉

@anitakaushik-be8mo 4 ай бұрын

@ dr harishgarg 41:00...a option kaise shi ho gya ...f(a ) bdd to a ko bdd kaise bol skte h ..inverse image thode hi bdd hoti h

@itsyourdev5143 5 ай бұрын

Thank you sir 🙏

@SanchitMehra-mf3rh 5 ай бұрын

Thanks again ❤

@steel679 5 ай бұрын

solid content sir

@siddhusiddharthan161 5 ай бұрын

Thank you❤ sir

@ranachanda2839 5 ай бұрын

Thanks sir...❤

@SaifAbbas-c9p Ай бұрын

thanks sir

@intelligencecorner609 5 ай бұрын

You are genius sir

@preetyahlawat2464 Ай бұрын

How to take f(x)=1, it is not one one ..at 35:01

@ThoihenbaKeishamMeetei 5 ай бұрын

love you sir❤❤❤

@ChandanKumar-dn9lz 5 ай бұрын

Thanks a lot sir jee .

@ASHISHKumar-zu7xo 5 ай бұрын

Please explain in bilingual. Your lecture is very useful for me. Thanks sir

@RanjangamingYT7477 20 сағат бұрын

34:24 you have not taking example f(x)=1 because one one function bola ha😢

@PIMMATHS 5 ай бұрын

Thanks sir ji

@professorragavan9783 5 ай бұрын

Thank you sir

@riyagoel8939 4 ай бұрын

37:10 how can we consider A=R in the (4) option sinceR is not compact

@newsteplaiddown9481 4 ай бұрын

A={1} it is compact , f^-1({1})=R it is not compact

@ikmathacademy5747 20 күн бұрын

Sir ode or pde bhi topicwise krwa do

@prabavathig462 5 ай бұрын

Sir... Please... Which software you are using for screen recording this video ?

@Radharanilove-y5d 4 ай бұрын

Sir please upload the vedios of linear algebra ... inner product spaces...and orthogonal...invariant subspcaes...

@DrHarishGarg 4 ай бұрын

Linear algebra, inner product space etc already uploaded.. Explore at my youtube channel.

@Radharanilove-y5d 4 ай бұрын

@@DrHarishGarg ok sir thanku

@anusuiya. 4 ай бұрын

Thank you sir🙏 Sir at 43:04 image of close interval under countinous function is always closed. and range of tan ^-1x is -pi/2 to pi/2 . So how option 1 is incorrect

@Siyagupta52 4 ай бұрын

Take f(x)=e^x , A=R then f(A)=(0,oo) which is not closed

@shefalithakur4580 4 ай бұрын

@@Siyagupta52 ha to in this case you take A=R which is not closed But continuous function always map closed to closed Compact to compact Cauchy to cauchy So option 1 is true here

@Siyagupta52 4 ай бұрын

@@shefalithakur4580continuous function maps compact to compact Closed to closed is not true . As take the same example of e^x

@shefalithakur4580 4 ай бұрын

@@Siyagupta52 I got it dear thanks Continuous not necessarily map closed to closed

@sahanar5228 4 ай бұрын

Continuity maps Closed inteval to closed interval...but not closed set to closed ..ie ex R

@nerdhayafs62525 3 ай бұрын

Please complete this topic with uniform continuity and all

@DrHarishGarg 3 ай бұрын

Already uploaded.... See at my youtube channel.

@BEGINNERMATHS 5 ай бұрын

Thankyou sir

@Siyagupta52 4 ай бұрын

@50:14 option (d) is incorrect as compact set will map to compact set. Is this correct or not? Can someone confirm?

@anamfatima3524 5 ай бұрын

Please upload the next lecture,

@saikatmalla7390 5 ай бұрын

sir last request..... please upload a video on pyqs of ring theory.... 🙏🙏

@naveenpondara4903 3 ай бұрын

at 16:11 how opt d is correct?

@shreya2262 5 ай бұрын

Thankyou

@SunitaPooran-bi8gj 5 ай бұрын

37:24 can anyone tell me..why sir had not taken compact subset A...why he has taken A=R

@Dearbhanusir 5 ай бұрын

Yes A can't take R because A is compact

@vikasmehta8027 5 ай бұрын

Thanku sir❤

@professorragavan9783 5 ай бұрын

8:17 I have a doubt in selection of option c. We neglect [-1,1] because 0 belongs to it. Similarly option C also have 0. Then why we take as a correct answer?.... Please someone explain me 😢

@DrHarishGarg 5 ай бұрын

The given option is set not interval because 1/n, n€N given .. So we need to find the function corresponding to this set and then check it continuity.... For example, for a and b option, function is given , but for c and d , function is not defined.... That's why, first defined the function and then check... Hope it help you.

@professorragavan9783 5 ай бұрын

Yes sir thank you ❤

@RanjangamingYT7477 20 сағат бұрын

31:37 b option me continuous booa ha but greatest integer function always discontinuous at countable numbe of points how b option correct 😂